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    (Original post by riixx)
    For the last question I chose first method because H3PO4 was the only product
    I chose the first method as the process was a two step process
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    (Original post by riixx)
    Also can anyone remember how many marks the mass question was aftert the ideal gas equation question
    3 i think
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    (Original post by Charco63)
    Paper was similliar in difficulty to last year due to weird questions and weird answers for the calculations (which I thought where originally wrong but glad I never changed them because by the looks of it they were right) so A will probably be around 56/57/58
    For CHEM1 the required UMS for an A Is usually 54-56, I think there was some questions that could have easily caught people out there so I think 57 for an A.
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    (Original post by jaymistry233)
    That's right
    Yeah it is, I just assumed since tetrahedral is 109.5, each bond angle lowers by about 2.5 so put 107 which is obviously wrong now


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    what did you all draw for the isomers of that alkene?
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    (Original post by Engineerrookie)
    I chose the first method as the process was a two step process
    It was the first method because H3PO4 was the only product meaning 100% atom economy.
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    (Original post by riixx)
    For the last question I chose first method because H3PO4 was the only product
    So did I
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    what did everyone get for the mass questions which was the 3rd last one the one after the pv=nrt question
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    all the products went to forming the phosphoric acid meaning it was in theory a 100% yield for the two step process
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    (Original post by Danny786)
    What was the formula for that Allende
    Was it thermal cracking also


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    C14H30

    Thermal cracking, Cond: High temp (600) and high pressure.
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    (Original post by Ultracrepidarian)
    what did everyone get for the mass questions which was the 3rd last one the one after the pv=nrt question
    It was a large mass, something like 1065kg
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    (Original post by Ultracrepidarian)
    what did everyone get for the mass questions which was the 3rd last one the one after the pv=nrt question
    0.451/0.453 m3 but not sure that is right, checked it over and over and couldn't see why not

    And mass of 1065000 something grams
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    (Original post by RME11)
    C14H30

    Thermal cracking, Cond: High temp (600) and high pressure.
    Perfect. What about the name of the Alkene it gave us??


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    (Original post by Bailey2j09)
    It was a large mass, something like 1065kg
    how did you work it out i got 80 something kg
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    (Original post by Charco63)
    0.451/0.453 m3 but not sure that is right, checked it over and over and couldn't see why not
    I got the exact same but it's wrong somehow - everyone else got 0.113


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    (Original post by Charco63)
    0.451/0.453 m3 but not sure that is right, checked it over and over and couldn't see why not

    And mass of 1065000 something grams
    i think i got 0.113 m3 , and then got 80kg for the mass
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    Is cracking conditions 700kpa or 7000kpa?
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    (Original post by Danny786)
    Perfect. What about the name of the Alkene it gave us??


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    But-1-ene
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    (Original post by Ultracrepidarian)
    how did you work it out i got 80 something kg
    This was the one where you had to convert m3 into dm3 right?
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    What did u guys get for why do vdw forces exist
 
 
 
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