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    (Original post by uwotfam)
    just realised i forgot the key on the stem and leaf question fml. Would i drop only 1 mark for that?
    Same. I'm such a retard lol. 1 silly mark gone
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    (Original post by MovedMasterMike)
    Same. I'm such a retard lol. 1 silly mark gone
    Made the same mistake on the 2015 mock, ahhh this time i put the key in first before doing anything.

    Don't worry about it, everyone's bound to make silly mistakes, its very hard to avoid them. Especially under pressure of exams.
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    Do you lose a mark for failing to label the y axis .... "frequency density"?
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    (Original post by jacksparrow1111)
    Do you lose a mark for failing to label the y axis .... "frequency density"?
    Yep I would say so it's normally a mark for it, sorry💔


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    How many marks will i get for this:

    I had the working out as 5p^2-x=y
    But i put down y=x-5p^2, i know silly mistake!
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    (Original post by Malom)
    How many marks will i get for this:

    I had the working out as 5p^2-x=y
    But i put down y=x-5p^2, i know silly mistake!
    2 out of 3


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    How many marks will i get for these questions. Its driving me nuts just thinking about it.



    Pauls car question

    My answer:15000(1-23/100)^1=11500 <==first year
    1550(1-18/100)^2 = 7766.22 <=== 2 years added on

    1/2 of 15000 = 7500

    I then added the 7766.22 and 11500 by mistake.(4 mark question)


    Q.colins drive
    My answer:

    3.50x5 = £17.50
    18*5=90
    90*2=180
    180/45.2=3.982300885 - 2DP = 3.98
    1836.9*18.1488 = 2484.57072p

    p to £ x100 = £24.85

    I for got to add the £17.50 at the end(5Mark question)
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    (Original post by Malom)
    How many marks will i get for these questions. Its driving me nuts just thinking about it.



    Pauls car question

    My answer:15000(1-23/100)^1=11500 <==first year
    1550(1-18/100)^2 = 7766.22 <=== 2 years added on

    1/2 of 15000 = 7500

    I then added the 7766.22 and 11500 by mistake.(4 mark question)


    Q.colins drive
    My answer:

    3.50x5 = £17.50
    18*5=90
    90*2=180
    180/45.2=3.982300885 - 2DP = 3.98
    1836.9*18.1488 = 2484.57072p

    p to £ x100 = £24.85

    I for got to add the £17.50 at the end(5Mark question)
    For the first one marked harshly 2 and marked leniently 3 however I think you're likely to get 3?

    For the last one I think you got 4/5 because you only missed out one step.

    Can I quickly pm you?


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    (Original post by DamnDaniel2)
    For the first one marked harshly 2 and marked leniently 3 however I think you're likely to get 3?

    For the last one I think you got 4/5 because you only missed out one step.

    Can I quickly pm you?


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    Yeah sure
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    Here is the paper 2 GCSE June 2015 edexcel trial and improvement question:

    "The equation x3 – x2 = 30 has a solution between 3 and 4
    Use a trial and improvement method to find this solution.
    Give your answer correct to one decimal place.
    You must show ALL your working
    (Total for Question 2 is 4 marks)"

    And here is the official mark scheme:
    "B2 for a trial 3.4 ≤ x ≤ 3.5 evaluated correctly
    (B1 for a trial evaluated correctly for 3 ≤ x ≤ 4 )
    B1 for a different trial evaluated correctly for 3.45≤ x < 3.5
    B1 (dep on at least one previous B1) for 3.5
    [Note: Trials should be evaluated to at least accuracy shown in table, truncated or rounded]
    [NB No working scores 0 marks]"

    This is the table of solutions for the function and values that candidates may have used:
    x x3 – x2
    3.1 20.(181)
    3.2 22.(528)
    3.3 25.(047)
    3.4 27.(744)
    3.5 30.(625)
    3.6 33.(696)
    3.7 36.(963)
    3.8 40.(432)
    3.9 44(109)
    3.45 29.1(61125)
    3.46 29.4(50136)
    3.47 29.7(41023)
    3.48 30.0(33792)
    3.49 30.3(28449)

    To summarise, based on previous official markschemes,the mark scheme this year is likely to be as follows:
    B2 for correctly evaluated trial with 3.7 ≤ x ≤ 3.8
    B1 for different correctly evaluated trial with 3.75 ≤ x < 3.8
    B1 for 3.8

    The correct answer is 3.8, and if you have not been taught to use the halfway point (in this case 3.75) then you are being misinformed. As a year 11 teacher, I had a class of very able students, most of which obtained a A or B in their Feb mock (3 of them an A*) and I know they can look at the first point (worth B2) to decide the accurate value but I always emphasise that they must trial the midpoint. I'd be doing them a disservice if I didn't!
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    [QUOTE=GCSE DEMOLISHER;65690277]
    (Original post by Ikilliloot)
    Your actually wrong the answer is in fact, 3.7.

