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    The only two questions I had trouble with were 1b), writing Cos(Theta) in terms of p (I'm not great at remembering all the identities) and question 8 I think, showing Sec2A + Tan2A = (CosA + SinA)/(CosA - SinA), but I got there in the end! Overall, it wasnt that bad a paper in my opinion
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    (Original post by Nightmare8)
    So weird that there wasn't a change of sign or an inverse function. Did anyone else find it weird? O.o
    Absolutely. Inverse functions and "sign change => correct to 3dp" questions tend to be given marks. No given marks on this occasion though, really.
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    I got that aswell
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    guys please, what was the last question on the paper?
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    (Original post by BFP=big fat poo)
    right guys im so confused now, for the range question I wrote x=0, x=0.5, x=2
    many people seem to agree....
    from there i got -0.7<y<0.3 or something, and people say that's wrong but I don't see where I've gone wrong??????
    This is exactly what I got! Many people are saying its wrong but I can't see what else it could be.... :/
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    I really liked that paper, no lie.
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    (Original post by jf1994)
    That question was only four marks wasn't it? Based on how hard people have found the paper, I don't think missing that question out even entirely would severely dent your chances, assuming you did well in all the other questions
    I think it was 5, it leaves no room for error however.
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    There wasn't a question 10 was there? Only 9 questions?
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    I thought question 10 was pretty ok, got something like 269/ln2...
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    what was question 7?
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    Also guys, for the asymptotes I got 2? y=-5 and y=5?
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    For the last question:

    f'(x) = -3k/(x-k)^2

    Since k is a negative integer, let k = -a, where a >0.

    Thus: f'(x) = +ve/+ve since any integer squared is positive.

    The function is therefore increasing.


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    When is the hitler video out?
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    (Original post by LukeTownsend123)
    Attachment 426171This is what I got, people agree?

    The last question, dy/dx is greater than zero since k is a negative value
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    Increasing function, as numerator and denominator of differential were positive, therefore gradient is positive and thus increasing.
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    Name:  image.jpg
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Size:  432.4 KB
    (Original post by BenB96)
    If you split the fraction to separate it out so you have 1/cos2A + Sin2A/Cos2A
    I think you get to the correct solution
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    Other than the trig proof, the paper was of standard difficulty I reckon. Some questions were tricky and the format of the paper was unusual, but I wouldn't expect grade boundaries to drop more than 2 marks from last year.
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    (Original post by BFP=big fat poo)
    Also guys, for the asymptotes I got 2? y=-5 and y=5?
    Yes
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    Name:  01.jpg
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Size:  499.3 KBJust got hold of a paper. This is what I had for question 1
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    What was the answer to why they can't be an inverse function of g(x)
 
 
 
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