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    (Original post by WhiteX)
    yes i got the same m then i used this formula (y-9)=m(x-6) i used these coordinates
    is tha right ???? iah1700 did you do the same ?
    Yeah something like that, I definitely got 3/4 for gradient, then multiplied all values by 4 to get integers (I think)
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    (Original post by WhiteX)
    and make T the subject did you get T= m+1/3m-1?
    yep
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    what was the answer for the cube and spheres question?
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    I am fairly sure my answers are correct' here are some of the harder questions answers:

    Last question: range 185-188 acceptable
    Probability: lots of people got different answers; I got 5/28
    Angle ODC question: 63 degrees
    Re-arranging question: t= 1+3m/m-1 (something like that)
    Cubes question: 1439 cubes
    Rupees question: 52%
    Volume of vase (or whatever it was): 102.4cmcubed
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    (Original post by DJShaji)
    For the line question i got:3x - 4y = 19

    For the cube/sphere one, I think I got something like 1637

    I can't remember the probability one fully, but it was something over 80 something

    I got 188 for the area of the pentaagon
    what about make T the subject did you get T=m+1/3m-1 ?
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    (Original post by _Xenon_)
    Yes it will!
    I just feel so terrible, I've got method marks
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    (Original post by WhiteX)
    what about the bihra guy the propotion i got 51.6 will they give me full mark ?
    It said to give it as a whole number so 52% (you might lose one mark but I doubt it)
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    (Original post by aaljhfgahsj)
    I am fairly sure my answers are correct' here are some of the harder questions answers:

    Last question: range 185-188 acceptable
    Probability: lots of people got different answers; I got 5/28
    Angle ODC question: 63 degrees
    Re-arranging question: t= 1+3m/m-1 (something like that)
    Cubes question: 1439 cubes
    Rupees question: 52%
    Volume of vase (or whatever it was): 102.4cmcubed
    is 51.6 correct ?
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    A really easy way to do that question is this:
    (5,-1)
    (Y-y1) = m(X-x1)
    M is the gradient and you sub that in, y1 is the y point and x1 is the X point
    (Y--1) =0.75(X-5)
    And you expand
    Y+1 = 0.75X -3.75
    And rearrange
    y= 0.75x -4.75
    But they asked for it in a different form I can't remember what it was I think it was
    Y-0.75x = -4.75
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    what was the original length of one side of the cube? was it 4.7cm to 0.5cm
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    (Original post by lattu27)
    what was the answer for the cube and spheres question?
    1637 ??? I think it could have been 1657 something in that ball park
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    (Original post by WhiteX)
    what about make T the subject did you get T=m+1/3m-1 ?
    I can't remember it now sorry
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    (Original post by WhiteX)
    is 51.6 correct ?
    It is but you needed to round it to the nearest whole number, so you wouldn't get the accuracy mark
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    (Original post by lattu27)
    what was the original length of one side of the cube? was it 4.7cm to 0.5cm
    4.75
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    Hi guys for the UNOFFICIAL MARK SCHEME. Please help me get it together.
    http://www.thestudentroom.co.uk/show...3#post65192313
    Many thanks.
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    (Original post by lattu27)
    what was the original length of one side of the cube? was it 4.7cm to 0.5cm
    It was 4.5cm to nearest 0.5cm, and 3mm to the nearest mm
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    the question was 4.5 to nearest 0.5cm and 3mm to nearest mm.. did you have to find the upper bound of the volume of the cube i.e 125 cm3 and the lower bound the volume of the sphere,- converting mm to cm ?? then dividing them? I'm not sure thats what i did
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    Cube is incorrect - it was 1600 something and the probability was 25/84
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    (Original post by ForeverFrench)
    I just feel so terrible, I've got method marks
    I'm sure you've not done so badly. What grade you aiming for?

    See unofficial mark scheme I am trying to put together and we can see how well you might have done.

    http://www.thestudentroom.co.uk/show...3#post65192313
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    (Original post by alic12345)
    the question was 4.5 to nearest 0.5cm and 3mm to nearest mm.. did you have to find the upper bound of the volume of the cube i.e 125 cm3 and the lower bound the volume of the sphere,- converting mm to cm ?? then dividing them? I'm not sure thats what i did

    4.75x4.75x4.75 for cubes volume And 0.2 cm for marble balls
 
 
 
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