Advanced Higher Chemistry 2009 Watch

koolcat6
Badges: 0
#241
Report 9 years ago
#241
Abstraction did u get it was octrahedral shaped or trigonal bipyrimidal
0
reply
koolcat6
Badges: 0
#242
Report 9 years ago
#242
it cant be c cos draw the molecule out honestly u will see that 4 electrons remin cos remeber the other idoines are the same is not like 1 elctron from idoine binds with 1 elctron in anoth iodine.
0
reply
abstraction98
Badges: 0
Rep:
?
#243
Report 9 years ago
#243
(Original post by koolcat6)
because after a while the reaction will cool down

btwabstraction is 14 not a im deffo sure btw
How can it be A? Top layer over bottom layer. It can't be less than 1 for a start as clearly the top layer required greater neutralisation and thus had a greater conc.
0
reply
abstraction98
Badges: 0
Rep:
?
#244
Report 9 years ago
#244
(Original post by koolcat6)
Abstraction did u get it was octrahedral shaped or trigonal bipyrimidal
If you are talking about the iodinepentafluoride, trigonal bipyramidal.
0
reply
abstraction98
Badges: 0
Rep:
?
#245
Report 9 years ago
#245
(Original post by koolcat6)
it cant be c cos draw the molecule out honestly u will see that 4 electrons remin cos remeber the other idoines are the same is not like 1 elctron from idoine binds with 1 elctron in anoth iodine.
Cba explaining but it definetely can't be B. Why because the molecule is linear as shown here:

http://en.wikipedia.org/wiki/Triiodide
0
reply
oberon06
Badges: 0
#246
Report 9 years ago
#246
that paper wis a piece of piss! ahahahaha just kiddin

dont think i done too bad considering i never studied. id be happy with a D
0
reply
koolcat6
Badges: 0
#247
Report 9 years ago
#247
nUMBER 14

partion = chlorofrom divided by water
moles in chlorform = 0.0133 multply by 0.05= 0.000665

moles in water = 0.002 multiply by 0.05 = 0.001

so 0.000665 divide by 0.001= 0.665 something
0
reply
abstraction98
Badges: 0
Rep:
?
#248
Report 9 years ago
#248
(Original post by koolcat6)
nUMBER 14

partion = chlorofrom divided by water
moles in chlorform = 0.0133 multply by 0.05= 0.000665

moles in water = 0.002 multiply by 0.05 = 0.001

so 0.000665 divide by 0.001= 0.665 something
Yes, but the partition coefficient is the top layer over the bottom layer.
0
reply
koolcat6
Badges: 0
#249
Report 9 years ago
#249
no it applies to the equatoion does it not which is water to chlrofrom
0
reply
abstraction98
Badges: 0
Rep:
?
#250
Report 9 years ago
#250
(Original post by koolcat6)
no it applies to the equatoion does it not which is water to chlrofrom
??
0
reply
koolcat6
Badges: 0
#251
Report 9 years ago
#251
does anyone know what the % to get an A last year was. 2007 you had to get 70 percent aghhh
0
reply
koolcat6
Badges: 0
#252
Report 9 years ago
#252
Im not sure abstractions you are probably right cos you seem much smarter then me at chemistry but i thought that it applied to the equation in calculating parition coefficent which is product over reactant does not apply to the diagram
0
reply
abstraction98
Badges: 0
Rep:
?
#253
Report 9 years ago
#253
(Original post by koolcat6)
Im not sure abstractions you are probably right cos you seem much smarter then me at chemistry but i thought that it applied to the equation in calculating parition coefficent which is product over reactant does not apply to the diagram
Haha you reckon. I'm pretty sure I've seen similar questions and I'm afraid its top layer over bottom. Hey, its one mark. I got the stupid adding NaOH one wrong. Meh, these things happen.

Usually around about 70%

EDIT: In retrospect I think you are correct about it being 0. whatever. Cheeky question, but I suppose K does equal the right over the left.
0
reply
Lisa.Marie
Badges: 0
Rep:
?
#254
Report 9 years ago
#254
i feel like crying after that! i studyed so much and still found it pure hard! like i thought some of it was okay but some of the questions were like wtf! lol
0
reply
akj08
Badges: 12
Rep:
?
#255
Report 9 years ago
#255
For MC q7, I know you've got wikipedia etc. but from what's shown (in the question) is it not basic because it reacts with acid forming a salt and water? In the second equation you're just dissolving it in sodium hydroxide solution, no water is actually produced.