    Stop embarrassing yourself, it is a grade C question. When you put 3.7 into the equation, the answer is too low. When you put 3.8 into the equation, the answer is too high. When you put 3.75 into the equation, it is too low. This means that x is between 3.75 and 3.8. This means that no matter what number x is between 3.75 and 3.8, they will always round up to 3.8 to 1 decimal place. Stop answering back when you're not sure about the answer and learn from people who know the correct answer.
    Lol your deluded my friend, go on this past test paper, question 11 on this link.
    http://www.mathsgenie.co.uk/papers/2hjune2012ans.pdf

    The answer on this past test paper trial and improvement question is 4.6 wanna know why?
    4.7- 75.623-72 = 3.623
    4.6- 72-69.736 = 2.264

    If you take away you can see that 4.6 is closer, plus 4.65 is obviously closer to 4.7 then 4.6. See you dont need to do any fancy rounding stuff, you know it's 3.7 but you don't want to admit it, 3.7 is much closer to 34 than 3.8.
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    [QUOTE=Ikilliloot;65710221]
    (Original post by GCSE DEMOLISHER)

    Lol your deluded my friend, go on this past test paper, question 11 on this link.
    http://www.mathsgenie.co.uk/papers/2hjune2012ans.pdf

    The answer on this past test paper trial and improvement question is 4.6 wanna know why?
    4.7- 75.623-72 = 3.623
    4.6- 72-69.736 = 2.264

    If you take away you can see that 4.6 is closer, plus 4.65 is obviously closer to 4.7 then 4.6. See you dont need to do any fancy rounding stuff, you know it's 3.7 but you don't want to admit it, 3.7 is much closer to 34 than 3.8.
    In every single trial and improvement question you have to round up if the answer is closer to the original number and is at least half way. The answer is 38. Look on past exam questions.


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    [QUOTE=DamnDaniel2;65710307]
    (Original post by Ikilliloot)

    In every single trial and improvement question you have to round up if the answer is closer to the original number and is at least half way. The answer is 38. Look on past exam questions.


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    I meant 3.8


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    hiya will the grade boundaries go up or down?
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    (Original post by MissBdaviesMaths)
    Here is the paper 2 GCSE June 2015 edexcel trial and improvement question:

    "The equation x3 – x2 = 30 has a solution between 3 and 4
    Use a trial and improvement method to find this solution.
    Give your answer correct to one decimal place.
    You must show ALL your working
    (Total for Question 2 is 4 marks)"

    And here is the official mark scheme:
    "B2 for a trial 3.4 ≤ x ≤ 3.5 evaluated correctly
    (B1 for a trial evaluated correctly for 3 ≤ x ≤ 4 )
    B1 for a different trial evaluated correctly for 3.45≤ x < 3.5
    B1 (dep on at least one previous B1) for 3.5
    [Note: Trials should be evaluated to at least accuracy shown in table, truncated or rounded]
    [NB No working scores 0 marks]"

    This is the table of solutions for the function and values that candidates may have used:
    x x3 – x2
    3.1 20.(181)
    3.2 22.(528)
    3.3 25.(047)
    3.4 27.(744)
    3.5 30.(625)
    3.6 33.(696)
    3.7 36.(963)
    3.8 40.(432)
    3.9 44(109)
    3.45 29.1(61125)
    3.46 29.4(50136)
    3.47 29.7(41023)
    3.48 30.0(33792)
    3.49 30.3(28449)

    To summarise, based on previous official markschemes,the mark scheme this year is likely to be as follows:
    B2 for correctly evaluated trial with 3.7 ≤ x ≤ 3.8
    B1 for different correctly evaluated trial with 3.75 ≤ x < 3.8
    B1 for 3.8

    The correct answer is 3.8, and if you have not been taught to use the halfway point (in this case 3.75) then you are being misinformed. As a year 11 teacher, I had a class of very able students, most of which obtained a A or B in their Feb mock (3 of them an A*) and I know they can look at the first point (worth B2) to decide the accurate value but I always emphasise that they must trial the midpoint. I'd be doing them a disservice if I didn't!
    Do you think grade boundaries will be around 165? Or higher?


