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    (Original post by samh2301)
    Any predictions for grade boundaries?
    57/58
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    (Original post by metasysta)
    Let's do another community MS. Please press the button to request permission to contribute.
    https://docs.google.com/document/d/1...it?usp=sharing
    does anyone remember roughly the marks for each part?
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    were we supposed to compare the 2 different graphs for spearmans rank?
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    (Original post by samh2301)
    Any predictions for grade boundaries?
    Probably around the same as last year, maybe slightly lower as this paper seemed a little harder.
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    (Original post by student199919)
    does anyone remember roughly the marks for each part?
    Question numbers and questions would be useful too
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    0.0864 for very last question
    (Original post by metasysta)
    Let's do another community MS. Please press the button to request permission to contribute.
    https://docs.google.com/document/d/1...it?usp=sharing
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    (Original post by LukeBlizard)
    0.0864 for very last question
    I got 1.37
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    (Original post by sen99)
    wouldn't it be 12 bc it said less than 140
    This is probably wrong, but I got that Q1 was (something like) the 13.5th value, meaning that there are 13 values below the lower quartile
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    It was 12 as 13 was the lower quartile at 140 and it wanted values lower than 140
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    (Original post by torilee)
    This is probably wrong, but I got that Q1 was (something like) the 13.5th value, meaning that there are 13 values below the lower quartile
    I did too
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    (Original post by Btec certified)
    I got 1.37
    Lol how can a probability be more than one?
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    (Original post by Ozil5)
    Haha no worries, you had to use their position on the x and y axis as ranks, so they were 12345 and 12354. I think the final answer was 0.9
    I cant believe how simple it actually was ((. well there goes 5 marks. I used the wrong formula for variance but for the next part of the question i used the right method to get em2. Do you think I'll get any marks?
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    How's the BARBARA question 4/35. You already take in to account the repetitions in the first part, so you just have 1/210 as the probability.
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    (Original post by Vanilla Poison)
    How's the BARBARA question 4/35. You already take in to account the repetitions in the first part, so you just have 1/210 as the probability.
    this.
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    Mark Scheme: Kind of.
    1)
    Spearman (Given)= -1
    Spearmen (Calculated)= 0.9
    2)
    Last Q)
    P(X=3) = 0.128
    P(9<X<20) = P(X≤19)-P(X≤9) = 0.120 (3sf)
    3)
    Marie Wins:
    (0.2X0.2X0.7)+(0.2X0.2X0.3) =0.04
    Nadine Wins:0.0864
    4)
    Perm/com
    A) 210
    B)1/210
    C)1/70
    5)
    Group of 12 into 3: 27,720
    6)
    PMCC: 0.924 Therefore more then 0.92
    7) Mean N: 6.5
    Mean Z: About 20.9
    Total output: 20.9x12= 251
    8) E(X)=2.7
    VAR (X)= Forgot it but it was something obvious
    9)
    Coded Data
    Mean: 146.5
    Var= 12.8
    In the range: 13 apples
    Outliers: None (Marks for calculating both and saying no outliers)
    Sum of M^2: 11107676.1 )Something like that, forgot it, because it's a long ****ing long number)
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    Can someone explain to me why there aren't any outliers? What I did was find the iqr (15?) then multiply that by 1.5 then add it to the uq which was 155? So then I got that 177.5-180 were outliers. Is that wrong and why?
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    What do we think that 69/72 would be approximately UMS wise?
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    (Original post by Buymoria)
    What do we think that 69/72 would be approximately UMS wise?
    Probably the full 100 ums
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    The highest Value was 176 on the box and whisker plot, so there couldn't be any outliers.
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    Guys would I lose marks for using 147 and 21.8 to find the sum of msquared instead of 146.5 and 21.75?
 
 
 
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