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# The Physics PHYA2 thread! 5th June 2013 watch

• View Poll Results: What mark do you think you got out of 70?
0-20
6
3.00%
21-40
12
6.00%
41-50
29
14.50%
51-60
79
39.50%
61-70
74
37.00%

1. (Original post by SortYourLife)
Do you happen to have the paper?

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(Original post by .raiden.)
Anyone have the mark scheme for jan13?
I have both
2. (Original post by Qari)
I have both
Could you share?
3. (Original post by .raiden.)
Could you share?
Don't have PDF
4. (Original post by .raiden.)
Could you share?
Here is the Jan 13 Question paper and Mark Scheme:

http://www.thestudentroom.co.uk/atta...2&d=1368049482

http://www.thestudentroom.co.uk/atta...3&d=1368049482

Enjoy

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5. Thanks!
6. Question 2 a why is it sin not cos?
7. (Original post by Qari)
Question 2 a why is it sin not cos?
I think always with these exams the weight component is always thought of a mg*sintheta

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8. (Original post by Jimmy20002012)
I think always with these exams the weight component is always thought of a mg*sintheta

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No I realised what I did wrong, it was my own mistake
9. (Original post by Qari)
No I realised what I did wrong, it was my own mistake
Guess I was too slow
Attached Images

10. Is the tension in the cable a clockwise or anticlockwise moment, how do you know?

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Attached Images

11. (Original post by Jimmy20002012)
Is the tension in the cable a clockwise or anticlockwise moment, how do you know?

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This is force*perpendicular distance from pivot
12. (Original post by Qari)
This is force*perpendicular distance from pivot
No I mean the next one

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Attached Images

13. (Original post by Jimmy20002012)
No I mean the next one

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Just look at the diagram side ways and you know the bike handle is turning around the pivot so essentially the moment you worked out earlier = T x 25mm The handle being pushed down so it must be clockwise

Does this make sense or should I draw a diagram?
14. (Original post by .raiden.)
Just look at the diagram side ways and you know the bike handle is turning around the pivot so essentially the moment you worked out earlier = T x 25mm The handle being pushed down so it must be clockwise

Does this make sense or should I draw a diagram?
Oh, so the tension is basically anticlockwise? And with the question to do with the guy on the slope, why is the weight component sin not cos, or is it asking for the weight component actually down the slope?

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15. (Original post by Jimmy20002012)
Oh, so the tension is basically anticlockwise? And with the question to do with the guy on the slope, why is the weight component sin not cos, or is it asking for the weight component actually down the slope?

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Yes it is, I drew a diagram.

Look at my earlier post explaining why its sin
Attached Images

16. I don't understand the stuff about pitch, frequency and note.

in the textbook, it says that 'the pitch of a note corresponds to frequency', so it seems to me that if two things had the same pitch, then that means they have the same frequency

so how is it that for a vibrating string tuned to the same pitch as a tuning fork, it can include all sorts of overtone frequencies whereas a tuning fork would only vibrate at the fundamental frequency?
17. Has anyone does Jan 10 past paper? i need help on question 2 a part 3 its on moments...
18. Yeah but there was already another thread. Anyway

Q3 jan 09 thanks

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19. (Original post by MelisBaysal)
Has anyone does Jan 10 past paper? i need help on question 2 a part 3 its on moments...
Taking moments about B leaves you with two other figures, one which you know (the mass) and the other which you don't (A).

The mass of the truck is he clockwise moment and A is the anticlockwise moment. That gives you;

14000*1.4 = A*2.5

A = 7840

Then because there are two springs and each will exert the same force, you simply divide your answer by two giving you 3920.
20. (Original post by lebron_23)
Taking moments about B leaves you with two other figures, one which you know (the mass) and the other which you don't (A).

The mass of the truck is he clockwise moment and A is the anticlockwise moment. That gives you;

14000*1.4 = A*2.5

A = 7840

Then because there are two springs and each will exert the same force, you simply divide your answer by two giving you 3920.

ah ok but why use 2.5 why not the distance of the rear springs to the centre of mass?

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