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    i think a minimum for an A will be 46 but thats being too nice unless every1 did find it very difficult.
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    (Original post by DaveGBG)
    Make it equal zero so therefore you can get rid of the denominator. Then multiply out the brackets and then rearrange
    what did you get? i simplified it to -3x^3 +16x +3=0

    but how do you get x from this?
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    Not sure whether these are right, relooked at the hard questions at home and i've got these.

    1) x = a/3 and -3a
    2) Two stationary points are (-3,0) and (-5,24)
    3) 45000
    4i) 25Sin(theta+16.3)
    ii) theta= 12.4 and 135
    5) 12(pi)ln25
    6ii) 2.398
    7i) x = (e^8-8)^0.5
    ii) e^x
    iii) 6/e^3
    iv) 20.3
    8aii) 3pi-alpha
    bii) 225/322
    9ia) f'(x) = 2(e^2x+3/e^2x); therefore e^2x > 0; so f'(x) > 0
    b) x > ln3/4
    ii) Range of g(x) >= k^0.5 (1-k)

    So much easier when you do it at home...
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    Made a howler on the final part of the volume of revolution question.... pi 24 ln 3. Showed all working so hopefully only lost a mark or two.
    I'm fairly sure I got atleast 63 marks. Any idea of the boundary for an A*
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    (Original post by Princess_perfect786)
    what did you get? i simplified it to -3x^3 +16x +3=0

    but how do you get x from this?
    Re-arrange to get the x from '-3x^3' alone
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    what did you get? i simplified it to -3x^3 +16x +3=0

    but how do you get x from this?
    Then you get 3x^3 - 16x - 3 = 0, 3x^3 = 16x + 3, x^3 = 16/3x + 1, x is the cube root of the right hand side. Just wish I'd remembered this in the exam...
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    (Original post by Quadratic)
    So yeah, I'd guess that's what, 12 marks lost :/? Definitely no A* for me D:
    Not necessarily! Last year the 90 UMS boundary was 62 marks and that paper was tough, it was the one I had to take for real. If this one is as hard as you guys are cracking it up to be (I haven't seen the paper yet) then it's possible that the 90UMS boundary will be around 60 raw marks.

    You probably will get a little more credit for partial answers than you are perhaps expecting.
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    60 raw marks sounds high for a difficult paper... the last few ones I tried the boundaries were 55, 55, 53, 51.
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    [QUOTE=yourworstnightmare;2946133 5]Just saw that the paper was uploaded, so had a crack at the first page. I'm not sure how correct it is since I did it in 5 minutes and have no calculator (being borrowed by current students )





    where did you manage to find the paper?
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    (Original post by jackdelderfield)
    60 raw marks sounds high for a difficult paper... the last few ones I tried the boundaries were 55, 55, 53, 51.
    60 raw marks for an A* is what he meant I think. An A will probably be around 50-54
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    (Original post by joe3469)
    Made a howler on the final part of the volume of revolution question.... pi 24 ln 3. Showed all working so hopefully only lost a mark or two.
    I'm fairly sure I got atleast 63 marks. Any idea of the boundary for an A*
    If that 3 was a 5, you'd get full marks, but i'm pretty sure you'll get the majority of the working too
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    Yeah, just realised. My mistake!
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    (Original post by yourworstnightmare)
    Honestly, nobody can tell yet, and nor do we want to guess to elevate/dishearten students by false hope. The past two years have been around 50 and this exam was just as hard, if not harder, so depending on how the entire country did, it could be +2/-3 each way of 50.

    Just wait and see - you may surprise yourself with a mark much higher than you expected, just like I did
    hopefully lol......i think i might have got 46/72

    reaaly praying it actually goes straight down to 45
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    [QUOTE=*Lucy;29463387]
    (Original post by yourworstnightmare)
    Just saw that the paper was uploaded, so had a crack at the first page. I'm not sure how correct it is since I did it in 5 minutes and have no calculator (being borrowed by current students )





    where did you manage to find the paper?
    http://www.thestudentroom.co.uk/show...4&postcount=89

    There we are, m'dear
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    (Original post by jackdelderfield)
    60 raw marks sounds high for a difficult paper... the last few ones I tried the boundaries were 55, 55, 53, 51.
    I was referring to the 90UMS boundary, not the A grade boundary.
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    for 7(ii) was the function with the inverse f(x) and the inverse e^x?
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    Anyone else have a time issue with this paper?
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    That's what I got for the inverse. Though I worked it out before I realised it was that simple...
    And I got to the end with only like 10 minutes to spare.
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    (Original post by I0144)
    Not sure whether these are right, relooked at the hard questions at home and i've got these.

    1) x = a/3 and -3a
    2) Two stationary points are (-3,0) and (-5,24)
    3) 45000
    4i) 25Sin(theta+16.3)
    ii) theta= 12.4 and 135
    5) 12(pi)ln25
    6ii) 2.398
    7i) x = (e^8-8)^0.5
    ii) e^x
    iii) 6/e^3
    iv) 20.3
    8aii) 3pi-alpha
    bii) 225/322
    9ia) f'(x) = 2(e^2x+3/e^2x); therefore e^2x > 0; so f'(x) > 0
    b) x > ln3/4
    ii) Range of g(x) >= k^0.5 (1-k)

    So much easier when you do it at home...
    how did you get this? my answer was 1/e^3
    i found that gf(x)= (lnx)^2 + 8 so gf'(x)= 1/x^2 therefore it equals 1/e^3
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    how did everone expand tanacotatan2a?
 
 
 
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