Edexcel A2 C3 Mathematics 12th June 2015 Watch

This discussion is closed.
BFP=big fat poo
Badges: 2
Rep:
?
#2321
Report 3 years ago
#2321
(Original post by Johann von Gauss)
Not everyone can be handed out a pass... you're not entitled to a pass
Ha, i'm not asking for a pass, but when i do past papers all effing year with mostly all A* grades, well i'm understandably pissed off. They dole out this sh**e to us, and then expect to us to do it when past papers are fricking easy. So no i wasn't expecting an easy paper, but i don't think anyone expected this paper....
2
Chazley123
Badges: 2
Rep:
?
#2322
Report 3 years ago
#2322
(Original post by xKay)
I got 1 over square root of p squared + 1
tan = sin / cos
therefor cos = sin/tan so sin/p
1
sj97
Badges: 3
Rep:
?
#2323
Report 3 years ago
#2323
(Original post by Neilg99)
The range was -4 and 2.5
Wasn't the range for g supposed to have an e value in it?
0
studentwiz
Badges: 3
Rep:
?
#2324
Report 3 years ago
#2324
WHAT THE **** WAS THAT PROOF


Posted from TSR Mobile
0
Neilg99
Badges: 2
Rep:
?
#2325
Report 3 years ago
#2325
(Original post by xKay)
I got 1 over square root of p squared + 1
Correct
0
12345678zzz
Badges: 2
Rep:
?
#2326
Report 3 years ago
#2326
can someone make a difficulty poll on this?
0
Jemy
Badges: 11
Rep:
?
#2327
Report 3 years ago
#2327
(Original post by moment of truth)
Was harder than June 2013 (imo) and those grade boundaries were ridiculously low, so these should be quite similar (hopefully!) Still annoyed at the paper, but there is nothing we can do now. Look forward to the next paper instead

Posted from TSR Mobile
(Original post by BFP=big fat poo)
Ha, i'm not asking for a pass, but when i do past papers all effing year with mostly all A* grades, well i'm understandably pissed off. They dole out this sh**e to us, and then expect to us to do it when past papers are fricking easy. So no i wasn't expecting an easy paper, but i don't think anyone expected this paper....
Brace yourselves for C4....
0
STATER
Badges: 3
#2328
Report 3 years ago
#2328
(Original post by sj97)
Wasn't the range for g supposed to have an e value in it?
Youre right. It was 1/8e and something else e.
1
Chazley123
Badges: 2
Rep:
?
#2329
Report 3 years ago
#2329
(Original post by studentwiz)
What was the values of k


Posted from TSR Mobile
k < -2root5 k > 2root5
0
jf1994
Badges: 15
Rep:
?
#2330
Report 3 years ago
#2330
Did anyone else get that there was no asymptote for the second transformation graph? plz plz plz
0
MCMXCVIII
Badges: 6
Rep:
?
#2331
Report 3 years ago
#2331
What did you do for the trig proof and is an unofficial mark scheme out yet?


Posted from TSR Mobile
0
RThornton
Badges: 4
Rep:
?
#2332
Report 3 years ago
#2332
(Original post by Chazley123)
tan = sin / cos
therefor cos = sin/tan so sin/p
Yeah, then you have to use sin^2x + cos^2x = 1, to get rid of the sin
0
mahatma ghandi
Badges: 1
Rep:
?
#2333
Report 3 years ago
#2333
****
0
taichingkan
Badges: 2
Rep:
?
#2334
Report 3 years ago
#2334
Was it an increasing or decreasing function?
0
emu_neutrino
Badges: 10
Rep:
?
#2335
Report 3 years ago
#2335
(Original post by Chazley123)
how did everyone find it?
I found it alright actually at first the trig proof and the range question had me like WHAT but i got there in the end. I think i probably made one or two stupid mistakes though, like i realised that the gradient on the last q was positive but said that it was a decreasing function for some reason how about you?
0
PaulCJH
Badges: 1
Rep:
?
#2336
Report 3 years ago
#2336
My Answers:
1. 2p/(1-p^2), 1/((p^2+1)^1/2), (1+p)/(p-1)
2. x> or equal to ln5/2, Solutions: ln3/2, ln7/2.
3. 26.57, 2 root 5, 51.8 and -25.3, k<2 root 5 and k>2 root 5
4. 20, ln2/40, 93
5. 4pi^2, 1/3pi
7. -4e^-4<g(x)<1/(8e)
8. 2.820, 5.962,
9. increasing, -3k/(x-2k)^2

Some might be wrong please bear that in mind.
6
sj97
Badges: 3
Rep:
?
#2337
Report 3 years ago
#2337
(Original post by jf1994)
Did anyone else get that there was no asymptote for the second transformation graph? plz plz plz
No, I got y=-5 for the first one and y=5 for the second one? Messed up on the modulus questions though. Got something like x = 5/2.
0
phoenixsilver
Badges: 3
Rep:
?
#2338
Report 3 years ago
#2338
Why are people getting values with e in them for the range of g(x)?
The only hard questions in this paper was the trig prove one and (although easier) the range one.

I don't understand why people are getting e values for the range though.
The question gave the domain of g(x), so this must be equal to the range of the inverse function. I equated this to inverse g(x), getting a quadratic with x taken out of it.
How do you get e values..?
0
MelonKuma
Badges: 8
Rep:
?
#2339
Report 3 years ago
#2339
(Original post by Chazley123)
k < -2root5 k > 2root5
Yes i got that wooop

The paper wasn't too bad.
It was just tricky and long. Like 9 questions is a lot...

I couldn't answer 1b) cosx in terms of tan
And 8a) The proving ahhh.
I got up to 1 + Sin 2A divided by Cos 2A and didn't know that you had to equate the 1 to sin^a+cos^2a apparently.

Hopefully I can get an A* still.
0
mahatma ghandi
Badges: 1
Rep:
?
#2340
Report 3 years ago
#2340
(Original post by taichingkan)
Was it an increasing or decreasing function?
increasing you mug
1
X
new posts
Latest
My Feed

See more of what you like on
The Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

Personalise

University open days

  • Cardiff Metropolitan University
    Undergraduate Open Day - Llandaff Campus Undergraduate
    Sat, 27 Apr '19
  • University of East Anglia
    Could you inspire the next generation? Find out more about becoming a Primary teacher with UEA… Postgraduate
    Sat, 27 Apr '19
  • Anglia Ruskin University
    Health, Education, Medicine and Social Care; Arts, Humanities and Social Sciences; Business and Law; Science and Engineering Undergraduate
    Sat, 27 Apr '19

Have you registered to vote?

Yes! (502)
37.8%
No - but I will (102)
7.68%
No - I don't want to (91)
6.85%
No - I can't vote (<18, not in UK, etc) (633)
47.67%

Watched Threads

View All
Latest
My Feed

See more of what you like on
The Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

Personalise