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Aqa chem 4/ chem 5 june 2016 thread

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Original post by Anam

[Al(h20)6]2+ + OH- ===> [Al(OH)4]- + 3h20

is this equation right for excess oh- being added to aluminium

[Al(H2O)6]3+ + 4OH- -> Al(OH)4- + 6H2O

Original post by Anam

[Al(h20)6]2+ + OH- ===> [Al(OH)4]- + 3h20

is this equation right for excess oh- being added to aluminium

[Al(H2O)]3+ +4OH- ------> [Al(H2O)2(OH)4]- + 4H2O

Original post by Anam

[Al(h20)6]2+ + OH- ===> [Al(OH)4]- + 3h20

is this equation right for excess oh- being added to aluminium

that doesnt look right to me because youve lost 3 hydrogens from the complex to form 3 water but there is 4OH with your aliminium

Original post by Boundless_x

Can someone tell me bond angles for square planar please?

90

Original post by Anam

[Al(h20)6]2+ + OH- ===> [Al(OH)4]- + 3h20

is this equation right for excess oh- being added to aluminium

I thought it was [Al(h20)6]3+ + 6OH- [Al(OH)6]3- +6h20

Original post by handiepie

I thought it was [Al(h20)6]3+ + 6OH- [Al(OH)6]3- +6h20

no thats for hexa-aqua Cr3+ in excess oh

Whats the equation for cobalt/ copper with excess oh-?

Original post by Jmedi

They will tell you if it's in alkaline solution

Thanks!

Help in my notes, the equation for [Cr(h20)6]3+ with EXCESS OH is [Cr(h20)3(oh)3] + 3OH- --> [Cr(oh)6]3- + 3h2o but this is the mark scheme help??! It's the same with excess nh3 too!!

Original post by Anam

[Al(h20)6]2+ + OH- ===> [Al(OH)4]- + 3h20

is this equation right for excess oh- being added to aluminium

Al(H₂O)₃(OH)₃+ OH^-===> [Al(OH)₄]^-+ 3H₂O
or
[Al(H₂O)₆]³⁺+ 4OH^-===> [Al(OH)₄]^-+ 6H₂O

(edited 7 years ago)

Original post by Chembio123

Help in my notes, the equation for [Cr(h20)6]3+ with EXCESS OH is [Cr(h20)3(oh)3] + 3OH- --> [Cr(oh)6]3- + 3h2o but this is the mark scheme help??! It's the same with excess nh3 too!!

Can i see the question and I can see what's up

Hi,
For the rechargeable & and non rechargeable cells do we need to learn the species involved in each or we would be given, if a question is asked on it ?

Original post by Super199

Whats the equation for cobalt/ copper with excess oh-?

i know u get cu(oh)2 and co(oh)2 which are both blue precipitates.

only cobalt can be further oxidised at this point by air or h2o2 to give cr(h20)3(oh)3 which is brown ppte

Original post by Chembio123

Help in my notes, the equation for [Cr(h20)6]3+ with EXCESS OH is [Cr(h20)3(oh)3] + 3OH- --> [Cr(oh)6]3- + 3h2o but this is the mark scheme help??! It's the same with excess nh3 too!!

The question must ask for it to start with aq chromium
Your equation is further substitution after the dilute OH- has been added

Original post by Khadijahk

Hi,
For the rechargeable & and non rechargeable cells do we need to learn the species involved in each or we would be given, if a question is asked on it ?

The only cell half equations you need to know are the hydrogen fuel cell ones. All the others will be given if asked

Guys - if you would recommend I do any 3 CHEM5 papers, which ones would they be? Very short for time - hectic exam timetable :s-smilie:

:s-smilie:

Original post by SirRaza97

Al(H₂O)₃(OH)₃+ OH^-===> [Al(OH)₄]^-+ 3H₂O

What about if they ask for [Al(H20)6]2+ with excess OH?

What are the hydrogen fuel cell equations?

Original post by Boundless_x

What about if they ask for [Al(H20)6]2+ with excess OH?

[Al(H₂O)₆]³⁺+ 4OH^-===> [Al(OH)₄]^-+ 6H₂O

it's aliminium 3+ not 2+

(edited 7 years ago)

Original post by study2016

Guys - if you would recommend I do any 3 CHEM5 papers, which ones would they be? Very short for time - hectic exam timetable :s-smilie:

:s-smilie:

Any other than June 2015 i would say

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