Turn on thread page Beta
    Offline

    4
    ReputationRep:
    (Original post by Student403)
    Apologies I thought that was trivial......
    Though sound trivial but it would be helpful just in case someone isn't sure on the selection of modules into calculation of A* in FM..
    Offline

    6
    ReputationRep:
    For the last question first part I wrote it as 0.722, -0.722 or something rather than plus/ minus arcosh(0.75). Would that still get marks cause it didn't say in exact form?
    Offline

    8
    Just watched the Hitler video, lol.
    Offline

    2
    ReputationRep:
    (Original post by Arsey)
    Just watched the Hitler video, lol.
    Seen the paper any thoughts? Boundary predictions? :P
    Offline

    2
    ReputationRep:
    arsey make a mark scheme!!
    Offline

    3
    ReputationRep:
    (Original post by SB0073)
    64/65 for an A or A*?
    A* I'm hoping. I think 64/75 is fairly standard mark for an A grade. So maybe a few marks lower for an A grade for this paper. 60/75 for an A perhaps?
    Offline

    0
    ReputationRep:
    For the De Moivre's theorem question, did you need to start by showing that z^n - z^-n = 2i sin theta? I just quoted it
    Offline

    0
    ReputationRep:
    (Original post by DrownedDeity)
    Question didn't ask you to show it.
    But it said 'Using De Moivre's Theorem'. Technically, z^n -z^-n = 2i sin theta is not De Moivre's Theorem, it's an application of it.
    Offline

    2
    ReputationRep:
    (Original post by solid222)
    arsey make a mark scheme!!
    Arsey's been told off by Edexcel for making them, he's posted somewhere on TSR (can't remember where sorry) that he'll stop making them out of respect for Edexcel.
    Offline

    2
    ReputationRep:
    (Original post by sunsri101)
    But it said 'Using De Moivre's Theorem'. Technically, z^n -z^-n = 2i sin theta is not De Moivre's Theorem, it's an application of it.
    I showed it just in case, cause doing the question without it would not have used de Moivre's
    Offline

    0
    ReputationRep:
    (Original post by taichingkan)
    I showed it just in case, cause doing the question without it would not have used de Moivre's
    Ok, would I have lost all the marks for not doing this?
    Offline

    2
    ReputationRep:
    someone needs to make a markscheme
    Offline

    3
    ReputationRep:
    (Original post by Arsey)
    Just watched the Hitler video, lol.
    Hey Arsey, what do you think the A* boundary will be for this paper?
    Offline

    2
    ReputationRep:
    (Original post by sunsri101)
    Ok, would I have lost all the marks for not doing this?
    IIRC it was 5 marks, wasn't it? I'd say 2-3 marks tops.
    Offline

    2
    ReputationRep:
    (Original post by sunsri101)
    Ok, would I have lost all the marks for not doing this?
    Also, for the polar area question, I did C1-C2 instead of C1+C2, giving me an answer of 15ish instead of the 32.5 that most people seem to have got. If all the following working was correct, How many marks might I lose (I think that part Q was 7 marks)
    Offline

    0
    ReputationRep:
    (Original post by taichingkan)
    IIRC it was 5 marks, wasn't it? I'd say 2-3 marks tops.
    Yes it was. OK, thanks
    Offline

    0
    ReputationRep:
    (Original post by taichingkan)
    Also, for the polar area question, I did C1-C2 instead of C1+C2, giving me an answer of 15ish instead of the 32.5 that most people seem to have got. If all the following working was correct, How many marks might I lose (I think that part Q was 7 marks)
    You would get marks for integrating correctly and substituting limits. So I would have thought that you would get 4/7
    Offline

    2
    ReputationRep:
    (Original post by sunsri101)
    You would get marks for integrating correctly and substituting limits. So I would have thought that you would get 4/7
    Okay, thanks! How did you find the exam?
    Offline

    8
    ReputationRep:
    (Original post by sunsri101)
    But it said 'Using De Moivre's Theorem'. Technically, z^n -z^-n = 2i sin theta is not De Moivre's Theorem, it's an application of it.
    Being pedantic: z^(n) - z^(-n) = 2i sin (n theta)

    Any application of the theorem would be classed as 'using' the theorem. After all, the method only works if the theorem does too.

    (Original post by taichingkan)
    I showed it just in case, cause doing the question without it would not have used de Moivre's
    I also did that, they might not give credit for it but it's better to be safe than sorry
    Offline

    2
    ReputationRep:
    (Original post by Euclidean)
    Being pedantic: z^(n) - z^(-n) = 2i sin (n theta)

    Any application of the theorem would be classed as 'using' the theorem. After all, the method only works if the theorem does too.



    I also did that, they might not give credit for it but it's better to be safe than sorry
    Yeah true, hopefully they give us full credit :/
 
 
 
Reply
Submit reply
Turn on thread page Beta
Updated: February 24, 2017

2,743

students online now

800,000+

Exam discussions

Find your exam discussion here

Poll
Should predicted grades be removed from the uni application process

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reply
Hide
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.