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    (Original post by ad4m)
    I think for the last question, you had to round it to 3 significant figures. I got 80.38
    That's four significant figures, but they don't usually deduct marks for this.[/QUOTE]

    It is 80.4 to 3 significant figures
    If a zero is found between significant digits, it is significant.
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    The formula was 1/2 abSinC and therefore you had to find another angle first as you used c as 8 when that was the line for b not c
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    All my maths teachers say 3.8 for the trial and improvement. We are debating whether or not the perimeter question needed the unit of measurement.
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    How many marks are required for an overall C
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    (Original post by thomas-cowley)
    Fot the last question did people work out the top, bottom right or bottom left angle?
    What you needed to do was rearrange area of curled formula to find the bottom left angle in between the lengths 7 and 8 and I remember it to be 40.000

    Then that allows you to use the cosine rule in order fine the opposite length

    Finally, you can use all the information to the asked angle using the Sine rule which and I got 80.3
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    (Original post by Purpleunicorn197)
    Hi I'm going to start and unofficial markscheme so add your answers
    Reps are not necessary but would be appreciated

    Sorry for the hold up with the questions
    1. Order numbers correctly and include a key (Stem and leaf) (3 marks)
    b) 9/20=
    0.45 (2 marks)
    2a. 5a*2b*3c =
    30abc (1 mark)
    b. Factorise fully 3y +6 =
    3(y+2) (1 mark)
    c. Expand x(x-3)=
    x^2-3x (1 mark)
    3. Perimeter of a rectangle with side lengths x and x+4 is 45
    x+x+x+4+x+4= 4x+8
    4x+8=45
    4x=37
    x=9.25 (3 marks)
    4. Smallest packet was best value for money because it was cheapest per bag of crisps (4 marks)
    5. 4 times as many red than green: There were 0.4 blue and 0.15 yellow.
    0.4+0.15+4x+x=1
    0.55+5x=1
    5x=0.45
    x=0.09
    4x=0.36
    Green- 0.09 Red- 0.36 (3 marks)
    6a. Body mass index= m/h^2
    Mass= 50kg
    Height= 1.57m
    20.3 (2 marks)
    b. What mass will result in a BMI of 21 with a height of 1.8m
    68.04kg (2 marks)
    c. Tom's skis can be a maximum of 145% of his height what is their max. tenght (Tom is 1.8m)
    2.61m (3 marks)
    7. Trial and error. x^3-5x=34 with a number between 3 and 4
    x^3-5x=34
    3.7 gives you 32.153 which is too small
    3.8 gives you 35.872 which is too big
    So you go in the middle at 3.75 and if it is too big then its you go with the smaller option and viceversa so 3.75 gives you 33.984375 which is too small so you go for the larger option of 3.8
    3.8 (4 marks)
    8a. Photographs with of width 720 pixels and a height of 540 pixels what is the ratio width:height in its simplest form?
    4:3 (2 marks)
    b. The person now wants the ratio to be 2:3, without changing the width of the picture, what is the new height?
    480 pixels (2 marks)
    9.x= 124 degrees (4 marks)
    10. Mean of grouper freq. table 396(freq.*midpoint total)/50 (freq. total)
    7.92 (4 marks)
    11. Colin's drive to work
    £42.29 (5 marks)
    12. The middle angle of a pentagon
    x=144 degrees (4 marks)
    13.
    -2 -1 0 1 2
    -1 3 1 -1 3 (2 marks)
    Draw curve (2 marks)
    14. steel bar with length of 120cm and a cross sectional area of 72cm^2 and a density of 8g/cm^3. A trolley can carry 250kg so how many bars can it carry?
    3 Bars (5 marks)
    15. Pauls buys a car worth 15,000 pounds and the value depreciates by 23% in the first year and 18% after the first year. Has Paul's car lost half of its value in theree years?
    No, because 7766.22 was greater than 7500 pounds (4 marks)
    16. Median on cumulative freq. graph
    128g (1 mark)
    b. Use graph to find interquartile range
    11g (2 marks)
    17. Triangle with sides 15.6cm (opp), 18(hyp). Angle is split into 2, 30 degrees and x degrees. the whole angle is 60.1 so
    x=30.1 (4 marks)
    18. 10a^5b^4 (2 marks)
    b. y= 5p^2-x (3 marks)
    19. 51 out of the 234 were maths in yr 12 so 50 * 51/234
    11 males (2 marks)
    20. 3x^2 + 6x -2
    x= 0.29 or x= -2.29 (3 marks)
    21. v=14 to 2 s.f u= 8.7 to 2 s.f
    What is the upper bound of I when I= 5(v-u)
    29.25 (3 marks)
    22. Histogram -F.d- 1.6, 3.2, 2.4, 1.8, 0.3 (3 marks)
    23. Perimeter of the shaded part of the sector.
    Measurements were 4+4+5/2pi+25/6pi
    28.9 (3 marks)
    24a. Simplify (3-x)/3x^2-5x-12
    -1/3x+4 (2 marks)
    b. Write are one fraction in its simplest for (x/x-1)- (x/x+1)
    2x/(x+1)(x-1) (3 marks)
    25. Triangle with side lengths 7 and 8 finding the top angle using 1/2absinC , sine rule and cosine rule
    80.4 (6 marks)
    Question 24.a) I believe the answer is -(1)/(3x+4)
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    (Original post by flowerglobe)
    What would 130 be??
    possibly an A
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    I got 63 in the first paper and 74-75 in the second, total is 138-139/200. what grade is that.

    Thanks
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    For 24b would it matter if i expanded the denominator? To me x^2-1 looks simpler than the factorised version.
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    (Original post by DrPeter)
    There is more than one way to get the answer but Pythagoras isn't one of them (can only be used with right-angled triangles)

    For the last question I can't remember exactly what I did at the start but I split the triangle into two which gave me two right angled triangles. I was then able to use Pythagoras to find out the missing lengths then the cosine rule to find out the angle for each triangle which I added together at the end. Would this still not be relevant?
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    (Original post by Moonbunny)
    For 24b would it matter if i expanded the denominator? To me x^2-1 looks simpler than the factorised version.
    I think that should be fine - i did that too and the mark schemes usually give an answer and say "or equivalent". The expansion is the exact same value, just different form so i think it should definitely be ok!
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    By last years standards, that would be a
    B, but very close to an A (A is 145)
    Posted from TSR Mobile
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    HELP!!
    So you know the last question I put the formula for the area of a triangle which is 1/2ab sinC or something like that and it was six marks!! Do you think I would get a mark for the formula or not?


    Posted from TSR Mobile
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    What is 75-80
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    Can the stratified be 10 or 11 i was taught you cant round people up
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    If iwrote the right answer but then i crossed it out and put something different will it still get marked


    Posted from TSR Mobile
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    I think a will be 136


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    (Original post by gigge)
    Can the stratified be 10 or 11 i was taught you cant round people up
    That should be correct as well, as I think that the mark scheme is not as strict with these sort of questions as the correct answer would have to be a number where the stratified samples of all of the samples added up should be the sample size.
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    Hey guys so I got around 132-135 (depending on how lenient the marker will be) what grade do you think that will be this year..?
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    Does an A in GCSE Maths look good? I could've got an A* but I'm really kicking myself because of careless mistakes. Is it bad to have an A because it's a core subject? Thanks
 
 
 
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