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    (Original post by xandieman)
    What was the answer for 2^k surds question with 5x 4^2/3 + 3x14^1/3?
    wasn't it (... + 3x16^1/3)?

    The answer was 2^13/3 (you can check it)

    Here's the solution:

    = 5x (2^2)^2/3 + 3x(2^4)^1/3
    = 5x2^4/3 + 3x2^4/3
    = 8x2^4/3
    = 2^3 x 2^4/3
    = 2^13/3

    hope this helps
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    I think I put 2^(13/3), think the question was 5*4^(2/3)+3*16^(1/3), write 4 and 16 in powers of 2 and you'll get 2^(4/3)*8, then write 8 as a power of 2 and simplify to 2^(13/3) if I remember correctly.
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    You know a paper is hard if there are two Hitler reacts to OCR C1 2016 before 4pm on youtube
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    (Original post by KevinGu123456789)
    Guys the answer to the last question was 27, but for some stupid reason, I left the answer as:

    8 x (√27/12)^3

    Now, I checked on my calculator, and it is equal to 27, but I'm not sure about whether my form is acceptable. My intermediate working was all right, so do you think that they will dock marks, and if so, how many?
    Yeah I left mine as 18root27/12 which is also 27 so I'm hoping we will still get full marks as it is equivalent but hopefully if we do drop marks it will be only 1 mark
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    What was question 9 I can't remember it but I'm pretty sure I got it
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    Does anyone have any predictions for how many marks you would need for 90ums?
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    (Original post by blinin7)
    Indices: Q5 pt 2:
    2^13/2
    Because:
    it was 8(2^4/3) = 2^3 x 2^4/3 = 2^13/3.
    Quite sure its correct as lots of people around me got the same answer

    Got 27 for last Question, although i left it as a surd.

    Im also sure the radius was 0<r<=2
    As when you put y=0 into the circle equation, you got x=-2
    Given the centre of the mini circle was at the origin, and had to be within the larger circle, the furthest it could have been was 0 -> -2 giving it a radius of 2 or less? It was only 2 marks so I cant see how it would be more complex than that?

    Hoping grade boundaries low (56-58), definitely much harder than past papers. Everyone was of the same opinion, few of further maths kids didnt finish it and theyre the 100UMS type.

    I also got 2^13-3

    For the last question I left my answer as 8*(27/12)^3/2, which does equal 27, just hope that the examiner picks up on this, i should get it correct, right?

    also, I'm pretty sure the set of values for r was 0<r<3√5 -5
    we know the radius of the circle is 3√5. We can calculate using:
    L=SQRT((x2-x1)^2 + (y2-y1)^2)
    plugging in values for the origin (0,0) and the centre of the circle (4,3) (can't remember if that's correct) then you get the distance 5. Therefore the maximum distance must me 3√5 -5, and since the radius can never be 0, you produce the set of values I mentioned before, right?
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    How many marks was question 9?
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    (Original post by Jeremy1207)
    How many marks was question 9?
    I think 7 marks
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    (Original post by TheSurrealTV)
    I think 7 marks
    That's annoying, messed that one up, hope A's around 80%
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    How many marks was the 4+12x-2x^2 question worth? And what did u guys get for the k inequality question? Plz reply, ur help will be greatly appreciated.
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    (Original post by Oooskar)
    I think I put 2^(13/3), think the question was 5*4^(2/3)+3*16^(1/3), write 4 and 16 in powers of 2 and you'll get 2^(4/3)*8, then write 8 as a power of 2 and simplify to 2^(13/3) if I remember correctly.
    I got 2^4
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    (Original post by admirableyellow)
    what? june 2015 was one of the easiest papers to date
    Yes but at the time after the exam everyone was saying it was hard, happens every year
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    (Original post by Andy98)
    I got 2^4
    Yeah I got that but we basically multiplied the powers instead of adding them.
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    (Original post by FluffyCommie)
    wasn't it (... + 3x16^1/3)?

    The answer was 2^13/3 (you can check it)

    Here's the solution:

    = 5x (2^2)^2/3 + 3x(2^4)^1/3
    = 5x2^4/3 + 3x2^4/3
    = 8x2^4/3
    = 2^3 x 2^4/3
    = 2^13/3

    hope this helps
    great, thanks. I think I will have 1/2 out of the 3 there.
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    (Original post by nobodycarescarla)
    Yes but at the time after the exam everyone was saying it was hard, happens every year
    but you can see the change in structure between the last 5 years papers and this year paper, they must admit that this year paper was the hardest but still easier than c2
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    (Original post by MaxJacksonn)
    yes bruv u knowwww bout dat
    Shut up max you're not road, posh boy Name:  David-Attenborough-Rex.jpg
Views: 201
Size:  253.5 KB
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    Just did the June 2007 FP1 paper (grade boundary for an A was 54) and was far far easier
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    hardest c1 exam by far. did all the past papers got over 90-95 in them all and now i think i probs got 54-56 marks. Any chances of being an A?
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    Anyone know how much roughly roughly 35-40 marks would get me XD... yer i flopped hard
 
 
 
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