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    (Original post by tigerz)
    Ahh thanks, for now i'll just do the simple ones
    I don't even know how many conversations i'm having anymore :s
    Haha It gets confusing right?

    (Original post by Felix Felicis)
    Yeah, I know. xD
    I'm sure you do, but you called me a troll
    Comparitively: Me
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    :troll2:


    You:
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    :troll:
    :laugh:
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    (Original post by MathsNerd1)
    Good good, I'll now be back on this forum a lot more to test myself with the challenging questions and to help out others who need it as this morning I finished my exam which was taking such a great deal of my time up
    OH YEAHH! was it Chemistry? How was it?


    (Original post by joostan)
    Haha It gets confusing right?
    Yup! non-stop posting hahah
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    (Original post by reubenkinara)
    I give up. What I have is a stupid mess. I'll post in spoilers
    Spoiler:
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    S_{\infty}=\dfrac{(log_2 e)^2}{log_2 \frac{e^2}{2}}
    Yeah...the 2 forms aren't even equivalent

    Hint
    Common ratio = -\dfrac{\log_{4} e}{\log_{2} e} = -\dfrac{1}{2} \Rightarrow \mathcal{S}_{\infty} = ?
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    (Original post by reubenkinara)
    There's something I've always found interesting in logs!
    You gonna leave us hanging?

    (Original post by reubenkinara)
    I give up. What I have is a stupid mess. I'll post in spoilers
    Spoiler:
    Show
    S_{\infty}=\dfrac{(log_2 e)^2}{log_2 \frac{e^2}{2}}
    What was your common ratio?
    It's a while since I did this question :lol:
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    (Original post by tigerz)
    OH YEAHH! was it Chemistry? How was it?
    It was indeed and it didn't go as badly as it could've I've definitely lost 5 marks but it could be 3 more, so hopefully that'll still get me an A
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    (Original post by tigerz)
    Yup! non-stop posting hahah
    Live dangerously :horse:
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    (Original post by joostan)
    I'm sure you do, but you called me a troll
    Comparitively: Me
    Spoiler:
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    :troll2:


    You:
    Spoiler:
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    :troll:
    :laugh:
    Pshh, you're like a little troll, I'm the master, groovy troll :banana: :groovy:
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    (Original post by joostan)
    Live dangerously :horse:
    LOOL, yeah been procrastinating too much these last few days!

    (Original post by MathsNerd1)
    It was indeed and it didn't go as badly as it could've I've definitely lost 5 marks but it could be 3 more, so hopefully that'll still get me an A
    Waheeeyy
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    (Original post by joostan)
    You gonna leave us hanging?



    What was your common ratio?
    It's a while since I did this question :lol:
    My common ratio was \dfrac {-log_4 e}{log_2 e}
    I've forgotten what I've found interesting :banghead:
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    (Original post by MathsNerd1)
    Good good, I'll now be back on this forum a lot more to test myself with the challenging questions and to help out others who need it as this morning I finished my exam which was taking such a great deal of my time up
    Here's a DE as promised.
    Nothing exciting just a bit of an effort -
    Spoiler:
    Show
    it's got a star next to it which means it's meant to be hard.

    Find the general solution to the DE
    \dfrac{dy}{dx} = x^2\sin(x)\cot^2(y)

    (Original post by tigerz)
    LOOL, yeah been procrastinating too much these last few days!

    Waheeeyy
    It's a lil bit of fun.

    (Original post by reubenkinara)
    My common ratio was \dfrac {-log_4 e}{log_2 e}
    I've forgotten what I've found interesting :banghead:
    Looks good from memory - you know this simplifies?
    Lol can't have been that exciting then.
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    (Original post by Felix Felicis)
    Yeah...the 2 forms aren't even equivalent

    Hint
    Common ratio = -\dfrac{\log_{4} e}{\log_{2} e} = -\dfrac{1}{2} \Rightarrow \mathcal{S}_{\infty} = ?
    I see. What does mine simplify to?
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    Are we all anticipating a hard C2 paper tomorrow?
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    (Original post by joostan)
    Here's a DE as promised.
    Nothing exciting just a bit of an effort -
    Spoiler:
    Show
    it's got a star next to it which means it's meant to be hard.

    Find the general solution to the DE
    \dfrac{dy}{dx} = x^2\sin(x)\cot^2(y)
    I'll do this later on tonight but right now I've got to head off to get my Chemistry mock mark and have a good 2 hours with my teacher by myself, fun times
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    Guys, did you hear that as some C4 papers were lost, we'll be doing the reserve paper?
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    (Original post by GCSE-help)
    Are we all anticipating a hard C2 paper tomorrow?
    Yeah

    (Original post by joostan)
    Here's a DE as promised.
    Nothing exciting just a bit of an effort -
    Spoiler:
    Show
    it's got a star next to it which means it's meant to be hard.

    Find the general solution to the DE
    \dfrac{dy}{dx} = x^2\sin(x)\cot^2(y)


    It's a lil bit of fun.
    Haha it really is Didn't come on here from end you yr11 till last week, and now i'm on here like 24/7 LOOL
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    (Original post by GCSE-help)
    Are we all anticipating a hard C2 paper tomorrow?
    Not particularly.
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    (Original post by Felix Felicis)
    Pshh, you're like a little troll, I'm the master, groovy troll :banana: :groovy:
    You can be whoever you want to be princess
    Spoiler:
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    It seemed like a suitably cheesy thing to say - I don't know why it popped into my head.


    (Original post by tigerz)
    Yeah
    Haha it really is Didn't come on here from end you yr11 till last week, and now i'm on here like 24/7 LOOL
    It's nice to chat to people and do some other people's work regardless of your own mountain of work :lol:
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    (Original post by joostan)
    Here's a DE as promised.
    Nothing exciting just a bit of an effort -
    Spoiler:
    Show
    it's got a star next to it which means it's meant to be hard.

    Find the general solution to the DE
    \dfrac{dy}{dx} = x^2\sin(x)\cot^2(y)


    It's a lil bit of fun.



    Looks good from memory - you know this simplifies?
    Lol can't have been that exciting then.
    yep. felix has said
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    (Original post by MathsNerd1)
    I'll do this later on tonight but right now I've got to head off to get my Chemistry mock mark and have a good 2 hours with my teacher by myself, fun times
    Okey dokey

    (Original post by reubenkinara)
    yep. felix has said
    Has he been teaching you dark magic?
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    (Original post by joostan)
    Okey dokey


    Has he been teaching you dark magic?
    Quickest way to success :adore:
 
 
 
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