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    (Original post by MissBdaviesMaths)
    Here is the paper 2 GCSE June 2015 edexcel trial and improvement question:

    "The equation x3 – x2 = 30 has a solution between 3 and 4
    Use a trial and improvement method to find this solution.
    Give your answer correct to one decimal place.
    You must show ALL your working
    (Total for Question 2 is 4 marks)"

    And here is the official mark scheme:
    "B2 for a trial 3.4 ≤ x ≤ 3.5 evaluated correctly
    (B1 for a trial evaluated correctly for 3 ≤ x ≤ 4 )
    B1 for a different trial evaluated correctly for 3.45≤ x < 3.5
    B1 (dep on at least one previous B1) for 3.5
    [Note: Trials should be evaluated to at least accuracy shown in table, truncated or rounded]
    [NB No working scores 0 marks]"

    This is the table of solutions for the function and values that candidates may have used:
    x x3 – x2
    3.1 20.(181)
    3.2 22.(528)
    3.3 25.(047)
    3.4 27.(744)
    3.5 30.(625)
    3.6 33.(696)
    3.7 36.(963)
    3.8 40.(432)
    3.9 44(109)
    3.45 29.1(61125)
    3.46 29.4(50136)
    3.47 29.7(41023)
    3.48 30.0(33792)
    3.49 30.3(28449)

    To summarise, based on previous official markschemes,the mark scheme this year is likely to be as follows:
    B2 for correctly evaluated trial with 3.7 ≤ x ≤ 3.8
    B1 for different correctly evaluated trial with 3.75 ≤ x < 3.8
    B1 for 3.8

    The correct answer is 3.8, and if you have not been taught to use the halfway point (in this case 3.75) then you are being misinformed. As a year 11 teacher, I had a class of very able students, most of which obtained a A or B in their Feb mock (3 of them an A*) and I know they can look at the first point (worth B2) to decide the accurate value but I always emphasise that they must trial the midpoint. I'd be doing them a disservice if I didn't!
    For that june 2015 test paper i got it right, the answer is 3.5 because
    3.5- 30.625-30 = 0.625
    3.4- 30-27.744 = 2.256

    As you can see 3.5 is much more closer to 30 than 3.4 and i got the answer right.

    Also for this years non calculator questionnaire question 3 part c
    Can you say that it's kinda biased to ask students in a maths room about how much crisp they buy because it's better like to ask in a shop or supermarket how much crisp they buy?
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    (Original post by MissBdaviesMaths)
    Here is the paper 2 GCSE June 2015 edexcel trial and improvement question:

    "The equation x3 – x2 = 30 has a solution between 3 and 4
    Use a trial and improvement method to find this solution.
    Give your answer correct to one decimal place.
    You must show ALL your working
    (Total for Question 2 is 4 marks)"

    And here is the official mark scheme:
    "B2 for a trial 3.4 ≤ x ≤ 3.5 evaluated correctly
    (B1 for a trial evaluated correctly for 3 ≤ x ≤ 4 )
    B1 for a different trial evaluated correctly for 3.45≤ x < 3.5
    B1 (dep on at least one previous B1) for 3.5
    [Note: Trials should be evaluated to at least accuracy shown in table, truncated or rounded]
    [NB No working scores 0 marks]"

    This is the table of solutions for the function and values that candidates may have used:
    x x3 – x2
    3.1 20.(181)
    3.2 22.(528)
    3.3 25.(047)
    3.4 27.(744)
    3.5 30.(625)
    3.6 33.(696)
    3.7 36.(963)
    3.8 40.(432)
    3.9 44(109)
    3.45 29.1(61125)
    3.46 29.4(50136)
    3.47 29.7(41023)
    3.48 30.0(33792)
    3.49 30.3(28449)

    To summarise, based on previous official markschemes,the mark scheme this year is likely to be as follows:
    B2 for correctly evaluated trial with 3.7 ≤ x ≤ 3.8
    B1 for different correctly evaluated trial with 3.75 ≤ x < 3.8
    B1 for 3.8

    The correct answer is 3.8, and if you have not been taught to use the halfway point (in this case 3.75) then you are being misinformed. As a year 11 teacher, I had a class of very able students, most of which obtained a A or B in their Feb mock (3 of them an A*) and I know they can look at the first point (worth B2) to decide the accurate value but I always emphasise that they must trial the midpoint. I'd be doing them a disservice if I didn't!
    Also on question 3 (part a) non calc paper would you get a mark, if you put that 'often' was repeated 2 times in question and in the answer boxes?
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    I cannot believe how much time and space has been devoted to such a simple question (Trial and Improvement) and all over 1 mark. Thank God it's been taken off the specification for next year !!!
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    (Original post by DrPeter)
    I cannot believe how much time and space has been devoted to such a simple question (Trial and Improvement) and all over 1 mark. Thank God it's been taken off the specification for next year !!!
    I found the sample non calc for next year really hard!
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    Was this the 1MA1 or 1MA0 paper ?
 
 
 
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