# Edexcel FP2 June 2015 - Official ThreadWatch

3 years ago
#221
(Original post by simonli2575)
I was kinda disappointed that it wasn't very hard.
Anyway, here're my answers.
Spoiler:
Show
1.
-6<x<3 or x>1
x>1

2.
4
2pi/3
4096
+-sqrt(8) & +-sqrt(8)i

3.
3cot(x)-2cos^2(x)cot(x)+Ccosec(x)

5.
(-0.8,0) r=1.2
inside the circle

6.
(4.5a,pi/3)
a^2(9pi/4+81sqrt(3)/16

7.
Coefficients:
3, 8sqrt(3), 40, 176sqrt(3)

8.
x^4(A+Blnx)+1/8lnx+1/16

In the first one I got the same, but minus 3
so -6<x<-3 or x>1
x>1

And in 7 one of the coefficients is 176sqrt(3)/3
because I think 352sqrt3 for the derivative and then you have to divide by 3!=6
1
reply
3 years ago
#222
I'm pretty sure the region is outside the circle
0
reply
3 years ago
#223
(Original post by simonli2575)
I was kinda disappointed that it wasn't very hard.
Anyway, here're my answers.
Spoiler:
Show
1.
-6<x<3 or x>1
x>1

2.
4
2pi/3
4096
+-sqrt(8) & +-sqrt(8)i

3.
3cot(x)-2cos^2(x)cot(x)+Ccosec(x)

5.
(-0.8,0) r=1.2
inside the circle

6.
(4.5a,pi/3)
a^2(9pi/4+81sqrt(3)/16

7.
Coefficients:
3, 8sqrt(3), 40, 176sqrt(3)

8.
x^4(A+Blnx)+1/8lnx+1/16
I didnt get the same for question 3.
0
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3 years ago
#224
0
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3 years ago
#225

Can't remember the order but my answers
0
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3 years ago
#226
(Original post by jelo)
I didnt get the same for question 3.
I got 1.5sin2x + cotx (cosx)^2 + c cosecx
0
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3 years ago
#227
(Original post by jelo)
I didnt get the same for question 3.
Probably different format.
Was your integral factor sinx?
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3 years ago
#228
(Original post by PandaJules)
In the first one I got the same, but minus 3
so -6<x<-3 or x>1
x>1

And in 7 one of the coefficients is 176sqrt(3)/3
because I think 352sqrt3 for the derivative and then you have to divide by 3!=6
Whoops, I typed in the answer incorrectly.
0
reply
3 years ago
#229
(Original post by DoctorDren)
I'm pretty sure the region is outside the circle
I got inside.

z = 3iw/(1-w)

|z| <= 2

|3iw/(1-w)| <= 2
|3iw| <= 2|1-w|
3|w| <= 2 |-1| |w-1|
3|w| <= 2|w-1|

9(u^2 + v^2) <= 4(u-1)^2 + 4v^2
9u^2 + 9v^2 <= 4u^2 - 8u + 4 + 4v^2
5u^2 + 8u + 5v^2 <= 4

Therefore, shade inside the circle.
Is anything there wrong?
0
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3 years ago
#230
How many marks will i
Lose for putting (0,4/5) instead of (-4/5,0)

Posted from TSR Mobile
0
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3 years ago
#231
The only thing i got wrong is a term in the taylor series (last term) how many marks would i lose?

Posted from TSR Mobile
0
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3 years ago
#232
I am going for my morning walk ...

based on the first few votes and the comments amongst reputable users of this site it looks that this FP2 boundaries are going to be the highest ever!!

Keep voting at

http://www.thestudentroom.co.uk/show....php?t=3376607
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3 years ago
#233
(Original post by simonli2575)
Probably different format.
Was your integral factor sinx?
Yeah, sorry, that is correct
0
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3 years ago
#234
(Original post by simonli2575)
I was kinda disappointed that it wasn't very hard.
Anyway, here're my answers.
Spoiler:
Show
1.
-6<x<-3 or x>1
x>1

2.
4
2pi/3
4096
+-sqrt(8) & +-sqrt(8)i

3.
3cot(x)-2cos^2(x)cot(x)+Ccosec(x)

5.
(-0.8,0) r=1.2
inside the circle

6.
(4.5a,pi/3)
a^2(9pi/4+81sqrt(3)/16

7.
Coefficients:
3, 8sqrt(3), 40, 176sqrt(3)/3

8.
x^4(A+Blnx)+1/8lnx+1/16
That's what I got!
0
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3 years ago
#235

Anyone care to check my answer to 3?
0
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3 years ago
#236
Thought i'd done ok till i came on here. messed up q1 and the last part of 7. that's all i can remember, how do you guys know all your answers?
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3 years ago
#237
(Original post by mrno1324)
I got 1.5sin2x + cotx (cosx)^2 + c cosecx
I got the same answer. Is this correct? I'm seeing other people with completely different answers
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3 years ago
#238
Did anyone else use factor formulae for the differential equation in Q3 ( i think)
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3 years ago
#239
yes the integral was sinx, where pretty much a lot of my friends and other people said they got stuck in integrating cos2xsinx, you would use the cos2x expansion integrating after should get you

y= cot (x) - (2/3) cos^2(x) cot (x) + Ccosec(x)
0
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3 years ago
#240
Where can I find the questions guys? Has it been uploaded anywhere?
Your help is much appreciated.
0
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