Hey there! Sign in to join this conversationNew here? Join for free
    Offline

    0
    ReputationRep:
    (Original post by treeco)
    Can anyone remember the 1st equation you had to integrate in Q2?

    Think it was something like (4-1/x)^5

    If so, wouldn't the answer be x^2/6(4-1/x)^6...with no ln ?
    I got that!
    Offline

    11
    ReputationRep:
    (Original post by mil88)
    I got all but 81.92 part.

    I got 65.5.. and thus 66.
    Yup you're right, my bad!
    Offline

    1
    ReputationRep:
    (Original post by drandy76)
    Plugging pi/6 into a calculator gives 2, not 1, it was 0.6something


    Posted from TSR Mobile
    Yeah I got 0.6....And 2.6.... But 2.6 was outside the range so the solution was 0.6
    Offline

    2
    ReputationRep:
    (Original post by drandy76)
    Plugging pi/6 into a calculator gives 2, not 1, it was 0.6something


    Posted from TSR Mobile
    yeah I got 0.659
    Offline

    0
    ReputationRep:
    I'm guessing that no body else got a=1 and b=320
    Offline

    7
    ReputationRep:
    For the iterative question did you have to put the answe to 4 decimal places or 3? I did everything to 4???? How many marks have I lost? I also therefore put the intersection point to 4dp?
    Offline

    0
    ReputationRep:
    On question 8ii I put that f(x) couldn't have an inverse because of the modulus and that you can't inverse a modulus. I also wrote that the graph would be one to many and that it wouldn't be a function. Was the first part right and if it wasn't would I get the marks for the second part?
    Offline

    1
    ReputationRep:
    Can we add a poll to this?? how hard did everyone find it and what grade boundaries do you reckon?
    Offline

    3
    ReputationRep:
    how many marks would you lose for not getting A and B i did everything else right i even calculate the y value as 18 just didn't solve the simultaneous equations
    Offline

    2
    ReputationRep:
    (Original post by rich1334)
    My solutions, in order:Y=12x+15
    4x-4lnx-1/x+c
    3/16(4x+1)^4/3 + c
    128, 81.92
    31 hours
    1/13, 3/4
    Show ln2
    5/2
    A=6, B=5
    Graph
    Root 0.242
    Graph transformations
    Ranges: all real, greater or equal to 4a, modulus has no inverse
    Inverse: 1/5(x+4a)
    X=1.5a, x=-2.5a
    Show equiv to 2
    4+2root2
    0.659
    32sin(x)
    No guarantee these are right but I'm pretty confident
    These are pretty much exactly the same results i got, except in question 9 i got the value of 0.66, not 0.659, i rounded to 2sf where i should have rounded to 3, probably won't get that mark.
    I'm feeling confident about my answers, so it's reassuring to have someone else confident with the same answers :P
    Offline

    0
    ReputationRep:
    Can anyone remember what f(x) and g(x) were?
    Offline

    2
    ReputationRep:
    (Original post by Yazmin123)
    how many marks would you lose for not getting A and B i did everything else right i even calculate the y value as 18 just didn't solve the simultaneous equations
    You'll probably lose 1 mark for not solving the equations and 2 marks for each answer i'm guessing
    Offline

    3
    ReputationRep:
    What was the 8 mark question 6? The one with a=6 b=5?

    I want the exact question with equations if possible?

    I don't know why but I remember getting b=5 and a= 3 or 2?
    Offline

    1
    ReputationRep:
    (Original post by HecTic_H)
    Grade boundaries anyone?
    Going to guess:
    41 - C
    47 - B
    53 - A
    59 - A*
    Really difficult paper imo.
    Agree with you)
    May be 1 mark higher for each grade)
    Paper was not terrible but it was harder than the average paper)
    Offline

    2
    ReputationRep:
    (Original post by Mrrexxxx)
    For the iterative question did you have to put the answe to 4 decimal places or 3? I did everything to 4???? How many marks have I lost? I also therefore put the intersection point to 4dp?
    Only 1 I'd say if your value was the correct answer to 4 SF.
    Offline

    1
    ReputationRep:
    (Original post by Dom1997)
    Only 1 I'd say if your value was the correct answer to 4 SF.
    If I can remember correctly, the question asked the values of Xn to be to at least 4 sig figs. If you did it to 4dp that is fine. If you put your answer to 3 dp which = 4sf you will probably loose one mark.
    Offline

    0
    ReputationRep:
    for q8, I got -1.5 and 2.5; not 1.5 and -2.5. how many marks you think have I lost? And what did people get for 8 part i?
    Offline

    2
    ReputationRep:
    (Original post by Agent47_)
    If I can remember correctly, the question asked the values of Xn to be to at least 4 sig figs. If you did it to 4dp that is fine. If you put your answer to 3 dp which = 4sf you will probably loose one mark.
    Thats was for xn I think. The actual root had to be 3 SF
    Offline

    0
    ReputationRep:
    unofficial mark scheme??
    Offline

    0
    ReputationRep:
    Does anyone remember what g(x) was?
 
 
 
Poll
Do you agree with the PM's proposal to cut tuition fees for some courses?

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reply
Hide
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.