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Higher Maths :: Post-Exam Discussion :: 2010 :: Did you make it out alive? watch

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  • View Poll Results: How did you find it?
    Very hard. Thank god for appeals/resits!
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    Not too sure, and I don't want to think about it. :indiff:
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    Very easy! :thumbsup:
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    If, in paper two, I wrote one of the vector components wrong and I do parts b and c WITH those components, will I lose all the marks? Such a stupid mistake aswell.. (it's the first question of paper 2)
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    btw i forgot to put my calculator into radian mode for question 4 on paper 2. My teachher says if i have the right answer in degrees i'll only lose 1 mark, is that right?

    And did anyone else forget about radian mode!>
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    Yeah you'll lose a mark for that... I remembered as soon as I started the enext question so thank God!
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    (Original post by RizzyI)
    If, in paper two, I wrote one of the vector components wrong and I do parts b and c WITH those components, will I lose all the marks? Such a stupid mistake aswell.. (it's the first question of paper 2)
    no since it would be a carry on mistake so you still get the marks after that point as long as working is right afterwards though you'll probably lose a mark for the initial mistake.
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    Think I've lost about 8/9 marks in Paper 2, 6 marks in MC and 3 marks in Part B of paper 1. So something around 112 out of 130? Better than I though
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    (Original post by roar558)
    no since it would be a carry on mistake so you still get the marks after that point as long as working is right afterwards though you'll probably lose a mark for the initial mistake.
    Yeah that's what I thought but I wasn't sure. Thanks!
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    See for q 7)a)

    I did:

    log4x=p
    x=4^p

    log16 4^p

    p log16 4
    since log16 4 = 1/2, the answer is 0.5xp= 1/2P Is this valid?

    See for Q6)a) which asked to show that the equation of the tangent is y=1/3x, how many marks out of 5 do you think will be awarded for only proving the gradient is 1/3 at that point?
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    anyone got the solutions to paper 1 section b
    did anyone else get in 23b sinb = 3/5 and cosb = 4/5
    I think I have got a B
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    On a (completely) different topic, if you go to the Google homepage you can play Pacman!!!! Celebrating it's birthday or something. Pity it had to be on the maths exam :/
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    (Original post by alanainatizzy)
    I'm the same as most on here actually. Paper one was fairly straightforward, whereas paper 2 was :eek:
    Hopefully i'll get an A, that would be nice, but more likely a B.

    Did anyone write it all in pencil? I did and I saw a lot of people at my school did too, but I'm getting worried now that I think about it. :confused:
    Everyone at my school writes in pencil, we've never been told we have to write in pen even though it does say that on the front of the booklet. I don't think it should matter as long as your writing is legible, don't worry about it
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    (Original post by RizzyI)
    If, in paper two, I wrote one of the vector components wrong and I do parts b and c WITH those components, will I lose all the marks? Such a stupid mistake aswell.. (it's the first question of paper 2)
    no don't worry you will only lose the mark allocated for that vector - I made the same mistake and I did this in the prelim too but I only lost 1 mark for that incorrect vector and got theh rest of the marks
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    for paper 2 question 2.b) i think i got confused and put the answer to b(ii) in b(i) and vice versa. I checked and got the right answers but put them in the wrong place will i get no marks for this?
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    do you think if i managed to get an A (fingers tightly crossed) i would be able to give AH a bash even though i had a tutor?
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    (Original post by stefany-a)
    anyone got the solutions to paper 1 section b
    did anyone else get in 23b sinb = 3/5 and cosb = 4/5
    I think I have got a B

    I got 23b sinb = 3/5 and cosb = 4/5 as well
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    do you think if i managed to get an A (fingers tightly crossed) i would be able to give AH a bash even though i had a tutor?:confused:
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    See for q 7)a)

    I did:

    log4x=p
    x=4^p

    log16 4^p

    p log16 4
    since log16 4 = 1/2, the answer is 0.5xp= 1/2P Is this valid?

    See for Q6)a) which asked to show that the equation of the tangent is y=1/3x, how many marks out of 5 do you think will be awarded for only proving the gradient is 1/3 at that point?
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    See for q 7)a)

    I did:

    log4x=p
    x=4^p

    log16 4^p

    p log16 4
    since log16 4 = 1/2, the answer is 0.5xp= 1/2P Is this valid?

    See for Q6)a) which asked to show that the equation of the tangent is y=1/3x, how many marks out of 5 do you think will be awarded for only proving the gradient is 1/3 at that point?
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    (Original post by stefany-a)
    anyone got the solutions to paper 1 section b
    did anyone else get in 23b sinb = 3/5 and cosb = 4/5
    I think I have got a B
    Yeah I think that's what I got for sinb and cosb.
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    (Original post by garlicbreadman)
    See for q 7)a)

    I did:

    log4x=p
    x=4^p

    log16 4^p

    p log16 4
    since log16 4 = 1/2, the answer is 0.5xp= 1/2P Is this valid?

    See for Q6)a) which asked to show that the equation of the tangent is y=1/3x, how many marks out of 5 do you think will be awarded for only proving the gradient is 1/3 at that point?

    I think I did the same for 7 a) so hopefully it is an acceptable method
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    (Original post by T24)
    Yeah I think that's what I got for sinb and cosb.
    See for q 7)a)

    I did:

    log4x=p
    x=4^p

    log16 4^p

    p log16 4 ................log16 4 = 1/2
    since log16 4 = 1/2, the answer is 0.5p=1/2P Is this valid?

    See for Q6)a) which asked to show that the equation of the tangent is y=1/3x, how many marks out of 5 do you think will be awarded for only proving the gradient is 1/3 at that point?
 
 
 

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