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    screw English lit.
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    (Original post by Bude8)
    screw English lit.
    IKR!
    (Original post by Bude8)
    That takeaway :coma:
    What was it? :holmes:
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    (Original post by Bluffroom)
    IKR!

    What was it? :holmes:
    Mixed Meat & Chips :mmm:
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    (Original post by Bude8)
    screw English lit.
    Only bads would say such a thing
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    (Original post by Elm Tree)
    Only bads would say such a thing
    Your opinions are invalid
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    will somebody give me a step by step answer to this question

    15cm3 of ethanoic acid was neutralised by 45cm3 of NaOH of concentrration 0.2 molesdm-3

    calculate the concentration of the ethanoic acid in grams per decimetre?

    i can do it when it just says moles per deimetre but the last step from the CGP book baffles me -_-
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    (Original post by techno836)
    will somebody give me a step by step answer to this question

    15cm3 of ethanoic acid was neutralised by 45cm3 of NaOH of concentrration 0.2 molesdm-3

    calculate the concentration of the ethanoic acid in grams per decimetre?

    i can do it when it just says moles per deimetre but the last step from the CGP book baffles me -_-
    Devide all the volumes in cm3 by 1000 to get them in dm3



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    (Original post by techno836)
    will somebody give me a step by step answer to this question

    15cm3 of ethanoic acid was neutralised by 45cm3 of NaOH of concentrration 0.2 molesdm-3

    calculate the concentration of the ethanoic acid in grams per decimetre?

    i can do it when it just says moles per deimetre but the last step from the CGP book baffles me -_-
    Concentration = Number of Moles / Volume

    So how many moles of NaOH?

    Write out the balanced equation.

    How many moles of NaOH for Ethanoic Acid?

    Whatever it is scale the moles up.

    Concentration = Number of Moles / Volume

    Find the concentration.

    Then

    Mass in g = moles x Mr

    = mass in g/dm^3
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    (Original post by L'Evil Fish)
    Concentration = Number of Moles / Volume

    So how many moles of NaOH?

    Write out the balanced equation.

    How many moles of NaOH for Ethanoic Acid?

    Whatever it is scale the moles up.

    Concentration = Number of Moles / Volume

    Find the concentration.

    Then

    Mass in g = moles x Mr

    = mass in g/dm^3
    I got 24296 g/dm3 and that really doesnt seem right?
    Wait a sec i think I know where i went wrong...
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    (Original post by sammann123)
    I got 24296 g/dm3 and that really doesnt seem right?
    Wait a sec i think I know where i went wrong...
    Probably didn't divide by the 1000
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    (Original post by L'Evil Fish)
    Concentration = Number of Moles / Volume

    So how many moles of NaOH?

    Write out the balanced equation.

    How many moles of NaOH for Ethanoic Acid?

    Whatever it is scale the moles up.

    Concentration = Number of Moles / Volume

    Find the concentration.

    Then

    Mass in g = moles x Mr

    = mass in g/dm^3
    This stuff was the only part of Chemistry I was actually good at :mmm:
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    (Original post by justinawe)
    This stuff was the only part of Chemistry I was actually good at :mmm:
    It's actually my worst bit atm
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    (Original post by L'Evil Fish)
    Probably didn't divide by the 1000
    nope, made a stupid mistake in working out the no. mols
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    (Original post by L'Evil Fish)
    Concentration = Number of Moles / Volume

    So how many moles of NaOH?

    Write out the balanced equation.

    How many moles of NaOH for Ethanoic Acid?

    Whatever it is scale the moles up.

    Concentration = Number of Moles / Volume

    Find the concentration.

    Then

    Mass in g = moles x Mr

    = mass in g/dm^3

    36g ?


    0.045 x 0.2 = 0.009 Moles
    0.009 /0.015 = 0.6 molesdm-3
    (12+3+12+18+18+1) = 60
    so i then do mass per decimeter = 0.6 x 60 = 36g per deciimetre ?
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    (Original post by L'Evil Fish)
    Probably didn't divide by the 1000
    36 g/dm3 sounds like a much better answer
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    (Original post by techno836)
    36g ?


    0.045 x 0.2 = 0.009 Moles
    0.009 /0.015 = 0.6 molesdm-3
    (12+3+12+18+18+1) = 60
    so i then do mass per decimeter = 0.6 x 60 = 36g per deciimetre ?
    yeah thats what i just got
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    (Original post by sammann123)
    nope, made a stupid mistake in working out the no. mols
    (Original post by techno836)
    36g ?


    0.045 x 0.2 = 0.009 Moles
    0.009 /0.015 = 0.6 molesdm-3
    (12+3+12+18+18+1) = 60
    so i then do mass per decimeter = 0.6 x 60 = 36g per deciimetre ?
    (Original post by sammann123)
    36 g/dm3 sounds like a much better answer
    I myself don't know the answer :rofl:

    I just gave you general steps and hoped it'd work :yy:
    Sounds right though
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    (Original post by L'Evil Fish)
    I myself don't know the answer :rofl:

    I just gave you general steps and hoped it'd work :yy:
    Sounds right though
    Yeah if we both got the same thing and its a round number its most likely right!
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    (Original post by sammann123)
    Yeah if we both got the same thing and its a round number its most likely right!
    :yep: hi btw, don't think we've spoken?
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    (Original post by sammann123)
    yeah thats what i just got
    right CGP seriously made the grams part look overcomplicated -_-
 
 
 
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