what do you mean? this was random's answer and that was what I put.(Original post by Ewanclementson)
Having checked the answer you agreed with for Q5, I do disagree. The centre of mass was a distance of root(10)/2 from the pivot.
m(2a)+m(a)=2mx leads to x=1.5a then the centre of mass was 1.5a below L and by symmetry, 0.5a from l which gives root(10)/2.
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Official M5 Edexcel Thread June 2016 watch
- 21-06-2016 18:26
- 21-06-2016 18:38
I was saying that I think random's answer which had a root2 in was incorrect (and you said you put what he did). I believe 8752 is correct
- 21-06-2016 19:12
(Original post by 8752)
- 22-06-2016 01:55
Yes you're right it does lie on the line joining the two masses. The distance should be root10/2 a however. Im curious as to how people got root 2 tho?
5/2, rooting that gives root10/2, but for some reason instead of taking moments I used cos rule just a tiny bit wrong like this
by a factor of 2 in the term with cos145 gcse tier error tbh
- 24-06-2016 18:10
Just got hold of the paper and had a go myself.
Question 4 is ambiguous in that it's open to interpretation (with or without caps?). I've included both possibilities.
- 24-06-2016 19:09
(Original post by tiny hobbit)
- 24-06-2016 19:11
If you look in the formula book that Edexcel give you, the M of I of a cylindrical shell is given as being the same as for a hoop. That tells you that the shell does not have caps.
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