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    (Original post by OscarH)
    So I kinda screwed up the coursework, meaning i'm going to have to get 70-71/72 to get 90%. Anyone know whether the 90% in C3 and C4 is needed for both exams? Or is taken as an average?

    Also, can I redo my coursework without redoing my exams? If they go well that is.
    average
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    (Original post by [email protected])
    anyone got a list of what each transformation means

    i.e. f(ax) is a strethc in the y direction by a?????
    f(ax) is a stretch in the x direction by 1/a!!!
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    Can someone tell me what I should look out for?

    What should I focus my revision in?

    I literally have done every single past paper and some thrice.
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    (Original post by lizard54142)
    f(ax) is a stretch in the x direction by 1/a!!!
    Dont suppose you can list them all can you??

    so what would


    bf(ax) be??
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    (Original post by [email protected])
    Dont suppose you can list them all can you??

    so what would


    bf(ax) be??
    f(x-a) + b is a translation (a, b)

    af(x) is a stretch parallel to y axis, SF a

    f(ax) is a stretch parallel to x axis, SF 1/a

    -f(x) is a reflection in x axis

    f(-x) is a reflection in y axis
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    On June 2014 Q9iii how do we know that the grad of tangent = -m

    I read the bit before but still dont understand?
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    (Original post by [email protected])
    On June 2014 Q9iii how do we know that the grad of tangent = -m

    I read the bit before but still dont understand?
    Link the paper.
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    (Original post by lizard54142)
    Link the paper.
    9iii
    http://www.sixthform.m34maths.com/A-...c3/c314juQ.pdf
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    I'm just about to do this paper so don't want to look at the mark scheme I'll reply when I get to that question if no one else has answered.
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    (Original post by lizard54142)
    I'm just about to do this paper so don't want to look at the mark scheme I'll reply when I get to that question if no one else has answered.
    Okay thank you
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    because OP and the tangent are equally inclined to the x axis. The gradient of the line y=mx is m. Equally inclined means the gradients are the same but looking at the graph the line and the tangent form an "X" shape so the gradient of the tangent must be negative m (-m). hope that helps
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    (Original post by Sean 2062)
    because OP and the tangent are equally inclined to the x axis. The gradient of the line y=mx is m. Equally inclined means the gradients are the same but looking at the graph the line and the tangent form an "X" shape so the gradient of the tangent must be negative m (-m). hope that helps
    Okay I think I get what you mean, thank you
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    they lines form an isosceles triangle
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    so the line y=mx and the tangent are equally inclined because the lines form an isosceles triangle
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    the x axis is the base of the triangle
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    (Original post by Sean 2062)
    the x axis is the base of the triangle
    Omg thank you get it now
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    Got 71 in June 2014 so I think I'm ready (didn't say rotational symmetry about origin of order 2)

    Good luck tomorrow everyone!
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    (Original post by lizard54142)
    Got 71 in June 2014 so I think I'm ready (didn't say rotational symmetry about origin of order 2)

    Good luck tomorrow everyone!
    That or 180 degrees?
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    To get an A overall, is it just 480 UMS for both as and a2 combined ?


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    If this paper is similar to the January 2013 I think I might be able to get that B Iv been spending countless hours trying to hit. God I can't wait to never do integration or differentiation again! I need that B in Maths though buts it's so difficult.
 
 
 
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