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    For the magnesium steam observations, I put effervescence and white solid ppt but I don't think I get any marks bc it's not in liquid
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    Could you write about a squeaky pop with hydrogen for an observation? :/
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    (Original post by mgill17)
    What was the Termination step for the first Free Radical Substitution? You had to make something specific (I think it was C2H2Cl4??)
    I think I put 2 *CHCl2 --> CHCl2CHCl2, its empirical formula had to be C2H2Cl4


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    (Original post by r p)
    what did ppl out for the 2 environmental and 1 economic advantage of using low grade ore?? I put:
    Environmental: no SO2 released - no acid rain
    Less energy required, less fossil fuels burnt
    Economic: scrap iron is cheap

    Do you think that's ok?
    yeah i put the same as that for the first two but i think i put it costs a lot to provide energy to roast an ore
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    (Original post by Sam Webb)
    Did you have to make it negative because it was exothermic?
    It was asking about bond enthalpy, so the value of c-c would have been positive
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    Is it white solid or white ppt
    It can't be ppt can it when it wasn't in solution?
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    (Original post by WhoDaresWins)
    1 mark for the white ppt, but can't believe this, found it so nice and then these silly mistakes just accumulated!
    Grade boundaries will be sky high too.
    Yeah, like it's never outright getting answers wrong, it's just forgetting little things or not using common sense then being like "Ahhh yeah I see that now" afterwards:/
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    (Original post by RME11)
    Great paper - The only real curveball was the method of rate of hydrolysis questions which was a HSW question.

    Think I've got about 95ish there, only time will tell though!
    I said use a piece of card with a black cross on underneath the beakers with the reactions going on and then time how long it takes before you can't see the black cross
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    (Original post by WhoDaresWins)
    Oh fk thought it was elimination damn ittttt!!!
    Also thought the didn't we have to name the alcohols?
    Hi no

    It was dehydration - which is same as elimination but re agent here is conc h2so4


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    (Original post by lahigueraxxx)
    What did people put for the role of H2SO4 in the reaction with sodium iodide?? I put oxidising agent, but it was a really badly worded question..
    I think i put oxidising agent aswell
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    (Original post by Louisss)
    I think I put 2 *CHCl2 --> CHCl2CHCl2, its empirical formula had to be C2H2Cl4


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    I think/hope I got something with that empirical formula but it threw me off, it just seemed odd compared to the previous FRS questions?
    Thanks!
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    (Original post by mgill17)
    I think/hope I got something with that empirical formula but it threw me off, it just seemed odd compared to the previous FRS questions?
    Thanks!
    Yeah I agree, I think it's because the equation that we wrote at the beginning wasn't the one used for the frs mechanism


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    (Original post by mbh16)
    I said use a piece of card with a black cross on underneath the beakers with the reactions going on and then time how long it takes before you can't see the black cross
    I just said measure time taken for ppt to be formed - use equal volumes/concs, repeat test a few times to get a mean value etc. Probably dropped a couple of marks, but I can live with that.
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    (Original post by Seclusion)
    Magnesium produces the Bright white flame, not sure if they would credit white ppt, the second reason has to be about hydrogen, which is the pop.
    yeah but doesn't it produce MgO which is a white solid?
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    (Original post by mgill17)
    What was the Termination step for the first Free Radical Substitution? You had to make something specific (I think it was C2H2Cl4??)
    Propagation step gave CHCl2• (CH2Cl2 + Cl• ---> CHCl2• + HCl), so termination step to give C2H2Cl4 was CHCl2• + CHCl2• ---> C2H2Cl4
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    (Original post by RME11)
    I just said measure time taken for ppt to be formed - use equal volumes/concs, repeat test a few times to get a mean value etc. Probably dropped a couple of marks, but I can live with that.
    haha i completely forgot to say use the same concs/volumes but i said put in the reactants at the same time
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    The distillation Q

    - one was aldehyde - one was COOH

    COOH has hydrogen bonds which is stronger than vDw in aldehyde - it will allow vdw I'm sure

    - infrared Q on why the spectra shows it's not that product
    - u had to specify missing c=o bond and missing O-H bond

    Mechanism - propene with h2so4 - electrophillic addition with a secondary carbocation formed

    Explain why propan-2-ol is the major product (7)

    Reaction proceeds through carbocations - so secondary is more stable than tertiary

    State conditions for the two reactions and mechanism and state the role of oh- in both reactions 8)

    Elimination - base
    NS- nucleophillic

    Elimination - NS
    Re agent - KOH
    Conditions - hot ethanolic solvent
    NS - reagent - Naoh
    Condition - water as solvent - warm aquoes

    Mechanism was elimination


    These 2 Q were the big 7 8 markers




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    (Original post by iiPablo)
    Propagation step gave CHCl2• (CH2Cl2 + Cl• ---> CHCl2• + HCl), so termination step to give C2H2Cl4 was CHCl2• + CHCl2• ---> C2H2Cl4
    I definitely got that propagation step, but I can't remember for the life of me if I put that termination....I hope I did
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    (Original post by ahsan_ijaz)
    The distillation Q

    - one was aldehyde - one was COOH

    COOH has hydrogen bonds which is stronger than vDw in aldehyde - it will allow vdw I'm sure

    - infrared Q on why the spectra shows it's not that product
    - u had to specify missing c=o bond and missing O-H bond

    Mechanism - propene with h2so4 - electrophillic addition with a secondary carbocation formed

    Explain why propan-2-ol is the major product (7)

    Reaction proceeds through carbocations - so secondary is more stable than tertiary

    State conditions for the two reactions and mechanism and state the role of oh- in both reactions 8)

    Elimination - base
    NS- nucleophillic

    Elimination - NS
    Re agent - KOH
    Conditions - hot ethanolic solvent
    NS - reagent - Naoh
    Condition - water as solvent - warm aquoes

    Mechanism was elimination


    These 2 Q were the big 7 8 markers




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    is that for the one where you had to say what the functional group was of T and S was?
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    Btw the ms - like some Qs will have more than one answers - eg for copper one you can write less energy requirement / the fact it's scrap iron it's cheap and plenty more answers


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