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    for the second part of the question about the women and the man winning prizes, did anyone times something by 4 and add it to something ^4
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    (Original post by krishkmistry)
    What did everyone do for the first part on q2 - I used combinations and I'm not sure


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    me too, I did (5C2 x 5C1)/10C3 and i got 5/12 as my answer
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    (Original post by tumblrgirl)
    me too, I did (5C2 x 5C1)/10C3 and i got 5/12 as my answer
    same here
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    Lol theres no simplifying that fraction.
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    (Original post by tumblrgirl)
    me too, I did (5C2 x 5C1)/10C3 and i got 5/12 as my answer
    I got 5/12 too

    Are we wrong?

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    (Original post by tumblrgirl)
    me too, I did (5C2 x 5C1)/10C3 and i got 5/12 as my answer
    Either way is fine im sure.
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    plz someone tell me wat question 2 ii was ....
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    (Original post by Blobar)
    Either way is fine im sure.
    what did people get for the second part of this question?
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    (Original post by Blobar)
    Did you guyes get like 14. something for SD and then just x by 0.9 in the second part to get the 2nd SD and not take away 15 unlike the mean.
    Yes I did

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    I got 5/12 first time round then for some reason i put 5/6 if i used the answer of 5/6 for the next part of the question would i still get the marks for it?
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    (Original post by juniorx)
    what did people get for the second part of this question?
    What was it?
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    What I did was for part 2 is (5/12)^4 + (5/12)^3.

    Dunno if thats right.
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    (Original post by Blobar)
    What I did was for part 2 is (5/12)^4 + (5/12)^3.

    Dunno if thats right.
    i did (5/12)^4 + 4(5/12)^3 x 7/12
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    why the 7/12? and why the 4 x 5/12^3
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    ok there was 23 data in total for the media and iqr question
    I did 23 + 1 divdie by 2 which gave me the 12th value.
    23x3/4 which gave me 17.25 rounding gives me the 18th turn
    23/4 gives 5.75 rounding gives 6th turn. then just find the 18th number for q3 and 6th number for q1 to get iqr i did q3-q1
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    Ah I see where you're coming from, yeah I probably did that wrong tbh.
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    Prettty sure there was 25 numbers in the data set.
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    and for cumlative graph it was a total of 200

    to get median 200/2 = 100 using the graph 100 = 3.5
    q1 was 50
    q3 was 150
    iqr = 100

    using grpah 100 =3.5
    so u should of got the same median and iqr r the same
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    (Original post by x-Sophie-x)
    I got 5/12 too

    Are we wrong?

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    I also got that, I don't know what else it could have been.
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    (Original post by Blobar)
    why the 7/12? and why the 4 x 5/12^3
    This is hard to explain so bear with me. i calculated the probability of getting the combination of part 1 3 times and the 4th probability is not 2 women and man not getting the prizes. Then i think there are 4 ways of arranging it and added this to the proability of the prizes being awarded 4 times. I did this because i think it asked for the probability of more or equal to 3 and it said there were 4 events
 
 
 
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