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    (Original post by justinawe)
    du \not= dx

    Which is what you did in your substitution.
    (Original post by joostan)
    Beat me to it.
    Thanks
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    (Original post by reubenkinara)
    I see! :banghead::banghead::banghead::banghead::banghead:
    So glad this isn't the exam now!
    I highly doubt you'd get a question like that in the exam, anyway
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    (Original post by joostan)
    Well, that's how it goes
    Let's see . . .
    Got another problem for you.
    If \log_{10}2=x and \log_{10}3=y
    Express \log_5(36) in terms of x and y.
    Right so:

     \log_{5}36=\frac{\log_{10}36}{\l  og_{10}5}

     \log_{10}36={\log_{10}4}+{\log_{  10}9}={\log_{10}2^2}+{\log_{10}3  ^2}=2{\log_{10}2}+2{\log_{10}3}=  2x+2y

     \log_{10}5=\log_{10}10-\log_{10}2=1-x

    Therefore *drumroll* (This better be right!)  \log_{5}36=\frac{\log_{10}36}{\l  og_{10}5}=\frac{2x+2y}{1-x}
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    (Original post by justinawe)
    I highly doubt you'd get a question like that in the exam, anyway

    (Original post by reubenkinara)
    I see! :banghead::banghead::banghead::banghead::banghead:
    So glad this isn't the exam now!
    There were two previous parts in the book and a hence show that, but hey - who cares?
    (Original post by tigerz)
    Right so:

     \log_{5}36=\frac{\log_{10}36}{\l  og_{10}5}

     \log_{10}36={\log_{10}4}+{\log_{  10}9}={\log_{10}2^2}+{\log_{10}3  ^2}=2{\log_{10}2}+2{\log_{10}3}=  2x+2y

     \log_{10}5=\log_{10}10-\log_{10}2=1-x

    Therefore *drumroll* (This better be right!)  \log_{5}36=\frac{\log_{10}36}{\l  og_{10}5}=\frac{2x+2y}{1-x}
    Yep :congrats:
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    (Original post by justinawe)
    I highly doubt you'd get a question like that in the exam, anyway
    Perhaps not, however that mistake was worrying :sadnod::sadnod::sadnod::sadnod:
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    (Original post by joostan)
    There were two previous parts in the book and a hence show that, but hey - who cares?


    Yep :congrats:
    WOOOPPP! I hope there's a question like this tomorrow now :^_^:
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    (Original post by tigerz)
    WOOOPPP! I hope there's a question like this tomorrow now :^_^:
    Lol, you'll be one of the few who'll be able to do it
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    Anyone doing c2 tomorrow edexcel? any major tips for someone who is most likely to fail?!
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    75/75 on M4 June 2008!
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    (Original post by joostan)
    Lol, you'll be one of the few who'll be able to do it
    Haha, TSR taught meh logs LOOL :h: Thank youuuu for teaching \pi
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    Old but gold. :awesome:

    Spoiler:
    Show
    Show that every integer appears in the infinite sequence:

    \pm 1^{2}, \pm 1^{2} \pm 2^{2} , \pm 1^{2} \pm 2^{2} \pm 3^{2} , ...

    and appears so infinitely many times.
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    (Original post by dippers)
    Anyone doing c2 tomorrow edexcel? any major tips for someone who is most likely to fail?!
    Meeee, I'm sure you won't fail, I suggest you get some past papers done!

    here you gooo
    Attached Images
  1. File Type: pdf C2 Revision.pdf (260.1 KB, 42 views)
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    (Original post by tigerz)
    Haha, TSR taught meh logs LOOL :h: Thank youuuu for teaching \pi
    Es de nada.
    Anytime.
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    (Original post by Felix Felicis)
    Old but gold. :awesome:

    Spoiler:
    Show
    Show that every integer appears in the infinite sequence:

    \pm 1^{2}, \pm 1^{2} \pm 2^{2} , \pm 1^{2} \pm 2^{2} \pm 3^{2} , ...

    and appears so infinitely many times.
    I might be underthinking this but...

    Spoiler:
    Show


    surely as the series is infinite, you can just take as many  1^2 as required (With infinitely many ways of choosing these) to make your integer, and then use the plus or minus signs to make everything else cancel out as the series is infinite?

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    (Original post by DJMayes)
    I might be underthinking this but...

    Spoiler:
    Show


    surely as the series is infinite, you can just take as many  1^2 as required (With infinitely many ways of choosing these) to make your integer, and then use the plus or minus signs to make everything else cancel out as the series is infinite?

    Notice the discreet commas, it's a sequence rather than a series Each term in the sequence only has 1 \pm 1^{2}
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    (Original post by DJMayes)
    I might be underthinking this but...

    Spoiler:
    Show


    surely as the series is infinite, you can just take as many  1^2 as required (With infinitely many ways of choosing these) to make your integer, and then use the plus or minus signs to make everything else cancel out as the series is infinite?

    We're looking at the sequence, not the series, as I understand it.

    EDIT: Gah, this is what happens when you preview your posts before posting. You end up being the second poster to everything!
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    (Original post by joostan)
    Es de nada.
    Anytime.
    Haha
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    (Original post by Felix Felicis)
    Notice the discreet commas, it's a sequence rather than a series Each term in the sequence only has 1 \pm 1^{2}
    Ah, possibly should've read that. :lol:
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    (Original post by Scientific Eye)
    We're looking at the sequence, not the series, as I understand it.

    EDIT: Gah, this is what happens when you preview your posts before posting. You end up being the second poster to everything!
    Post and edit ftw
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    5cosθ − 2sinθ = 0,

    prove tanx = 2.5
 
 
 
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