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    (Original post by Bobby21231)
    I think it's a constant as it stays the same whatever the k value is and is unaffected by it and it's got no x's with it, I may be wrong though
    You are correct, in y=mx+c, c stands for constant. I would assume... :P
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    are we sure the integration one is 512/15???
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    (Original post by Snicherz)
    are we sure the integration one is 512/15???
    Certain mate
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    For question 5bi) I got the answer and then multiplied it by a^2 to a quadratic and then factorised it, will I lose any marks for that?
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    i got 72-(5+2)= 65
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    Can we make an unofficial mark scheme?
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    did we have to differentiate on one question as i remember doing so :s
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    (Original post by Bobby21231)
    For the last question how many marks do you think I would get,
    I squared everything to get sin^2ax=3cos^2ax
    Then used the identies to get 1-cos^2ax=3cos^2ax
    Then rearranged to get 4cos^2ax=1 ,then cos^2ax=1/4
    then square rooted to get cosax=+ or - 1/2
    Then somehow I ended up with pi/3a and 2pi/3a as my final answer.
    Thanks very much
    I did the exact same!
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    Community Assistant
    Answers: http://www.thestudentroom.co.uk/show....php?t=4118305
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    (Original post by ellaatherz)
    I did the exact same!
    Oh that's good I'm glad I'm not the only one who didn't realise to just divide by cosax, hopefully we will still get most of the marks
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    what was the binomial question ???
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    I had to redo the first question in one of the spare booklets because i did it wrong originally in the answer booklet as my calculator was in radians so i had wrong solutions in the answer box.

    I wrote in the answer book "Please see sheet" and drew a circle around it. However i dont think i actually scribbled out my wrong answer/method in the answer booklet. Will i still get the marks for having the right solution/method in the spare booklet?
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    (Original post by ellaatherz)
    I did the exact same!
    Tan graph rrepeats every n radians so in this case it repeats n/a radians so after getting first value of n/3a you add n/a to this value to get the next positive value and so it is equal to 4n/3a
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    Are none of you ****tards able to read the ****ing mark scheme?
 
 
 
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