Hey there! Sign in to join this conversationNew here? Join for free
    Offline

    0
    ReputationRep:
    (Original post by GabbytheGreek_48)
    think it was p=-10 q-40 r--80 as the other 80 in the expansion was already showed in the question
    I agree, one 80 was given in the question.
    Offline

    9
    ReputationRep:
    (Original post by Danjohnson)
    It was 90😭😭
    lol he probably forget that n-= 4 in the notation and not 0
    Offline

    9
    ReputationRep:
    (Original post by beanigger)
    Unoffical Mark scheme for C2 AQA 2016

    It would help if you could correct the amount of marks in each question if it is wrong please

    Questions:

    1)a) integrate something to get -36x-1 + ax2 /2 [3]
    b) find the value of a when the answer to 1)a) is equal to 16 with limits of 3 to 1, a = - 2 [2]

    2)a) Draw the graph of (0.2)x and state where itcrosses axis (0,1)[2]
    b) use logarithms to solve (0.2)x = 4 , x = -0.861 [2]
    c) describe transformation of (0.2)x onto (5)x reflection in y axis [1]

    3)a) differentiate something to get 3x-1/2 -1 [2]
    b) find y co-ordinate of the maximum point M M(9,6) [3]
    c) equation of normal to curve at P i think P was (5,6) y=-2x+13 [2]
    d) the normal to curve at P is translated by (0,k) find value of k, k = 5.5 [3]

    4)a) show that a+10d=8 [2]
    b)sum to 2nd and 3rd term is 50, work out the 12th term of the series D=-2 and A=28, u12 = 6 [3]
    c) work out the sum of the 21st term minus sum of 3rd term = 90 [3]

    5)a) show that thetha (in radians) was 0.568 [2]
    b) work out area of triangle 19.9 [2]
    c) work out perimeter of shaded area, first piece of info given -> area of sector = area of shaded area

    you had to realise that the area of sector = area of triangle - area of sector
    re-arrange to get 2(area of sector) = 19.9 and solve for r to get 5.36?
    perimeter of shaded = (9-r) + (8-r) + 5 + (length of arc = r*theta)
    perimeter of shaded = 13.8 [6]

    6)a)trapezium rule to get 65.6 [4]
    b) describe transformation of graph y=(x2 +9)1/2 onto y = 5 + (x2 +9)1/2
    Translation by (0, 5) [2]
    c) describe transformation of graph y=(x2 +9)1/2 onto y=3(x2 +1)1/2 Stretch by scale factor 1/3 in x direction [2]

    7)a) expand (2+x)5 work out p q r, i think p was 10 q was -80 and r was 80 (correct me if im wrong) [4]
    b)find the coefficient of x10 in the expansion of (2+x)5 * (something else)7
    it was something like -1648 [5]

    8)a)find the value of tan(x) tan(x) = -5/4 [2]
    b) values of tanx in the range of 0 to 360 degrees 45, 129, 225, 309 [3]
    b) re-arrange 16+9sin2x / 3 - 5cosx into the form p + qcosx and find the min value = 2, this is when x is equal to pi [4]

    9)re-arrange something into the form (c)1/2 / d^2 to get 3y y = 1/2 ( m + 12n) [4]
    b) find the one and only solution of something, x = 5/2 ( you should get two equal roots i think) [4]
    also i think point P (4,5) good mark scheme though i can hardly remember the questions after a test
    Offline

    8
    ReputationRep:
    (Original post by Rowan396)
    In x isnt it the opposite, so moving right it a negative value?

    Either way I'm sure it was (k,0) not (0,k) like in the OP
    I can't remember the exact question but yes you're right it was (k,0) not (0,k), but it was definitely 5.5 not -5.5
    The change to x was -5.5, but as this is opposite it meant k was 5.5
    Offline

    8
    ReputationRep:
    (Original post by beanigger)
    Unoffical Mark scheme for C2 AQA 2016

    It would help if you could correct the amount of marks in each question if it is wrong please

    Questions:

    1)a) integrate something to get -36x-1 + ax2 /2 [3]
    b) find the value of a when the answer to 1)a) is equal to 16 with limits of 3 to 1, a = - 2 [2]

    2)a) Draw the graph of (0.2)x and state where itcrosses axis (0,1)[2]
    b) use logarithms to solve (0.2)x = 4 , x = -0.861 [2]
    c) describe transformation of (0.2)x onto (5)x reflection in y axis [1]

    3)a) differentiate something to get 3x-1/2 -1 [2]
    b) find y co-ordinate of the maximum point M M(9,6) [3]
    c) equation of normal to curve at P i think P was (5,6) y=-2x+13 [2]
    d) the normal to curve at P is translated by (0,k) find value of k, k = 5.5 [3]

    4)a) show that a+10d=8 [2]
    b)sum to 2nd and 3rd term is 50, work out the 12th term of the series D=-2 and A=28, u12 = 6 [3]
    c) work out the sum of the 21st term minus sum of 3rd term = 90 [3]

    5)a) show that thetha (in radians) was 0.568 [2]
    b) work out area of triangle 19.9 [2]
    c) work out perimeter of shaded area, first piece of info given -> area of sector = area of shaded area

    you had to realise that the area of sector = area of triangle - area of sector
    re-arrange to get 2(area of sector) = 19.9 and solve for r to get 5.36?
    perimeter of shaded = (9-r) + (8-r) + 5 + (length of arc = r*theta)
    perimeter of shaded = 13.8 [6]

