Edexcel Chemistry A2 Unit 5 ~ Wednesday 19th June 2013 (Now Closed) Watch

Poll: How pumped up are you for this exam?-(warning)-(bad jokes arene this poll!)
"Titanium-I'm not going to corrode (even at high temperatures)" (A*) (22)
16.67%
"Benzene's my middle name, give me the paper in a week and I'll ace it!" (A) (27)
20.45%
"Yeah, I'm fairly electrophillic (positively charged) about the exam" (B) (27)
20.45%
"I'm in the middle of the salt bridge, but I will pass-eventually" (C) (21)
15.91%
"I'm feeling rather electroNegative about this exam" (D) (18)
13.64%
"Benzene, what's that?" (E) (6)
4.55%
"Chemistry, what's that?" (F) (11)
8.33%
This discussion is closed.
mrhedgehog
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#2261
(Original post by Bord3r)
Ah the elusive question 16. I'm starting to doubt whether it even exists.
I know right I am still thinking trying to remember what it was
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mrhedgehog
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#2262
for the 2 peaks of benzophenone is the C-H arene peak correct as one of them with the wave number of 3030cm-1
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mar junior
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(Original post by Bord3r)
Ah the elusive question 16. I'm starting to doubt whether it even exists.
it was talking about planar molecules,

Which one of these isnt planar?

A: C6H6, (Benzene ring)

B: CCL4

C: BF3

D: Pt(NH3)2(CL)2

I chose CCL4, as its tetrahedral and all the others are planar


I think the grade boundaries for this exam will be minimum 70 for an A, This paper was relatively easy considering the vast amount of stuff they could have asked, everything was straightforward.
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F1's Finest
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#2264
(Original post by mar junior)
it was talking about planar molecules,

Which one of these isnt planar?

A: C6H6, (Benzene ring)

B: CCL4

C: BF3

D: Pt(NH3)2(CL)2

I chose CCL4, as its tetrahedral and all the others are planar


I think the grade boundaries for this exam will be minimum 70 for an A, This paper was relatively easy considering the vast amount of stuff they could have asked, everything was straightforward.
Yeah the answer was CCl4
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TheNoobyPotato
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(Original post by Bord3r)
Multiple Choice (Unofficial) Mark Scheme

Explanation of question/answer in brackets

1 - C (1.3 - 0.4 as moles independent of E cell)
2 - D (Delta S total is proportional to E cell)
3 - A Can't remember which letter (changing conc of Mn2+ would alter E cell of the half equation)
4 - C (Fe2+ acts as a catalyst)
5 - C (EDTA leads to an increase in Entropy therefore more stable)
6 - C (equilibrium shifts to the right)
7 - A (CO2 would lower pH as it provides the H+)
8 - D (Cr was in ox states +3, +6, +2)
9 - D (hetero catalysts don't change oxidation state)
10 - D (ligand exchange when ammonia reacts with given complex)
11 - A (tertiary alcohol (CH3)2-C(OH)-CH3 will not be oxidised by dichromate)
12 - B (3 isomers of dibromobenzene)
13 - B (COO- and NH2 groups on the amino acid as it was in basic solution)
14 - D (COCl and NH2 groups to form the polyamide)
15 - B (had chiral centre but had only one COOH and NH2 group so was neutral)
16 - ??
17 - B (C3H8 from simple mole ratios)
18 - A (oxygen accepts pair of electrons in reduction mechanism of carbonyl)
19 - B (C-O bond broken in the acid as this was the only one which could be deduced from the question)
20 - C (CH2=CH2 requires electrophilic action whilst H- is a nucleophile)

All credit goes to marjunior for uploading the questions

Anyone remember question 16?
hi, is this all confirmed and agreed?
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Bord3r
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#2266
(Original post by TheNoobyPotato)
hi, is this all confirmed and agreed?
Yeah, I think everyone is in agreement with this.

Multiple Choice (Unofficial) Mark Scheme - FINAL

Explanation of question/answer in brackets

1 - C (1.3 - 0.4 as moles independent of E cell)
2 - D (Delta S total is proportional to E cell)
3 - A Can't remember which letter (changing conc of Mn2+ would alter E cell of the half equation)
4 - C (Fe2+ acts as a catalyst)
5 - C (EDTA leads to an increase in Entropy therefore more stable)
6 - C (equilibrium shifts to the right)
7 - A (CO2 would lower pH as it provides the H+)
8 - D (Cr was in ox states +3, +6, +2)
9 - D (hetero catalysts don't change oxidation state)
10 - D (ligand exchange when ammonia reacts with given complex)
11 - A (tertiary alcohol (CH3)2-C(OH)-CH3 will not be oxidised by dichromate)
12 - B (3 isomers of dibromobenzene)
13 - B (COO- and NH2 groups on the amino acid as it was in basic solution)
14 - D (COCl and NH2 groups to form the polyamide)
15 - B (had chiral centre but had only one COOH and NH2 group so was neutral)
16 - B (CCl4 is tetrahedral Cisplatin, Benzene and BF3 were all planar)
17 - B (C3H8 from simple mole ratios)
18 - A (oxygen accepts pair of electrons in reduction mechanism of carbonyl)
19 - B (C-O bond broken in the acid as this was the only one which could be deduced from the question)
20 - C (CH2=CH2 requires electrophilic action whilst H- is a nucleophile)

