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    What on earth...please tell me other people round that hard
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    This is the hardest paper I have never seen
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    Anyone can post the mark schemes?
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    I swear the ****ing space module had incorrect figures.....i got the deceleration as like 9.8 or 9.1.......which made the answer ****ing stupid....what on earth
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    Help what even was that
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    Was absolutely solid. By the way could the rocket engines slow it down. I calculated they slow the spaceship to like 2.8ms-1
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    (Original post by Sufyxyz)
    Was absolutely solid. By the way could the rocket engines slow it down. I calculated they slow the spaceship to like 2.8ms-1
    Hiw did you get 2.8

    I did 890g-670n=ma

    Then divide by mass to get like 9.1 acceleration then times by 3.5s....slowed it way too fast....what did i miss
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    Used v=u+at where a f/m

    a was in the opposite direction to u
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    what did you put for six marker?the tank
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    (Original post by Sufyxyz)
    Used v=u+at where a f/m
    How did you find acceleration
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    I got this too
    (Original post by Sufyxyz)
    Was absolutely solid. By the way could the rocket engines slow it down. I calculated they slow the spaceship to like 2.8ms-1
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    Did anyone else run out of time? lol
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    That was brutal none of the past papers coud have prepared me for this vague ******** of paper
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    Oh noooooo did gravity not apply?....was it really jist 670/mass to find a?!
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    that paper was so long and yet no youngs modulus stuff ??? i liked the wave question tho. didnt like the spring one that much (4 i think ??)
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    (Original post by philo-jitsu)
    How did you find acceleration
    I did the resultant force acting upwards that the question gave us divided by the mass of the ship also given.
    Bro I might be wrong in my answer so don't worry.
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    What a ****ing piss take, 8 questions each of which was harder than any other past paper question (and i've done them all). Managed to just squeeze in all the questions in the time. I swear they just have it in for us because they knew we were all retakers.
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    (Original post by 09rramphulm)
    what did you put for six marker?the tank
    Since acceleration is inversely proportional to mass, the decreasing mass meant that the lorry would accelerate at a greater rate. This means the initial gradient on the graph would be steeper.

    The lorry reaches its terminal velocity when it is in equilibrium. The driving force and the restitive forces are equal. Due to the higher acceleration, this lorry reaches its terminal velocity sooner than that in figure 7.

    Because the air resistance is independent of the mass of the lorry, the change in mass would not effect the maximum speed.


    This is roughly what I put, not sure what's right or wrong though.
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    That was so hard!!!! Anyone fancy starting another Twitter trend/outrage😭😭😭
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    lol kill me please
 
 
 
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