Hey there! Sign in to join this conversationNew here? Join for free
    Offline

    0
    ReputationRep:
    Do you reckon I would have lost a mark for putting pos/neg in that rearranging question when r>0?
    Offline

    0
    ReputationRep:
    I think you would because it said r>0
    Offline

    0
    ReputationRep:
    Siriuspudh- I think you may do sire. Just start praying for c2 now. not much you can do
    Offline

    0
    ReputationRep:
    (Original post by siriuspudh)
    Do you reckon I would have lost a mark for putting pos/neg in that rearranging question when r>0?
    Unfortunately, I think you will suffer a 1 mark deduction. I think this question caught me out too. None of the past papers have something like "x>0 or t>0" so this caught me out. Oh well. Hopefully, this was the one of the only marks I lost.
    Offline

    0
    ReputationRep:
    My answers were as follows:
    1. y=-0.5x+3
    2.(0.7,0.1)
    3.i) 25 ii)8a^9
    4. r=squareroot 3V/pi(a+b)
    5. k=3
    6. -2560x^3
    7.i)5^3.5 ii)8+11root5
    8. 3(x-2)^2 -7 and minimum y value was -7
    9i) 3n ii) 3n^2 + 2 and then i did a bit of waffling
    10i). radius= 2root5 and centre (3,2)
    ii) y values 2+_root11 and x values were -1 and 7
    iii) midpoint AB (4,5) and distance of chord thingy was root10
    11i) draw graph
    ii) -2,0, 7/2
    iii) (2x+9)(x+1)(x-1)
    12i) points of intersection were (-1.6,-0.3) and (2.1,7.2)
    12 ii)1+_root57/4
    iii) 0 = x^2 -2k(x+1) +1 when i equated the two lines and my k value was completly wrong though i did write b^2-4ac=0 in the last part which should give me a mark.
    so overall would you say these answers are correct apart from the last part of 12 and 7ii ?

    Any help would be appreciated
    Offline

    0
    ReputationRep:
    (Original post by krishparscrotam)
    My answers were as follows:
    1. y=-0.5x+3
    2.(0.7,0.1)
    3.i) 25 ii)8a^9
    4. r=squareroot 3V/pi(a+b)
    5. k=3
    6. -2560x^3
    7.i)5^3.5 ii)8+11root5
    8. 3(x-2)^2 -7 and minimum y value was -7
    9i) 3n ii) 3n^2 + 2 and then i did a bit of waffling
    10i). radius= 2root5 and centre (3,2)
    ii) y values 2+_root11 and x values were -1 and 7
    iii) midpoint AB (4,5) and distance of chord thingy was root10
    11i) draw graph
    ii) -2,0, 7/2
    iii) (2x+9)(x+1)(x-1)
    12i) points of intersection were (-1.6,-0.3) and (2.1,7.2)
    12 ii)1+_root57/4
    iii) 0 = x^2 -2k(x+1) +1 when i equated the two lines and my k value was completly wrong though i did write b^2-4ac=0 in the last part which should give me a mark.
    so overall would you say these answers are correct apart from the last part of 12 and 7ii ?

    Any help would be appreciated
    Hi,

    I got the same answers as you except for 7ii and 12iii.

    Can you remember the question for 12ii)?

    Thank you.
    Offline

    0
    ReputationRep:
    (Original post by thisisjokes)
    I did exactly this and for some reason didn't see that 1/0.04=25.
    Really hope I don't lose a mark for it
    yeah i didnt see that either hopefully its fine
    Offline

    3
    ReputationRep:
    hey guys for question 4 I got:
    r = ((3V/(a+b))/pi)^1/2

    Is this correct?
    original equation was 1/3(r^2)pi(a+b) = V

    slowly finding out i got more and more wrong.
    Offline

    0
    ReputationRep:
    (Original post by Deceived)
    Hi,

    I got the same answers as you except for 7ii and 12iii.

    Can you remember the question for 12ii)?

    Thank you.
    The question to 12ii) was when you had to equate 1/(x-2) and y=2x+3 to give the quadratic then solve to find points of intersection I think :/
    Offline

    0
    ReputationRep:
    (Original post by Dr.Monstaa)
    The question to 12ii) was when you had to equate 1/(x-2) and y=2x+3 to give the quadratic then solve to find points of intersection I think :/
    Oh yeah, I remember now. Thanks.

