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    (Original post by RR97)
    Maths is different - it's 90 in each unfortunately with maths. (I'm predicted an A* so it's been explained to me)
    It's a 90 average mate


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    (Original post by Alleykat606)
    what was question 9??!!
    algerbraic fractions involving two variables x and k, you simplified it, you then differentiated it for b and something else after that, I see many people missed it which is good right? grade boundaries lowered!!!
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    (Original post by ArtemMakushin)
    I'm not sure man, but I got a y coordinate being massive... Because the gradient of the line was 24pie for me... Did you get same?
    Its 1/24pi
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    Pretty Confident i hit somewhere in the high 50s/Low 60s, reckon that will be an A grade?
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    (Original post by Bustamove)
    ****, made the most stupidest mistake when converting sec2A + tan2A...

    why the **** did I use Tan2A = 2tanA/1-Tan^A
    I should have used sin2A/Cos2A

    thats 4 marks down the ****ing drain...
    what did everyone get for their solutions for part b)?
    Did exactly the same man.
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    Please vote on poll:

    http://strawpoll.me/4609429
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    (Original post by dhamm)
    So did you draw on an asymptote for that one?
    No I just wrote no asymptote

    We shall have to wait for Lord Arsey to confirm if I'm right or wrong
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    (Original post by Chazley123)
    algerbraic fractions involving two variables x and k, you simplified it, you then differentiated it for b and something else after that, I see many people missed it which is good right? grade boundaries lowered!!!
    oh PHEW i did that one....thought i missed it for a sec
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    (Original post by jf1994)
    Yep, for the gradient of the line where you had to find where it crosses the y-axis i think
    **** yeah!!! I got that too!
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    (Original post by frozo123)
    65/75 for an A*?
    hell no!!! better be like June 2013 grade boundaries or imma flip ma sheeet
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    (Original post by HGKID)
    Anyone else get 4 answers for 8b?? (The one using the proof where you got tan(2theta) = -1/3
    I dont think it was 2theta I believe it was just tanA= -1/3
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    (Original post by ArtemMakushin)
    I'm not sure man, but I got a y coordinate being massive... Because the gradient of the line was 24pie for me... Did you get same?
    (Original post by Kill3er)
    Anyone get 1/24pi anywhere in any question?
    i got gradient 1/24 pi because gradient is dy/dx but the graph was x=
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    (Original post by Half Crazy)
    Nooo it wasn't G^-1(x) = f(x)e^-2x, it was G'(x) = f(x)e^-2x.

    G'(x) is differential of G(x),
    G^-1(x) is inverse function of G(x)
    I almost screwed this up, but realised half way through that i was doing G^-1 (x) instead of G'(x). I think it will be a common error
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    Name:  IMG_0030.jpg
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    My proof:
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    (Original post by Chazley123)
    I dont think it was 2theta I believe it was just tanA= -1/3
    Yeah -1/3


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    Guys did anyone get (6pi-1)/12for the y intercept


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    for question 9.. it's a increasing function... my friends told me just now... they were very sly about it...
    Caught me out as well...

    the gradient is = -3K/X something
    so you would assume it's decreasing function because it's negative gradient
    but at the top of the page, they said that K is a negative number

    so its increasing...

    Edexcel are a bunch of cheeky *****....
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    (Original post by jf1994)
    No I just wrote no asymptote

    We shall have to wait for Lord Arsey to confirm if I'm right or wrong
    i drew the asymptote but to be fair i looked at the question and it didnt say to state the asymptotes
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    (Original post by TruMuslima)
    Yep I got that. But not sure about it.

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    I thought it was -5x^2. Almost sure of it
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    (Original post by ArtemMakushin)
    I'm not sure man, but I got a y coordinate being massive... Because the gradient of the line was 24pie for me... Did you get same?
    Gradient was 1/ 24 pi
 
 
 
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