Edexcel FP2 June 2015 - Official Thread Watch

TeeEm
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#201
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#201
last minute practice?
http://www.thestudentroom.co.uk/show....php?t=3353445
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nayilgervinho
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#202
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Can someone help me with 9b of this paper I don't know why they have used the limits they have.
Qp: https://8dedc505ac3fba908c50836f5905...%20Edexcel.pdf
Ms:https://8dedc505ac3fba908c50836f5905...%20Edexcel.pdf
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Anshul6974
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#203
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(Original post by nayilgervinho)
Can someone help me with 9b of this paper I don't know why they have used the limits they have.
Qp: https://8dedc505ac3fba908c50836f5905...%20Edexcel.pdf
Ms:https://8dedc505ac3fba908c50836f5905...%20Edexcel.pdf
They are using the points of intersection and the sector of a circle, by intergrating between the intersection point and zero, then multiplying by 2, all that's left is the sector.
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kotosif
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#204
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(Original post by nayilgervinho)
Can someone help me with 9b of this paper I don't know why they have used the limits they have.
Qp: https://8dedc505ac3fba908c50836f5905...%20Edexcel.pdf
Ms:https://8dedc505ac3fba908c50836f5905...%20Edexcel.pdf
They are integrating the C1 polar question from 0 to pi/12. That helps find that tiny sliver that you need. They then doubled that and added that to the area of the sector, which was found using C2 polar question, to find the total area of R.
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Edac
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#205
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ok I thought I was fine til I found this, now im ****ting myself

One of these is arg((z+1)/(z+i)), and other is arg((z+i)/(z+1))

Which one is which and why? please help! thanks
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InOrbit
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(Original post by Edac)
ok I thought I was fine til I found this, now im ****ting myself

One of these is arg((z+1)/(z+i)), and other is arg((z+i)/(z+1))

Which one is which and why? please help! thanks
Draw the circle ANTICLOCKWISE from the numerator to the denominator.

arg((z+1)/(z+i)) would be anticlockwise arc from x=-1 to y=-1.
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Edac
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(Original post by Alex:)
Draw the circle ANTICLOCKWISE from the numerator to the denominator.

arg((z+1)/(z+i)) would be anticlockwise arc from x=-1 to y=-1.
Thank you! Why have I only heard this now >.< Im starting to doubt what I know...
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TeeEm
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#208
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last minute practice?
http://www.thestudentroom.co.uk/show....php?t=3353445
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nayilgervinho
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#209
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#209
Predictions for any curveballs they could throw at us?
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Emmi12345
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#210
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What would we do for arg((z-z1)/(z-z2)) = 3pi/4 ? Anyone?
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Anshul6974
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(Original post by Emmi12345)
What would we do for arg((z-z1)/(z-z2)) = 3pi/4 ? Anyone?
A minor arc going from z1 to z2 anti-clockwise
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aidinpoori
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(Original post by Pholl)
Hey guys, quick question about doing second order differentials:

When you're working out the complimentary function, and you're left with an answer that can be written like e^{x}[A\text{cos}(x) + B\text{sin}(x)] does it actually matter if you write an "i" after the B? (e.g. e^{x}[A\text{cos}(x) + Bi\text{sin}(x)]). I did it by accident while practicing and I'm unsure whether I'd get the marks.
No it doesn't matter and you'll get the full mark since Bi can be considered to be another constant (say B'. In fact the constants A and B are both complex in the complementary function.
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aidinpoori
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(Original post by Pholl)
Never said it was. Just didn't consider the fact that the constants A and B have to be real.
You are absolutely right. A and B are complex in general (remember every real number is also a complex number with the imaginary part equal to zero)
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TeeEm
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#214
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http://www.thestudentroom.co.uk/show....php?t=3376607
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nizamikn
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#215
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#215
Did anyone here take the FP2 IAL EXAM? WTF WAS THAT ****? 1.5 HOURS FOR THAT? **** YOU EDEXCEL!
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bobo19966
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#216
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How was it? (Not IAL)
I think it is just another standand paper
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Asad_2015
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#217
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(Original post by bobo19966)
How was it?
I think it is just another standand paper
Wat u get for the answers
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bobo19966
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#218
(Original post by Asad_2015)
Wat u get for the answers
Which answers?
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kidder007
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#219
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#219
Went pretty well answered most things. Grade boundaries will be roughly the same as previous years


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simonli2575
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#220
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I was kinda disappointed that it wasn't very hard.
Anyway, here're my answers.
Spoiler:
Show
1.
-6<x<-3 or x>1
x>1

2.
4
2pi/3
4096
+-sqrt(8) & +-sqrt(8)i

3.
3cot(x)-2cos^2(x)cot(x)+Ccosec(x)

5.
(-0.8,0) r=1.2
inside the circle

6.
(4.5a,pi/3)
a^2(9pi/4+81sqrt(3)/16

7.
Coefficients:
3, 8sqrt(3), 40, 176sqrt(3)/3

8.
x^4(A+Blnx)+1/8lnx+1/16
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