Mr M's OCR (not OCR MEI) Core 2 Answers May 2016 Watch

mrbeady9
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#181
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#181
(Original post by ComputeiT)
Using previous part:
x^2/(x+4) = 3^2 = 9
x^2=9(x+4)
x^2=9x+36
x^2-9x-36=0
(x-12)(x+3)=0
x=12 or -3

But log base 3 (-3) is undefined.
Therefore x = 12
I originally thought this and put down my answer as x = 12. But then I realised that 2log3(-3) is the same as log3(9) [(-3)^2 = 9]. So isn't -3 allowed? If you do this on your calculator you get the correct answer. I'm not saying you're wrong I just don't understand why -3 isn't allowed.
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Jitesh
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#182
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#182
(Original post by mrbeady9)
I originally thought this and put down my answer as x = 12. But then I realised that 2log3(-3) is the same as log3(9) [(-3)^2 = 9]. So isn't -3 allowed? If you do this on your calculator you get the correct answer. I'm not saying you're wrong I just don't understand why -3 isn't allowed.
Sketch a graph of log3(X)
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ArranJones
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#183
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(Original post by Mr M)
\displaystyle \sum_{n=1}^{\infty} W_n = 1200

\displaystyle \frac{N}{2}(2a+(N-1)d)>1200

Let a = 5 and d = 1.5 and solve.
I used both as the sum of the geometric series due to the previous question, will I get any marks do you think? I used the correct method throughout but didn't get a quadratic equation. I think I've averaged out at about 55 marks, should that be at least a C, I did want at least a B though.

Thank you for your time.
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Mr M
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#184
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#184
(Original post by ArranJones)
I used both as the sum of the geometric series due to the previous question, will I get any marks do you think? I used the correct method throughout but didn't get a quadratic equation. I think I've averaged out at about 55 marks, should that be at least a C, I did want at least a B though.

Thank you for your time.
If you found the sum to infinity was 1200, you'll get 1 mark. I doubt whether you'll get more credit as you completely misunderstood what you were expected to do.
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ArranJones
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#185
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(Original post by Mr M)
If you found the sum to infinity was 1200, you'll get 1 mark. I doubt whether you'll get more credit as you completely misunderstood what you were expected to do.
Okay then, thank you. I do understand the question. Just didn't do it properly in the exam, worst feeling ever!
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Mr M
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#186
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(Original post by ArranJones)
Okay then, thank you. I do understand the question. Just didn't do it properly in the exam, worst feeling ever!
It's one question out of 6 modules. It won't prevent you from getting the grade you need in the end.
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Project22
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#187
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#187
What was the question for 8iv?
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Ozil5
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#188
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#188
if there a stats thread?
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