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Edexcel GCSE Mathematics A Higher Paper 2016 Unofficial Markscheme Watch

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    (Original post by SkyeAmber)
    Me too
    well done
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    (Original post by Omz123)
    Sh¡t I got 7 zeros at the end of my answer not 8
    are u gonna cry?
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    (Original post by tig16v)
    oh sorry man, that was my last grain!
    go 2 the soup kitchen im sure theyll fed u
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    (Original post by Redcoats)
    So did I. I'm pretty sure that's correct.
    I got only 3 minus root 6????
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    OMG exam was hard! Can someone tell me how many marks the questions were. I want to calculate how i did. I'm predicted an A but I feel like I got a B


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    (Original post by 34908seikj)
    The grade boundaries will be pretty high, it was quite an easy exam imo
    Agree. Reckon the grade boundaries will be 99 for an A*, 98 for an A, 97 for a B, 96 for a C ahaha
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    (Original post by DhillonDodhia)
    hahahahha unlucky mate
    just kids
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    (Original post by LogicalFallacy)
    Hey, if anybody is willing to contribute the answers, and preferably the questions, then I shall set up a mark scheme for you all. Thanks in advance!

    Can people please attach question numbers to their answers? Method would be appreciated.
    Spoiler:
    Show
    Question 1. What is the volume of the prism?
    Area of face = 30cm² Length of prism = 25cm.

    30cm² x 25cm = 750cm³

    Question 6(?). How many teachers are there altogether?
    2/5 of teachers are male. 36 are male.

    2/5 of total = 36
    2 x 18 = 36
    18 x 2 = 90.
    Answer is 90 teachers.


    Question (?). X² = 4(X-3)²

    X² = 4[(X - 3)(X - 3)]
    X² = 4[X² - 3X - 3X+ 9]
    X² = 4[X² - 6X + 9]
    X² = 4X² - 24X + 36

    0 = 4X² - X² - 24X + 36
    0 = 3X² - 24X + 36

    0 = 3[X² - 8x + 12]
    0 = 3[(X - 6)(X - 2)]

    X = 6 or X = 2
    Q?? - Estimate 892/18.9 (or something idk) (2 marks - maybe)
    Round to 1sf
    900/20 = 45

    Q?? - Angle = 69 (4 marks [I think])

    180-48-48 = 84 (angles in a triangle sum to 180 & base angles in an isosceles are equal)
    84/2 = 42 (angle at the centre is twice the angle at the circumference)
    (180-42)/2 = 69 (angles in a triangle sum to 180 & base angles in an isosceles are equal)
    Therefore angle = 69 (alternate segment theorem)

    Q?? - Angie does not have enough varnish (5 marks)

    Total area = (4x10) + (2x2.5x2) = 50 metres squared
    Litres required = 50/5 = 10 litres
    Angie has = 3 x 2.5 = 7.5 litres
    10 litres > 7.5 litres

    Q?? - find shaded area of triangles in square= 25(4 - π) (5 marks)

    Square = 10x10 = 100 cm squared
    Circle = π x 5 squared = 25π
    Shaded = 100 - 25π = 25 (4 - π)

    Q25 - find the shaded area = 3 - root6/12 (3 marks)

    (root2/2 x root2/2)x 1/2 = 1/2 x 1/2 = 1/4 cm squared
    (root3/3 x root2/2) x 1/2/ = root6/6 x 1/2 = root6/12 cm squared
    1/4 - root6/12 = 3/12 - root6/12 = 3 - root6/12

    That's all I can remember for now
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    would 85% be enough for an A*??
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    What was the answer to the circle theorems question?
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    (Original post by katodizzle)
    What was the answer to the circle theorems question?
    69
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    Area question attached belowName:  ImageUploadedByStudent Room1464261362.835161.jpg
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Size:  124.1 KB


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    (Original post by 11tan)
    Q?? - Estimate 892/18.9 (or something idk) (2 marks - maybe)
    Round to 1sf
    900/20 = 45

    Q?? - Angle = 69 (4 marks [I think])

    180-48-48 = 84 (angles in a triangle sum to 180 & base angles in an isosceles are equal)
    84/2 = 42 (angle at the centre is twice the angle at the circumference)
    (180-42)/2 = 69 (angles in a triangle sum to 180 & base angles in an isosceles are equal)
    Therefore angle = 69 (alternate segment theorem)

    Q?? - Angie does not have enough varnish (5 marks)

    Total area = (4x10) + (2x2.5x2) = 50 metres squared
    Litres required = 50/5 = 10 litres
    Angie has = 3 x 2.5 = 7.5 litres
    10 litres > 7.5 litres

    Q?? - find shaded area of triangles in square= 25(4 - π) (5 marks)

    Square = 10x10 = 100 cm squared
    Circle = π x 5 squared = 25π
    Shaded = 100 - 25π = 25 (4 - π)

    Q25 - find the shaded area = 3 - root6/12 (3 marks)

    (root2/2 x root2/2)x 1/2 = 1/2 x 1/2 = 1/4 cm squared
    (root3/3 x root2/2) x 1/2/ = root6/6 x 1/2 = root6/12 cm squared
    1/4 - root6/12 = 3/12 - root6/12 = 3 - root6/12

    That's all I can remember for now
    Yeah I got all the same answers. Does anyone remember what they got for using the graph to estimate the x^2+4x-2=0 etc.
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    (Original post by DhillonDodhia)
    are u gonna cry?
    Probably...it is my GCSE math exam...
    Also stop commenting anything that's not math related u scrub
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    someone talk about the vectors question
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    (Original post by MrsGren)
    would 85% be enough for an A*??
    yes
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    (Original post by MrsGren)
    would 85% be enough for an A*??

    No, 'twas an easy paper, probably around 92%
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    How is question 11, 36%. Please can you show the working out.
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    (Original post by MrsGren)
    would 85% be enough for an A*??
    Normally yeah
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    (Original post by Omz123)
    Sh¡t I got 7 zeros at the end of my answer not 8
    (3.5x10^6)/(5x10^-3)
    3.5 / 5 = 0.7
    indices rule 6--3 =9
    0.7x10^9
    put in standard form
    7x10^8
 
 
 
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