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Maths year 11 Watch

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    (Original post by z_o_e)
    So I need to work out one red and one white and add them up?

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    You need the probability of getting a red disk in disk 1 and then a while disk in disk two, then you need to find the probability of getting a while disk then a red disk then add them up

    so 6/9 * 3/9 + 3/9 * 6/9 = P(R,W)+P(W,R)
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    (Original post by 34908seikj)
    You need the probability of getting a red disk in disk 1 and then a while disk in disk two, then you need to find the probability of getting a while disk then a red disk then add them up

    so 6/9 * 3/9 + 3/9 * 6/9 = P(R,W)+P(W,R)
    Tyyx

    What about this



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    (Original post by z_o_e)
    Tyyx

    What about this



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    Part B is wrong
    Probability of one homework has two paths.

    If maths no homework then english home work and maths homework then english no home work

    or

    P(H,NH) and P(NH,H)

    Try it again now. Remember once you find the probability of both outcomes, you need to add them together.
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    (Original post by 34908seikj)
    Part B is wrong
    Probability of one homework has two paths.

    If maths no homework then english home work and maths homework then english no home work

    or

    P(H,NH) and P(NH,H)

    Try it again now. Remember once you find the probability of both outcomes, you need to add them together.
    Done xx

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    Could you show the full question?
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    (Original post by 34908seikj)
    Could you show the full question?


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    Yeah, it's right lol. I was a little confused with what you were doing.
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    (Original post by 34908seikj)
    Yeah, it's right lol. I was a little confused with what you were doing.
    Haha ha thank you x

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    (Original post by 34908seikj)
    Yeah, it's right lol. I was a little confused with what you were doing.
    Topic list


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    (Original post by 34908seikj)
    Yeah, it's right lol. I was a little confused with what you were doing.
    Heres topic list of this year x


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    (Original post by 34908seikj)
    You need the probability of getting a red disk in disk 1 and then a while disk in disk two, then you need to find the probability of getting a while disk then a red disk then add them up

    so 6/9 * 3/9 + 3/9 * 6/9 = P(R,W)+P(W,R)
    I'm not sure on the units for this questions I have to find the mass. The title of this work is called compound measure.



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    (Original post by z_o_e)
    I'm not sure on the units for this questions I have to find the mass. The title of this work is called compound measure.



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    What's 1KM?

    KM usually refers to a measurement of distance (kilometres), not volume. Are you sure that's right? Can you show the question please?
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    (Original post by 34908seikj)
    What's 1KM?

    KM usually refers to a measurement of distance (kilometres), not volume. Are you sure that's right? Can you show the question please?
    Yes it's right.
    This was set as homework to complete this table.



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    (Original post by z_o_e)
    I'm not sure on the units for this questions I have to find the mass. The title of this work is called compound measure.



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    You can't use the formula with density in terms of g per cm^3 and volume in km^3

    How many cm in a km and therefore how many cm^3 in a km^3 - think about it before you answer




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    (Original post by gdunne42)
    You can't use the formula with density in terms of g per cm^3 and volume in km^3

    How many cm in a km and therefore how many cm^3 in a km^3 - think about it before you answer




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    This is what I don't understand. I don't understand conversions and how to do them.

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    (Original post by z_o_e)
    This is what I don't understand. I don't understand conversions and how to do them.

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    How many cm in a m
    How many m in km
    So how many cm in a km

    Now imagine a cube that measures 1 km in each direction, how would you calculate its volume


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    (Original post by gdunne42)
    How many cm in a m
    How many m in km
    So how many cm in a km

    Now imagine a cube that measures 1 km in each direction, how would you calculate its volume


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    I don't know conversions :/

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    (Original post by z_o_e)
    I don't know conversions :/

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    There are 100000 cm in 1 km. So in 1cm3 there are 100000^3 in 1km3 =1015 km3.
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    (Original post by z_o_e)
    I don't know conversions :/

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    You don't know that there are 100 cm in a m?
    or 1000 m in 1 km?
    So 100 x 1000 cm in a km


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    (Original post by z_o_e)
    Yes it's right.
    This was set as homework to complete this table.



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    Copper- 89.62 g/cm^3 - 14700 / 164

    Air - 15.38 m^3 - 20kg * 0.0013g/cm^3 then I just converted it into M^3, however it's probably easier to convert the 0.0013g/cm^3 in m^3 first.

    Edit: I did hydrogen wrong.
 
 
 
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