Oxford MAT 2013/2014

Since mathhelper does not have all the past papers eg. 2005, does anyone know where I can find them?

I've tried looking for them before but I can't find them


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Everyone ready for mat??????????????????


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Not in the slightest way possible. Going terribly. How about you?

Does anyone understand the solution to the 2009 paper, 1D? i dont get it.

The addition of the terms gives the sequence, 1, -1, 2, -2, 3, -3...

1-2 = -1
-1+3 = 2
2-4 = -2
.
.
.

Notice that when when n=2k (where k is a positive integer) the series is equal to -n/2 so when n=200 the series will equal -100. Therefore when n=199 the series will equal 100.

If anyone can help with Specimen Paper A, Q 4 part ii, I don't understand how they've jumped from:

Area (AQR) = 1/2 AQ . AR sin alpha
to
AQ/c x AR/b x Area (ABC)

in the solutions here: http://www.maths.ox.ac.uk/system/files/attachments/solutionsa.pdf

I get that I'm trying to re-write the areas of the three small triangles in terms of the whole thing, but I don't understand this line?
Thanks.

Go a few lines up in the solution where Area(ABC) and sin alpha are in an equation together.

does anyone understand the solution to MAT 2009 Q2) iv ? i cant seem to get how they got 1 + ( (n-1)/2 ) * ( 4 + 2n ) using the AP formula.

What do you get when you apply the AP sum?

There is a formula used here

sum of AP = n/2 * (a+l)

where n is number of terms, a is first term, l is last, which is used here.

22 to 117 pages in a day WOW