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# Ocr mei statistics 1 exam thread (24/05/13) Watch

1. for the second part of the question about the women and the man winning prizes, did anyone times something by 4 and add it to something ^4
2. (Original post by krishkmistry)
What did everyone do for the first part on q2 - I used combinations and I'm not sure

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me too, I did (5C2 x 5C1)/10C3 and i got 5/12 as my answer
3. (Original post by tumblrgirl)
me too, I did (5C2 x 5C1)/10C3 and i got 5/12 as my answer
same here
4. Lol theres no simplifying that fraction.
5. (Original post by tumblrgirl)
me too, I did (5C2 x 5C1)/10C3 and i got 5/12 as my answer
I got 5/12 too

Are we wrong?

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6. (Original post by tumblrgirl)
me too, I did (5C2 x 5C1)/10C3 and i got 5/12 as my answer
Either way is fine im sure.
7. plz someone tell me wat question 2 ii was ....
8. (Original post by Blobar)
Either way is fine im sure.
what did people get for the second part of this question?
9. (Original post by Blobar)
Did you guyes get like 14. something for SD and then just x by 0.9 in the second part to get the 2nd SD and not take away 15 unlike the mean.
Yes I did

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10. I got 5/12 first time round then for some reason i put 5/6 if i used the answer of 5/6 for the next part of the question would i still get the marks for it?
11. (Original post by juniorx)
what did people get for the second part of this question?
What was it?
12. What I did was for part 2 is (5/12)^4 + (5/12)^3.

Dunno if thats right.
13. (Original post by Blobar)
What I did was for part 2 is (5/12)^4 + (5/12)^3.

Dunno if thats right.
i did (5/12)^4 + 4(5/12)^3 x 7/12
14. why the 7/12? and why the 4 x 5/12^3
15. ok there was 23 data in total for the media and iqr question
I did 23 + 1 divdie by 2 which gave me the 12th value.
23x3/4 which gave me 17.25 rounding gives me the 18th turn
23/4 gives 5.75 rounding gives 6th turn. then just find the 18th number for q3 and 6th number for q1 to get iqr i did q3-q1
16. Ah I see where you're coming from, yeah I probably did that wrong tbh.
17. Prettty sure there was 25 numbers in the data set.
18. and for cumlative graph it was a total of 200

to get median 200/2 = 100 using the graph 100 = 3.5
q1 was 50
q3 was 150
iqr = 100

using grpah 100 =3.5
so u should of got the same median and iqr r the same
19. (Original post by x-Sophie-x)
I got 5/12 too

Are we wrong?

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I also got that, I don't know what else it could have been.
20. (Original post by Blobar)
why the 7/12? and why the 4 x 5/12^3
This is hard to explain so bear with me. i calculated the probability of getting the combination of part 1 3 times and the 4th probability is not 2 women and man not getting the prizes. Then i think there are 4 ways of arranging it and added this to the proability of the prizes being awarded 4 times. I did this because i think it asked for the probability of more or equal to 3 and it said there were 4 events

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