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# OCR (not MEI) Core 3 - 19/01/2011 Watch

1. (Original post by nikita_atikin)
You did your exam without a calculator?
Oh no, I did C3 last year on OCR, just had a look in here to see the general reaction of the paper and asked my friends (the current year 13) how they found it.

I just had a go at the first few questions (without a calculator - I generally try to avoid it if I can ).

Good luck
2. (Original post by Rokaf0)
Bristol, they've specified A in C3, B in C4 even though it's an economics course not a maths one! However, i'm still waiting for a reply from Durham and they could be a potential first choice as well
3. (Original post by yourworstnightmare)
Oh no, I did C3 last year on OCR, just had a look in here to see the general reaction of the paper and asked my friends (the current year 13) how they found it.

I just had a go at the first few questions (without a calculator - I generally try to avoid it if I can ).

Good luck
Your dedication for maths inspires me. Doing a paper that you don't need to... Respect, bro!
4. (Original post by Sophie.atlanta)
Bristol, they've specified A in C3, B in C4 even though it's an economics course not a maths one! However, i'm still waiting for a reply from Durham and they could be a potential first choice as well
Hey, exactly the same with me. I've got an economics offer from bristol but am waiting to here from ucl and edinburgh. ucl want an A* in maths though so this really matters... stressful!
5. (Original post by alexco)
If anyone's interested, I think I got the following (I think! I'm also not claiming to be a Mr M!):

1) x=(1/3)a or x=-3a
2) Stationary point at (-5,24) - translate -3 units parallel to x-axis, stretch s.f. 4, reflect in x-axis.
3) 45000cm^2 h^-1 (2sf)
4) i)25sin(theta + 16.3)
ii)12.4, 135
5) a=9, Vol. = 24*pi*ln5
6) i)dy/dx=(-6x^3 + 32x +6)/((x^3 - 4x^2 +2)^2), then show that...
ii) (2.398, -1.552)
7) i) Sq. root (e^8 - 8)
ii) f has inverse : e^x
iii) 6/e^3 (or 6e^-3)
iv) 20.3
8) ai) Drawing y=cosecx
aii) beta = 3*pi - alpha
bi) tan(2x) = 2tanx/(1-(tanx)^2)
bii) 225/322
9) i) Show that... comes out to be sum of two positive exponentials
ii) Show that... I made f"(x) = 4f(x). Then x>0.25ln3
iii) g(x) > or equal to 2*(sq root k)
I Got All Except For The Volume I Got 12*pi*ln(25)
6. 61-63/72 any chance to get an A*?
7. (Original post by a.nk)
Hey, exactly the same with me. I've got an economics offer from bristol but am waiting to here from ucl and edinburgh. ucl want an A* in maths though so this really matters... stressful!
Ah really! I know it's really stressful. Don't envy having to get an A*, an A seems bad enough after this exam!
8. (Original post by Munchy5793)
I Got All Except For The Volume I Got 12*pi*ln(25)
Thats right he just simplified it more 12pi ln(25) => 12pi ln(5)^2 = 24pi ln(5)
9. (Original post by Munchy5793)
I Got All Except For The Volume I Got 12*pi*ln(25)
12*pi*ln(25) = 12*pi*ln(5^2) = 24*pi*ln5

They'll almost certainly allow either.
10. This paper was absolute bull****.
Killed all my confidence..
Look's like i'm re-sitting.
11. (Original post by Munchy5793)
I Got All Except For The Volume I Got 12*pi*ln(25)
12*pi*ln(25)
=12*pi*ln(5^2)
=2*12*pi*ln(5)
=24*pi*ln5

12. (Original post by yu80359)
61-63/72 any chance to get an A*?
I don't know for definite (I won't be able to tell until the grade boundaries are out - OCR won't even be able to tell you), but I believe this will be enough for an A* on this paper.

However, you will need a similar performance on C4, the grade boundaries tend to be lower for C3 than C4.

Good luck and well done
13. LOL WAT DOES EVERY THINK IS A JUSTIFIED OR LIKELY GRADE BOUNDARY FOR THIS EXAM?

personally i think an A could be 45/72
14. (Original post by ElMoro)
12*pi*ln(25)
=12*pi*ln(5^2)
=2*12*pi*ln(5)
=24*pi*ln5

Do them both on a calculator (usually i'd do it for you, but i've borrowed them all out ), if you get the same numerical value from 24piln5 as 12piln25, you will get full marks for both.

I can confirm that 12pi ln 25 is certainly correct
15. (Original post by CtrlAltDefeat)
This paper was absolute bull****.
Killed all my confidence..
Look's like i'm re-sitting.
Exactly this, I went through the hardest questions in the book and most of the past papers, fully understood them, but this exam was ridiculous -.-

re-sit in the summer
16. Ok, I have just been sent a paper so will sort some answers out now. See you in half an hour!
17. (Original post by nomzie)
LOL WAT DOES EVERY THINK IS A JUSTIFIED OR LIKELY GRADE BOUNDARY FOR THIS EXAM?

personally i think an A could be 45/72
Honestly, nobody can tell yet, and nor do we want to guess to elevate/dishearten students by false hope. The past two years have been around 50 and this exam was just as hard, if not harder, so depending on how the entire country did, it could be +2/-3 each way of 50.

Just wait and see - you may surprise yourself with a mark much higher than you expected, just like I did
18. (Original post by yourworstnightmare)
Do them both on a calculator (usually i'd do it for you, but i've borrowed them all out ), if you get the same numerical value from 24piln5 as 12piln25, you will get full marks for both.

I can confirm that 12pi ln 25 is certainly correct
I didn't say it was wrong.

I was just showing them that 12*pi*ln(25)=24*pi*ln(5)
19. (Original post by Mr M)
Ok, I have just been sent a paper so will sort some answers out now. See you in half an hour!
Though I didn't sit the paper, cheers Mr M

Make sure you all rep and thank him
20. (Original post by alexco)
If anyone's interested, I think I got the following (I think! I'm also not claiming to be a Mr M!):

1) x=(1/3)a or x=-3a
2) Stationary point at (-5,24) - translate -3 units parallel to x-axis, stretch s.f. 4, reflect in x-axis.
3) 45000cm^2 h^-1 (2sf)
4) i)25sin(theta + 16.3)
ii)12.4, 135
5) a=9, Vol. = 24*pi*ln5
6) i)dy/dx=(-6x^3 + 32x +6)/((x^3 - 4x^2 +2)^2), then show that...
ii) (2.398, -1.552)
7) i) Sq. root (e^8 - 8)
ii) f has inverse : e^x
iii) 6/e^3 (or 6e^-3)
iv) 20.3
8) ai) Drawing y=cosecx
aii) beta = 3*pi - alpha
bi) tan(2x) = 2tanx/(1-(tanx)^2)
bii) 225/322
9) i) Show that... comes out to be sum of two positive exponentials
ii) Show that... I made f"(x) = 4f(x). Then x>0.25ln3
iii) g(x) > or equal to 2*(sq root k)

for Q4 I got 25sin(thete+78.3)

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