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Edexcel FP3 - 27th June, 2016 watch

  • View Poll Results: How did you find the Edexcel FP3 exam?
    Very hard
    41
    8.40%
    Hard
    69
    14.14%
    Normal
    156
    31.97%
    Easy
    165
    33.81%
    Very easy
    57
    11.68%

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    (Original post by EricPiphany)
    The guy they hired to do the solutions got drunk that night.
    "Professor Adams. Are you sure you're fit to continue with the solution bank?"

    "*hic* mmmyeeaaaaah hold my maths while I write this beerrrrrrr"
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    (Original post by Zacken)
    Unpopular opinion: Chapter 2 mixed exercises is quite nice...
    I actually like it. They actually require some thought!
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    (Original post by aymanzayedmannan)
    they're doable after the first 3
    I thought question 3 was pretty easy tbh, the first 2 were hideous tho. Having said that, I did question 3 differently to solution banl
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    FP3 is probably the worst module I've ever done. None of the content seems hard, but I've done exam questions and they just leave me so confused (literally any topic). Are there any websites that explain the solid parts of FP3 (namely loci of points associated with certain graphs and vectors).
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    (Original post by Craig1998)
    FP3 is probably the worst module I've ever done. None of the content seems hard, but I've done exam questions and they just leave me so confused (literally any topic). Are there any websites that explain the solid parts of FP3 (namely loci of points associated with certain graphs and vectors).
    http://www.examsolutions.net/maths-r...FP3/module.php
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    Thank you, last time I checked that website FP3 wasn't finished.
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    (Original post by Craig1998)
    Thank you, last time I checked that website FP3 wasn't finished.
    yea it got finished off quite recently, just in time too :laugh:
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    Apparently question 8 last year was hard (the last question).

    My friend didn't answer the last part in the exam last year :0.
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    (Original post by Louisb19)
    Apparently question 8 last year was hard (the last question).

    My friend didn't answer the last part in the exam last year :0.
    im planning to do it over easter (i dont want to leave it to june as if its as hard as everyone is making out then my confidence will plummet just before the exam)

    i am actually quite nervous :laugh:
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    (Original post by Craig1998)
    Thank you, last time I checked that website FP3 wasn't finished.
    (Original post by DylanJ42)
    yea it got finished off quite recently, just in time too :laugh:
    It hasn't been finished. There's nothing on matrices, hyperbolas and it's missing a huge chunk of integration.
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    (Original post by Zacken)
    It hasn't been finished. There's nothing on matrices, hyperbolas and it's missing a huge chunk of integration.
    oh then im retarded :laugh: whoops
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    Name:  Screen Shot 2016-03-29 at 16.25.29.png
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    I can't understand what the last part of this question wants me to do, would anyone be able to explain it to me?

    Thanks

    Zacken
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    (Original post by Euclidean)
    Name:  Screen Shot 2016-03-29 at 16.25.29.png
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    I can't understand what the last part of this question wants me to do, would anyone be able to explain it to me?

    Thanks

    Zacken
    Normalised direction vector
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    (Original post by Euclidean)
    Name:  Screen Shot 2016-03-29 at 16.25.29.png
Views: 129
Size:  224.8 KB

    I can't understand what the last part of this question wants me to do, would anyone be able to explain it to me?

    Thanks

    Zacken
    I'm not sure what the "cosines" mean but as Eric, said - the unit vector in the direction OF.
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    (Original post by Zacken)
    I'm not sure what the "cosines" mean but as Eric, said - the unit vector in the direction OF.
    If you have a normalised vector, the cosine of the angle between it and each of i, j, and k are the components of the vector, as can be seen by taking the dot products.
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    (Original post by EricPiphany)
    If you have a normalised vector, the cosine of the angle between it and each of i, j, and k are the components of the vector, as can be seen by taking the dot products.
    Ah, thanks!
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    (Original post by EricPiphany)
    Normalised direction vector
    (Original post by Zacken)
    I'm not sure what the "cosines" mean but as Eric, said - the unit vector in the direction OF.
    (Original post by EricPiphany)
    If you have a normalised vector, the cosine of the angle between it and each of i, j, and k are the components of the vector, as can be seen by taking the dot products.
    Thanks!
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    (Original post by Louisb19)
    Apparently question 8 last year was hard (the last question).

    My friend didn't answer the last part in the exam last year :0.
    I didn't get time to finish it in the exam but i did it straight after and it wasn't too bad. Still lost loads of marks in that exam.


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    (Original post by Euclidean)
    Name:  Screen Shot 2016-03-29 at 16.25.29.png
Views: 129
Size:  224.8 KB

    I can't understand what the last part of this question wants me to do, would anyone be able to explain it to me?

    Thanks

    Zacken
    (Original post by EricPiphany)
    If you have a normalised vector, the cosine of the angle between it and each of i, j, and k are the components of the vector, as can be seen by taking the dot products.
    (Original post by Zacken)
    Ah, thanks!
    The phrase is not used in Edexcel FP3.

    More information here:
    https://en.wikipedia.org/wiki/Direction_cosine
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    How would you phrase the answer to this question? Jn is defined as Jn = integral between 0 and 2pi of cos^n x, with the reduction being nJn=cos^n-1 x sinx +(n-1)Jn-2. Basically you had to show if n is odd Jn is always equal to 0. I basically said that the only term independent of sine (as sine npi is 0) is the case where n =1, i.e. the integral of cosx so again you get sinx which when evaluated obviously gives you 0 again, but i wondered if there was a more eloquent way to show it.
 
 
 
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