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    (Original post by iPixelBlue)
    Since mathhelper does not have all the past papers eg. 2005, does anyone know where I can find them?
    I've tried looking for them before but I can't find them


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    (Original post by physicsmaths)
    I've tried looking for them before but I can't find them


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    i read somewhere on a similar thread that some people have got hold of them. i wish i did too.
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    Everyone ready for mat??????????????????


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    (Original post by physicsmaths)
    Everyone ready for mat??????????????????


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    Not in the slightest way possible. Going terribly. How about you?
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    Does anyone understand the solution to the 2009 paper, 1D? i dont get it.
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    (Original post by Icicle Man)
    Not in the slightest way possible. Going terribly. How about you?
    I'm scared as it could go really well or really bad.... Depends on quest 5....


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    (Original post by AwesomeSauce#1)
    Does anyone understand the solution to the 2009 paper, 1D? i dont get it.
    The addition of the terms gives the sequence, 1, -1, 2, -2, 3, -3...

    1-2 = -1
    -1+3 = 2
    2-4 = -2
    .
    .
    .

    Notice that when when n=2k (where k is a positive integer) the series is equal to -n/2 so when n=200 the series will equal -100. Therefore when n=199 the series will equal 100.
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    (Original post by SherlockHolmes)
    The addition of the terms gives the sequence, 1, -1, 2, -2, 3, -3...

    1-2 = -1
    -1+3 = 2
    2-4 = -2
    .
    .
    .

    Notice that when when n=2k (where k is a positive integer) the series is equal to -n/2 so when n=200 the series will equal -100. Therefore when n=199 the series will equal 100.
    thanks very much, i get it now. i spent too much time trying to understand the whole 1, -1, 2, -2, 3, -3... sequence, when i was already given it.
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    I hate this paper.
    Just did 2011 and got 1/10 on MC....
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    ughghm, i have one more question in regard to the solution of 2009 paper, 1i.

    Name:  Untitled.png
Views: 113
Size:  27.3 KB

    for the part highlighted in red, why is it that n=10 or n=-15 instead of the other possibility that n=-10 or n=15

    nvm, i figured it out lol.
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    If anyone can help with Specimen Paper A, Q 4 part ii, I don't understand how they've jumped from:

    Area (AQR) = 1/2 AQ . AR sin alpha
    to
    AQ/c x AR/b x Area (ABC)

    in the solutions here: http://www.maths.ox.ac.uk/system/fil...solutionsa.pdf

    I get that I'm trying to re-write the areas of the three small triangles in terms of the whole thing, but I don't understand this line?
    Thanks.
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    (Original post by Theaetetus)
    If anyone can help with Specimen Paper A, Q 4 part ii, I don't understand how they've jumped from:

    Area (AQR) = 1/2 AQ . AR sin alpha
    to
    AQ/c x AR/b x Area (ABC)

    in the solutions here: http://www.maths.ox.ac.uk/system/fil...solutionsa.pdf

    I get that I'm trying to re-write the areas of the three small triangles in terms of the whole thing, but I don't understand this line?
    Thanks.
    Go a few lines up in the solution where Area(ABC) and sin alpha are in an equation together.
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    does anyone understand the solution to MAT 2009 Q2) iv ? i cant seem to get how they got 1 + ( (n-1)/2 ) * ( 4 + 2n ) using the AP formula.
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    (Original post by RichE)
    Go a few lines up in the solution where Area(ABC) and sin alpha are in an equation together.
    Thank you, that was kind of simple after all. Still probably wouldn't have thought of it by myself, but that makes complete sense reading through.
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    (Original post by AwesomeSauce#1)
    does anyone understand the solution to MAT 2009 Q2) iv ? i cant seem to get how they got 1 + ( (n-1)/2 ) * ( 4 + 2n ) using the AP formula.
    What do you get when you apply the AP sum?

    There is a formula used here

    sum of AP = n/2 * (a+l)

    where n is number of terms, a is first term, l is last, which is used here.
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    (Original post by RichE)
    What do you get when you apply the AP sum?

    There is a formula used here

    sum of AP = n/2 * (a+l)

    where n is number of terms, a is first term, l is last, which is used here.
    thank you so much, i completely forgot about that formula.
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    22 to 117 pages in a day WOW
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    (Original post by arun96)
    22 to 117 pages in a day WOW
    I think you're on the wrong thread. I think you're talking about Oxford MAT test 2014.
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    LOL **** wrong thread thats embarrasing
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    Does anyone have a copy of the MAT paper that they can upload?

    I didn't sit the paper but I am interested in trying it. Are people allowed to discuss it/upload stuff yet?
 
 
 
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