All credit goes to marjunior for uploading the questions
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dhirschowitz
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#2267
is there an unofficial mark scheme for section b and c?
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F1's Finest
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#2268
(Original post by Bord3r)
Yeah, I think everyone is in agreement with this.

Multiple Choice (Unofficial) Mark Scheme - FINAL

Explanation of question/answer in brackets

1 - C (1.3 - 0.4 as moles independent of E cell)
2 - D (Delta S total is proportional to E cell)
3 - A Can't remember which letter (changing conc of Mn2+ would alter E cell of the half equation)
4 - C (Fe2+ acts as a catalyst)
5 - C (EDTA leads to an increase in Entropy therefore more stable)
6 - C (equilibrium shifts to the right)
7 - A (CO2 would lower pH as it provides the H+)
8 - D (Cr was in ox states +3, +6, +2)
9 - D (hetero catalysts don't change oxidation state)
10 - D (ligand exchange when ammonia reacts with given complex)
11 - A (tertiary alcohol (CH3)2-C(OH)-CH3 will not be oxidised by dichromate)
12 - B (3 isomers of dibromobenzene)
13 - B (COO- and NH2 groups on the amino acid as it was in basic solution)
14 - D (COCl and NH2 groups to form the polyamide)
15 - B (had chiral centre but had only one COOH and NH2 group so was neutral)
16 - B (CCl4 is tetrahedral Cisplatin, Benzene and BF3 were all planar)
17 - B (C3H8 from simple mole ratios)
18 - A (oxygen accepts pair of electrons in reduction mechanism of carbonyl)
19 - B (C-O bond broken in the acid as this was the only one which could be deduced from the question)
20 - C (CH2=CH2 requires electrophilic action whilst H- is a nucleophile)

All credit goes to marjunior for uploading the questions
I would have thought that 18 is C

How comes it's A?
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Exon
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#2269
(Original post by James A)
I would have thought that 18 is C

How comes it's A?
Attachment 228463

It's not C. If the carbon atom accepts electrons from the methyl group, it become less positive, making it more difficult to add nucleophiles.
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710
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#2270
The mark scheme is out for this paper, but only for teachers, guys. Anyone have access to it, or can post it up??? Thanks.
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jojo1995
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(Original post by 710)
The mark scheme is out for this paper, but only for teachers, guys. Anyone have access to it, or can post it up??? Thanks.
It's too late to change anything now ... Reading the ms won't change anything so you might as well wait a couple days until results
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Gnome :)
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#2272
(Original post by jojo1995)
It's too late to change anything now ... Reading the ms won't change anything so you might as well wait a couple days until results
But... But... 23 whole days and my future may depend on the results of this exam!
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F1's Finest
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#2273
All Edexcel MS.

Quoted the most recent people on this thread.

(Original post by Bord3r)
x

(Original post by Gnome :))
x

(Original post by mar junior)
x

(Original post by Blob2491)
x

(Original post by TheNoobyPotato)
x

(Original post by AS01)
x

(Original post by oli_G)
x

(Original post by Exon)
x

(Original post by LeaX)
x


(Original post by 710)
x

(Original post by jojo1995)
x
http://api.viglink.com/api/click?for...13746817176506
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LeaX
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omg i have so many butterflies now, i managed to forget about this exam up until now haha
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Blob2491
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Thanks James, I'll +rep you when I can. I can't remember what I put for most q's so now I'm just feeling more anxious
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LeaX
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Thank you for posting, James.

I finally summoned up the courage to look at the mark scheme and I accidently opened up the wrong one and I had my answers to the mcq up and was going through them and I nearly had a heart attack as they were all wrong. So relieved when I realised lol.
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F1's Finest
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No worries folkes.
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1234lime
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#2278
So, any changes to grade boundary predictions now that the markscheme is out?
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AtomicMan
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#2279
(Original post by 1234lime)
So, any changes to grade boundary predictions now that the markscheme is out?
I think the paper was roughly the same difficulty as the last two years (slightly harder IMO), so roughly the same/lower grade boundaries?
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Bord3r
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#2280
I'm impressed we managed to get the unofficial multiple choice mark scheme to match the official one. Teamwork.
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