# Edexcel A2 C3 Mathematics 12th June 2015Watch

This discussion is closed.
3 years ago
#2101
(Original post by anonwinner)
Just woke up... Anyone else here?
yep
0
3 years ago
#2102
(Original post by Hudl)
Got a question from that june 13 paper, not gone to bed yet as trying to understand where I flawed. There are a few algebraic errors due to silly mistakes. Sill managed an A* but only got 58.

I'm confused as to why you found the maximum value for the denominator, if we want the minimum value for V shouldnt the value on the denominator be as small as possible so -25 in other words, that way you get 21/-25 which is smaller than 21/25?

for the velocity question part b q8 June 2013

EDIT

Also within the range we're given 0 < X < 150 we cant have cosX as 1
Velocity can never be negative and the RCos(x-a) graph is shifted to the right so you can get 1

Posted from TSR Mobile
0
3 years ago
#2103
Is there any Jan 2015 c3 IAL paper?
0
3 years ago
#2104
(Original post by Freddy-Francis)
Is there any Jan 2015 c3 IAL paper?
yeah but it is a mix of c3 and c4
0
3 years ago
#2105
(Original post by Maham88)
yeah but it is a mix of c3 and c4
i was thinking why integration was there
0
3 years ago
#2106
i try get my head around it but i still dont understand part b, how would you do it using part a can some give me a worked solution in detail please

0
3 years ago
#2107
(Original post by studentwiz)
i try get my head around it but i still dont understand part b, how would you do it using part a can some give me a worked solution in detail please

what paper is this ?
0
3 years ago
#2108
(Original post by studentwiz)
i try get my head around it but i still dont understand part b, how would you do it using part a can some give me a worked solution in detail please

b)

let a = (x+ pie/2)
b = (x+pie/6)

so.

2cos (A) = secB
2cosA = 1/cosB Multiply by cos B
2cosAcosB = 1
now u get the form as above.. so use that layout from part a.

At part A it says 2cosAcosB = cos(A+B) + cos(a-b)

sub in a and b
so cos(x+pie/2 + x + pie/6) + cos(x+pie/2 - (x + pie/6)) = 1
cos(2x + 2/3pie) + cos(1/3pie) = 1

so cos(2x +2/3pie) = 1/2
is that right?

x = pie/2, 5/6pie

and solve, i think
0
3 years ago
#2109
(Original post by Maham88)
what paper is this ?
solomon paper G
0
3 years ago
#2110
(Original post by studentwiz)
solomon paper G
Dude i solved it ^^ at least reply
0
3 years ago
#2111
(Original post by Freddy-Francis)
b)

let a = (x+ pie/2)
b = (x+pie/6)

so.

2cos (A) = secB
2cosA = 1/cosB Multiply by cos B
2cosAcosB = 1
now u get the form as above.. so use that layout from part a.

At part A it says 2cosAcosB = cos(A+B) + cos(a-b)

sub in a and b
so cos(x+pie/2 + x + pie/6) + cos(x+pie/2 - x + pie/6) = 1
cos(2x + 2/3pie) + cos(1/3pie) = 1

so cos(2x +2/3pie) = 1/2
is that right?

x = pie/2, 5/6pie

and solve, i think
nice thank you!
0
3 years ago
#2112
(Original post by Freddy-Francis)
Dude i solved it ^^ at least reply
1
3 years ago
#2113
(Original post by studentwiz)
nice thank you!
No Prob
0
3 years ago
#2114
Getting close now, could someone just send a list of the all the formulas that we need to learn that aren't in the formula book please?
0
3 years ago
#2115
(Original post by Maths,man)
Getting close now, could someone just send a list of the all the formulas that we need to learn that aren't in the formula book please?
http://www.slideshare.net/anicholls1...ything-edexcel
0
3 years ago
#2116
Anyone ready for the exam!!!
0
3 years ago
#2117
what do you have to say for the sign change iteration proof question to get full marks
0
3 years ago
#2118
(Original post by studentwiz)
what do you have to say for the sign change iteration proof question to get full marks
since there is a change in sign there is a root between the intervals
1
3 years ago
#2119
Anyone realise that the qoutient rule is given in the formula booklet?
0
3 years ago
#2120
(Original post by Sants)
Anyone realise that the qoutient rule is given in the formula booklet?
But wastes time looking back :P

Do u really need to check
0
X
new posts
Latest
My Feed

### Oops, nobody has postedin the last few hours.

Why not re-start the conversation?

see more

### See more of what you like onThe Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

### University open days

• Cranfield University
Cranfield Forensic MSc Programme Open Day Postgraduate
Thu, 25 Apr '19
• University of the Arts London
Open day: MA Footwear and MA Fashion Artefact Postgraduate
Thu, 25 Apr '19
• Cardiff Metropolitan University
Undergraduate Open Day - Llandaff Campus Undergraduate
Sat, 27 Apr '19

### Poll

Join the discussion

#### Have you registered to vote?

Yes! (213)
39.23%
No - but I will (38)
7%
No - I don't want to (36)
6.63%
No - I can't vote (<18, not in UK, etc) (256)
47.15%

View All
Latest
My Feed

### Oops, nobody has postedin the last few hours.

Why not re-start the conversation?

### See more of what you like onThe Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.