    6)a)trapezium rule to get 65.6 [4]
    b) describe transformation of graph y=(x2 +9)1/2 onto y = 5 + (x2 +9)1/2
    Translation by (0, 5) [2]
    c) describe transformation of graph y=(x2 +9)1/2 onto y=3(x2 +1)1/2 Stretch by scale factor 1/3 in x direction [2]

    7)a) expand (2+x)5 work out p q r, i think p was 10 q was -80 and r was 80 (correct me if im wrong) [4]
    b)find the coefficient of x10 in the expansion of (2+x)5 * (something else)7
    it was something like -1648 [5]

    8)a)find the value of tan(x) tan(x) = -5/4 [2]
    b) values of tanx in the range of 0 to 360 degrees 45, 129, 225, 309 [3]
    b) re-arrange 16+9sin2x / 3 - 5cosx into the form p + qcosx and find the min value = 2, this is when x is equal to pi [4]

    9)re-arrange something into the form (c)1/2 / d^2 to get 3y y = 1/2 ( m + 12n) [4]
    b) find the one and only solution of something, x = 5/2 ( you should get two equal roots i think) [4]
    3d was (k,0) in the question, not (0,k) just so you know :*
    Offline

    4
    ReputationRep:
    [QUOTE=CirclesAreRound;65174541]
    (Original post by Dynamic_Vicz)

    Haha here's hoping! Best of luck to you too!
    Thanks man... One quick question ? Are you doing the remaining 3 modules for the A level maths (C3, C4 , applied module)
    Offline

    8
    ReputationRep:
    what did u guys get for the trapizium rule?
    Offline

    6
    ReputationRep:
    What total ums do you guys think is 70/75 on c1 and c2?
    Offline

    2
    ReputationRep:
    (Original post by Dynamic_Vicz)
    could you link me to the physics thread? This is for the new specification right?
    Yep, new spec:
    http://www.thestudentroom.co.uk/show....php?t=4114965

    This is for the Breadth, Im not sure if there is one for the Depth one yet
    Offline

    14
    ReputationRep:
    i think i failed c2 tbh, maybe a D ? if im lucky

    lets say if i get;
    'C' in c1
    'D' in c2
    what will i have to get in s1 to get a B (and is it even still possible for me to get a B ? LMAO )

    I mean B as an overall grade in AS maths
    Offline

    1
    ReputationRep:
    For question 6 part C I got stretch in the X by a scale factor of 1/9

    Ill show you how I got it
    First I rearranged the y=(x^2+9)^1/2 to make it easier to compare

    Y=(x^2+9)^1/2
    Y=(9(x^2/9 +1))^1/2
    Y=3(x^2/9+1)^1/2

    Comparing that with y=3(x^2+1)^1/2 you would have to stretch it in the X by a scale factor of 1/9???

    I know this doesn't look too nice with all the powers and divides but if you write it down it makes more sense

    I was just wondering if anyone could confirm my method or tell me where I went wrong as I believe this could have been one of those transformations with multiple answers??
    Offline

    4
    ReputationRep:
    (Original post by voltz)
    Yep, new spec:
    http://www.thestudentroom.co.uk/show....php?t=4114965

    This is for the Breadth, Im not sure if there is one for the Depth one yet
    Thanks really appreciate the help
    Offline

    0
    ReputationRep:
    Does anyone have any ideas on what 100 UMS would be?
    Offline

    1
    ReputationRep:
    (Original post by money-for-all)
    i think i failed c2 tbh, maybe a D ? if im lucky

    lets say if i get;
    'C' in c1
    'D' in c2
    what will i have to get in s1 to get a B (and is it even still possible for me to get a B ? LMAO )

    I mean B as an overall grade in AS maths
    Mate it's all about UMS, for a B roughly you're talking 70 UMS, and considering the difficulty of the papers changes then so does UMS. Therefore out of the 3 papers (300 UMS being the max) you would need 210 so say you did get a C and a D that would be around 130ish so you'll need a good 80 UMS on your S1 paper to get a B.
    I don't do S1 so I'm not sure how hard it is to get 80 UMS but it will be around the 60 marks, so just try and smash it, can always resit next year can't you
    Offline

    9
    ReputationRep:
    (Original post by money-for-all)
    i think i failed c2 tbh, maybe a D ? if im lucky

    lets say if i get;
    'C' in c1
    'D' in c2
    what will i have to get in s1 to get a B (and is it even still possible for me to get a B ? LMAO )

    I mean B as an overall grade in AS maths
    hhmmm idk probably a high a but mayb you did nt do as bad as you think
    Offline

    14
    ReputationRep:
    (Original post by GabbytheGreek_48)
    hhmmm idk probably a high a but mayb you did nt do as bad as you think
    Thanks Gabby the Greek !

    i like your motivation , im going to vote to stay in EU just for you !
    long like Greece and the UK !!
    Offline

    9
    ReputationRep:
    (Original post by money-for-all)
    Thanks Gabby the Greek !

    i like your motivation , im going to vote to stay in EU just for you !
    long like Greece and the UK !!
    lol im not actually from greece sadly just love greek mythology and culture
    Offline

    0
    ReputationRep:
    Couldn't do 8b! How did you get it into the form p+qcosx
    Offline

    7
    ReputationRep:
    (Original post by lucyshirl)
    Couldn't do 8b! How did you get it into the form p+qcosx
    Ohh yh, what was the answer for this one?
    Offline

    2
    ReputationRep:
    Grade boundaries predictions?
 
 
 
Poll
Who is your favourite TV detective?

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reply
Hide
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.