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    Anyone remember their answers to 2b, 4ia, 4ib, and the roots question?
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    (Original post by JoshC98)
    Anyone remember their answers to 2b, 4ia, 4ib, and the roots question?
    n(n^2 - 3n -9)/2(n + 2)

    x=(r/q)[1-e^-(qt/p)]

    y=(2/5)sin(theta)-(1/5)cos(theta)+(1/5)e^-2theta

    Not entirely sure I remember what the roots question was?

    Edit: oh I remember now

    2e^i(pi/24, 13pi/24, -23pi/24, -11pi/24)

    Your roots may be different, add 2pi to ones you don't match with just to check if they're equal
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    (Original post by Rkai01)
    Yes it was can't remember what I put but I'm assuming i lost a mark.
    No you wouldn't lose a mark. I put it in that form as well (it didn't specify). There was a paper in the past which had an answer to 3sf so we'll be fine.
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    (Original post by somevirtualguy)
    n(n^2 - 3n -9)/2(n + 2)

    x=(r/q)[1-e^-(qt/p)]

    y=(2/5)sin(theta)-(1/5)cos(theta)+(1/5)e^-2theta

    Not entirely sure I remember what the roots question was?

    Edit: oh I remember now

    2e^i(pi/24, 13pi/24, -23pi/24, -11pi/24)

    Your roots may be different, add 2pi to ones you don't match with just to check if they're equal
    For the series proof. I wrote out non simplified sum of the series, after simplifying my final answer was in that form, but it was wrong. I tried it again after the exam and wrote out the non simplified equation as I had in the exam and I got the right answer this time. How many marks would I lose for that?
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    Just wondering whats happened to the unofficial mark scheme.. it's been 24 hours.
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    (Original post by Pyslocke)
    For the series proof. I wrote out non simplified sum of the series, after simplifying my final answer was in that form, but it was wrong. I tried it again after the exam and wrote out the non simplified equation as I had in the exam and I got the right answer this time. How many marks would I lose for that?
    I'm useless at estimating these sorts of things Zacken should be able to give you a better idea
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    (Original post by Craig1998)
    Just wondering whats happened to the unofficial mark scheme.. it's been 24 hours.
    Chill, I woke up late. Currently on Q6.
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    (Original post by Zacken)
    Chill, I woke up late. Currently on Q6.
    Hey I saw your post where you said you only need 5 marks or something to get A*. How is that even possible?
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    (Original post by fpmaniac)
    Hey I saw your post where you said you only need 5 marks or something to get A*. How is that even possible?
    Already sat M1, M1, M3, S1, S2, S3 in Jan and I've sat S3 in June already so I barely need anything in FP2/3 to get the A*
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    (Original post by Zacken)
    Already sat M1, M1, M3, S1, S2, S3 in Jan and I've sat S3 in June already so I barely need anything in FP2/3 to get the A*
    So your sitting 8 FM subjects and 6 Maths subjects?
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    (Original post by target21859)
    No you wouldn't lose a mark. I put it in that form as well (it didn't specify). There was a paper in the past which had an answer to 3sf so we'll be fine.
    No but I'm assuming I rounded it wrong lol
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    (Original post by fpmaniac)
    So your sitting 8 FM subjects and 6 Maths subjects?
    7 FM and 6 maths:

    C1-4, M1-3, S1-3, FP1-3 = (4 + 2) + (1 + 3 + 3) = 6 + 7
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    (Original post by Zacken)
    7 FM and 6 maths:

    C1-4, M1-3, S1-3, FP1-3 = (4 + 2) + (1 + 3 + 3) = 6 + 7
    Will you post unofficial MS on here or start a new thread?
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    (Original post by athers116)
    Will you post unofficial MS on here or start a new thread?
    New thread.
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    (Original post by Zacken)
    New thread.
    ok thanks
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    (Original post by Zacken)
    New thread.
    Hey Zacken, how many marks do you think I lost in the polar coordinates if I substituted in the wrong limits for BOTH curves? My integration is correct and I added both areas up at the end so I should get those method marks...everything is correct apart from the limits and final answer
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    On the last question i worked out the area of the circle and took off the area of the bit on the right. The method works but i must've made a numerical error in the exam. How many marks lost?
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    (Original post by athers116)
    On the last question i worked out the area of the circle and took off the area of the bit on the right. The method works but i must've made a numerical error in the exam. How many marks lost?
    Why do you think it's a circle?
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    (Original post by Zacken)
    Why do you think it's a circle?
    r=7cos(theta) is a circle with radius 3.5
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    For the polar coordinates question did you guys get cos(theta) = 0.74 and for theta got a decimal answer in radians?
 
 
 
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