    This is what I got:

    2x+3=1/(x-2)

    (2x+3)(x-2)=1

    2x2+3x-4x-6=1

    2x2-x-7=0

    x2-(1/2*x)-(7/2)=0

    (x-1/4)2-(1/16)-(56/16)=0

    (x-1/4)2=57/16

    x-1/4=±√57/4

    x=1/4±√57/4

    x=(1±√57)/4

    So yeah, I got a different answer.
    Offline

    3
    ReputationRep:
    you got the same answer.....
    Offline

    11
    ReputationRep:
    I felt so happy after the exam,now I feel very nervous - I hope the grade boundary is like 56 for an A because I'm assured ill at least get a B worse comes to worst - I'm hoping I've got at least 60 out of 72 though - going to have to do 3 core 2 past papers a day if I want to be prepared for Friday


    Posted from TSR Mobile
    Offline

    15
    ReputationRep:
    (Original post by krishparscrotam)
    My answers were as follows:
    1. y=-0.5x+3
    2.(0.7,0.1)
    3.i) 25 ii)8a^9
    4. r=squareroot 3V/pi(a+b)
    5. k=3
    6. -2560x^3
    7.i)5^3.5 ii)8+11root5
    8. 3(x-2)^2 -7 and minimum y value was -7
    9i) 3n ii) 3n^2 + 2 and then i did a bit of waffling
    10i). radius= 2root5 and centre (3,2)
    ii) y values 2+_root11 and x values were -1 and 7
    iii) midpoint AB (4,5) and distance of chord thingy was root10
    11i) draw graph
    ii) -2,0, 7/2
    iii) (2x+9)(x+1)(x-1)
    12i) points of intersection were (-1.6,-0.3) and (2.1,7.2)
    12 ii)1+_root57/4
    iii) 0 = x^2 -2k(x+1) +1 when i equated the two lines and my k value was completly wrong though i did write b^2-4ac=0 in the last part which should give me a mark.
    so overall would you say these answers are correct apart from the last part of 12 and 7ii ?

    Any help would be appreciated
    Not sure about your answer for question 1 and 7ii is wrong for sure. the last part of question 12 was k= 0 or 4 (unfortunately only put 4) given 2 more minutes i would've got the 0
    Offline

    0
    ReputationRep:
    (Original post by TheNote)
    you got the same answer.....
    How did we?

    1
    ±√57/4 ≠ (1±√57)/4

    Brackets make all the difference.
    Offline

    1
    ReputationRep:
    (Original post by Pjmckenna96)
    Does anyone know of an unofficial mark scheme available online?
    there probably wont be one cos it is mei
    Offline

    0
    ReputationRep:
    (Original post by krishkmistry)
    I felt so happy after the exam,now I feel very nervous - I hope the grade boundary is like 56 for an A because I'm assured ill at least get a B worse comes to worst - I'm hoping I've got at least 60 out of 72 though - going to have to do 3 core 2 past papers a day if I want to be prepared for Friday


    Posted from TSR Mobile
    Feeling exactly the same. Wish I never came on this forum haha. I know I've dropped at least 1 mark from the ± mistake on the re-arranging question. Other than that I think I'm fine. Hopefully, I didn't make many stupid mistakes in the exam. Good luck with C2. I've done all the past papers and therefore don't have much revision material left haha.
    Offline

    3
    ReputationRep:
    (Original post by Deceived)
    How did we?

    1
    ±√57/4 ≠ (1±√57)/4

    Brackets make all the difference.
    i am assuming he meant brackets due to a typo
    Offline

    1
    ReputationRep:
    does anybody the last question? We can go through it and figure out the 'actual answer.'
    See if it is 4/0 or the other one
    Offline

    0
    ReputationRep:
    (Original post by TheNote)
    i am assuming he meant brackets due to a typo
    Thanks for clearing that up.
    Offline

    0
    ReputationRep:
    On the last part of 12 I tried to differentiate the (x-2)^-2 (C3/C2 differentiation), make dy/dx=-1 (because y=-x+k) then tried to find k from that. I ended up with -4/3 and -16/5 or something.. lots of room for error with that so not that confident with those...
 
 
 
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • Poll
    Brussels sprouts
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

    Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

    Quick reply
    Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.