Overall it was fair I think, bit strange there was not stoichiometry question or reaction mechanism...
0
reply
justasmalltowngirl
Badges: 0
Rep:
?
#256
Report 9 years ago
#256
i thought that as crazy hard though looking at everyone elses answers i think i got 22 on the multiple choice and 44 on the other bit which is better than i thought but still annoying. i think my investigation is really good so if i get like 20 on it i may still be able to get and A if the mark is lowered?

what do u think?

also for mc 10 i put c? why isn't it c?

and on 3 b i put atomisation? and -2326


does anyone no all the right answers for the mc?
0
reply
Kgraham1991
Badges: 0
#257
Report 9 years ago
#257
Hi here's my MC answers, i know i got 4 wrong, my chem teacher told me its B, point out any other noticed mistakes please! thanks!

1 D
2 D
3 A
4 D (apparently right answer is B which i had and changed :mad: )
5 A
6 C
7 D
8 B
9 D
10 C
11 B
12 C
13 A
14 C
15 D
16 A
17 A
18 C
19 B (i guessed)
20 A
21 B
22 A (i guessed that too)
23 A
24 C
25 B
26 D
27 B
28 A
29 C
30 C
31 B
32 B
33 C
34 D
35 D
36 A
37 A
38 D
39 C
40 A

let me know if thats good or bad, i'm not sure!
0
reply
OriginofSymmetry
Badges: 1
Rep:
?
#258
Report 9 years ago
#258
HA. HA. HA.

Didn't study for it, and it showed :p:
0
reply
Kieran578
Badges: 0
Rep:
?
#259
Report 9 years ago
#259
(Original post by abstraction98)
cba starting a new page..

Was a fair exam I thought. Totally played the exam and guessed that ZnO was amphoteric - it is..

Got the "what is the sodium hydrogencarbonate for" one wrong. A few other bits I'm slightly worried about, but nothing drastic. Multiple choice answers:

1. D
2. D
3. A
4. C
5. A
6. C
7. D (http://en.wikipedia.org/wiki/Amphoteric)
8. B
9. D
10. C
11. C ~
12. D
13. A
14. C
15. B
16. C
17. A
18. A
19. D
20. B
21. B
22. C
23. A
24. C
25. B
26. D
27. D
28. A
29. C
30. C
31. B
32. C
33. C
34. D
35. B
36. A
37. B
38. B
39. C
40. C


we're quite similar - you seem to know your stuff so thats cheered me up.....looking back I can't believe I've got 2 of the most simple MC Qs wrong - 5(didn't read the Q - thought it was a pn-junction) and 12......my own fault
0
reply
abstraction98
Badges: 0
Rep:
?
#260
Report 9 years ago
#260
(Original post by akj08)
For MC q7, I know you've got wikipedia etc. but from what's shown (in the question) is it not basic because it reacts with acid forming a salt and water? In the second equation you're just dissolving it in sodium hydroxide solution, no water is actually produced.

Overall it was fair I think, bit strange there was not stoichiometry question or reaction mechanism...
Yes, it's basic in the first but acidic in the second. I had a hunch that aluminium oxide does the same thing which is why I went for it. The zinc and hydroxyl group are actually a 2- ion. I agree, its a hard question. On that wikipedia page scroll down and it has exactly the same reactions..

What did you get for mc 11 and 14

Agree? No mechanism or titration etc.!?
0
reply
X

Quick Reply

Attached files
Write a reply...
Reply
new posts
Latest
My Feed

See more of what you like on
The Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

Personalise

University open days

  • Cranfield University
    Cranfield Forensic MSc Programme Open Day Postgraduate
    Thu, 25 Apr '19
  • University of the Arts London
    Open day: MA Footwear and MA Fashion Artefact Postgraduate
    Thu, 25 Apr '19
  • Cardiff Metropolitan University
    Undergraduate Open Day - Llandaff Campus Undergraduate
    Sat, 27 Apr '19

Have you registered to vote?

Yes! (458)
38.01%
No - but I will (91)
7.55%
No - I don't want to (85)
7.05%
No - I can't vote (<18, not in UK, etc) (571)
47.39%

Watched Threads

View All