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    (Original post by krishkmistry)
    I get that - but what do you all think it will be?


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    80% = 57-58

    but I think that question 13 (iii) was awkward for a lot of people, except for the few that spotted the correct way to do it.
    i've heard from a few of the higher graders in my year that thye found this a big hard at points so i'm going to say 55-53.
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    (Original post by Deceived)
    For the very last question, did people get k=0 or k=4?

    Thanks
    Both Checked a few ways and these are the only 2 numbers that work
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    (Original post by PreppyNinja)
    Hope so. Was the Y-value 2root11?
    2-rt11 and 2+rt11 because the roots can be positive and negative, and the circle crosses twice
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    (Original post by Deceived)
    I think the equation went:

    V=1/3*pi*r2*(a+b)
    3V=pi*r2*(a+b)
    3V/pi=r2*(a+b)
    3V/(pi*(a+b))=r2
    r=Pos/Neg (3V/(pi*(a+b))1/2


    Hope that helps.
    Think the root had to be positive as it said r>0
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    You know if the grade boundaries aren't low, I think I managed a C/B which is bad! :/
    Reading your answers made me depressed and now I gotta work harder on the other too.

    Too many silly mistakes
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    (Original post by jojo19apr)
    Think the root had to be positive as it said r>0
    Yeah I forgot the question. That was just off the top of my head. Hopefully, in the exam I didn't put (pos/neg). Can't remember.
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    (Original post by Soho32)
    for the evaluate 0.2^-2 was it okay to leave the answer as a fraction? i.e 1/0.04?
    Not sure as it said simplify, and you haven't fully simplified it. I found it easier to look at it as (1/5)^-2, then you have 5^2 and can see easier that it is actually 25.
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    (Original post by jojo19apr)
    Not sure as it said simplify, and you haven't fully simplified it. I found it easier to look at it as (1/5)^-2, then you have 5^2 and can see easier that it is actually 25.
    omg cant believe i didnt see that

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    (Original post by TheNote)
    the answer was 25;

    (1/5)^-2

    (5/1)^2

    5^2 = 25


    since 1/0.04 = 25 then you should be okay even if youe method is a bit of a weird way round it.
    Do you think a triple decker fraction is ok - I put 1/(1/25) ?


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    (Original post by krishkmistry)
    Do you think a triple decker fraction is ok - I put 1/(1/25) ?


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    yeah because they are equivilent:
    → 1/1/25 = (1*25)/1
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    Guys what about the question 4 or 5
    It was something like 10+7sqrt5 + 38 over 1-2sqrt5
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    Does anyone know of an unofficial mark scheme available online?
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    (Original post by Sonicsuper)
    Guys what about the question 4 or 5
    It was something like 10+7sqrt5 + 38 over 1-2sqrt5
    Yeah:

    10+7√5+38/(1-2√5)

    =10+7√5+(38)(1+2√5)/(1-2√5)(1+2√5)

    =10+7√5+(38+76√5)/(1-2√5+2√5-4√25)

    =10+7√5+(38+76√5)/(-19)

    =10+7√5-2-4√5

    =8+3√5

    That's what I got. Hope this helps.
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    (Original post by Deceived)
    Yeah:

    10+7√5+38/(1-2√5)

    =10+7√5+(38)(1+2√5)/(1-2√5)(1+2√5)

    =10+7√5+(38+76√5)/(1-2√5+2√5-4√25)

    =10+7√5+(38+76√5)/(-19)

    =10+7√5-2-4√5

    =8+3√5

    That's what I got. Hope this helps.
    I got 12 + 11root5....
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    (Original post by Sonicsuper)
    I got 12 + 11root5....
    Please post your working out.
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    (Original post by Deceived)
    Please post your working out.
    Sorry i found my mistake, your answer was right!
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    (Original post by Sonicsuper)
    Sorry i found my mistake, your answer was right!
    No problem. I made an egregious error in the exam. I'm so fortunate I checked my answers.
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    Reckon 56 for an A
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    Is there an unofficial mark scheme available anywhere by any chance?
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    (Original post by Sonicsuper)
    I got 12 + 11root5....
    All you did wrong was add (2 + 4root5) instead of taking away. Otherwise you would have got the right answer
 
 
 
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