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    (Original post by L'Evil Fish)
    Nope! I thought logic would say the lower value first, but I guess not I'll do them respectively :mmm:

    Anyway. I'll be off now
    Well it's whatever you have as you're domain which goes through some sort of function will give you the respective range value and okay, all the best!


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    Hi, i'd like to ask a bit of help with C3, it's about the Greatest Possible Domain

    I've been asked to determine the greatest possible domain for each of the following functions. Thing is I don't understand how I go about doing that, I know that when the function has a square root, the set of real numbers is not defined.

    So for example:

    f(x) = 3/x*squareroot(4-x) ... I know the set of real numbers is not defined because of the square root involved, but how do I find the domain here. Help please.
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    (Original post by MathsNerd1)
    Well it's whatever you have as you're domain which goes through some sort of function will give you the respective range value and okay, all the best!


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    Thanks, bye
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    (Original post by MathsNerd1)
    ...]
    i know this may seem really simple.. but im getting confused..

    what would you get for part Ai for this question...exam in about 2hrss

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    (Original post by ryanb97)
    i know this may seem really simple.. but im getting confused..

    what would you get for part Ai for this question...exam in about 2hrss

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    I'd get -a+b/4?


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    (Original post by ryanb97)
    i know this may seem really simple.. but im getting confused..

    what would you get for part Ai for this question...exam in about 2hrss

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    Note that:

    \vec{AB} = \mathbf{b} - \mathbf{a}

    \vec{DB} = \frac{3}{4} \mathbf{b}
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    (Original post by MathsNerd1)
    I'd get -a+b/4?


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    Sorry I would help but I've never done vectors
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    (Original post by tigerz)
    Sorry I would help but I've never done vectors
    It's okay, I think I've put the correct answer anyway and they're not that hard to grasp really, but it's best to get your other exams out of the way first before learning new stuff


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    (Original post by MathsNerd1)
    It's okay, I think I've put the correct answer anyway and they're not that hard to grasp really, but it's best to get your other exams out of the way first before learning new stuff


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    Ahh, I really need to learn them! They came up in my gcse I just guessed and skipped it, our teacher decided to teach us SOH CAH TOA 20 times and leave out vectors and this other equating thingy :L

    Yup I will
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    Is it okay to talk about C2?
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    (Original post by tigerz)
    Ahh, I really need to learn them! They came up in my gcse I just guessed and skipped it, our teacher decided to teach us SOH CAH TOA 20 times and leave out vectors and this other equating thingy :L

    Yup I will
    That's unfortunate really and would it be simultaneous equations that they left out?


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    (Original post by MAyman12)
    Is it okay to talk about C2?
    I don't think so if you've sat Edexcel, you'll have to wait until midnight.


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    (Original post by MAyman12)
    Is it okay to talk about C2?
    Not edexcel, still a bit over another 12 hours before you can discuss that.
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    You can discuss the Edexcel exam after midnight.
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    (Original post by MathsNerd1)
    It's okay, I think I've put the correct answer anyway and they're not that hard to grasp really, but it's best to get your other exams out of the way first before learning new stuff


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    You did put the correct answer
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    (Original post by MathsNerd1)
    I don't think so if you've sat Edexcel, you'll have to wait until midnight.

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    Ok
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    (Original post by MAyman12)
    Is it okay to talk about C2?
    Me, You, C2 talk, 12AM LOOL i'm messing yeah you gotta wait

    (Original post by MathsNerd1)
    That's unfortunate really and would it be simultaneous equations that they left out?


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    ]

    Trust cost me my A* at gcse loool, nah it was a bit like differentiation in C2, where you have to find an expression and then show that it equals another equation, usually with pyramids and cylinders!

    Back then I did not have this brain hahaha, so I couldn't do it
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    (Original post by MathsNerd1)
    I'd get -a+b/4?


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    (Original post by justinawe)
    Note that:

    \vec{AB} = \mathbf{b} - \mathbf{a}

    \vec{DB} = \frac{3}{4} \mathbf{b}
    how come it isnt -a+b/5 ??

    all the papers that i have done, i add the ratios.. why dont you have to do that here?

    ryan
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    (Original post by ryanb97)
    how come it isnt -a+b/5 ??

    all the papers that i have done, i add the ratios.. why dont you have to do that here?

    ryan
    Note that they said OD:OB = 1:4, NOT OD: DB = 1:4.

    OD is 1/4 of OB, which is the WHOLE line.
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    (Original post by justinawe)
    Not edexcel, still a bit over another 12 hours before you can discuss that.
    Don't internationals get a different paper now?
 
 
 
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