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    If I got the binomial wrong will I still get rewarded marks if I get the correct answer with the values that I got?
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    For the core 1 1/2 n^0.5 I got 1/2 170^0.5. You substituted in the minimum value to get AB^2 = 42.5 and then that somehow works out to 1/2 170^0.5
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    New links are up
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    (Original post by solosdk)
    60 for an A in Core 1 i think

    57 for an A in Core 2
    I think they'll both be lower than that to be honest, I've done easier past papers with higher boundaries.
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    Surely for the circle question the vector is [6, -7] as the second circle has center (-1,0) and the original has center (5,-7) so it's moved 6 units right and 7 down? Therefore [6 / -7] ?
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    (Original post by KoKiKo)
    I got the same answer for the integration, but most people seem to have got 27. I think we might have mad a mistake somewhere.
    Wow, that's actually amazing! I mean, the numbers seemed so ridiculous! Yet someone else got the same as me? That's quite interesting.

    I don't know where I went wrong with the first integration, but the second part I think I went wrong by calculating the area of the trapezium incorrectly. Just a silly error of reading the info wrong. This is one reason why I hate exams. Careless mistakes can cost you a grade, and it's not a perfect reflection on reality at all. Meh. Haha.

    By the looks of things, we both must have gone wrong in exactly the same place, and then a follow on error will have caused the rest to be wrong too. So there should be a good amount of marks available for method.
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    (Original post by buzfail)
    Surely for the circle question the vector is [6, -7] as the second circle has center (-1,0) and the original has center (5,-7) so it's moved 6 units right and 7 down? Therefore [6 / -7] ?

    I agree with this. Unless the question asked for a translation from the original circle to the new one. Anybody remember?

    I also agree with the way you wrote that post.
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    (Original post by stuart_aitken)
    I agree with this. Unless the question asked for a translation from the original circle to the new one. Anybody remember?

    I also agree with the way you wrote that post.
    read the question, it says 'the new circle equation' ONTO 'the old circle equation'.....
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    (Original post by Sophia Yeh)
    read the question, it says 'the new circle equation' ONTO 'the old circle equation'.....
    It says "Given that k has the same value as in part (a) (Which was 49), describe geometrically the transformation that maps the circle with equation (x+1)^2 + y^2 onto the circle C"

    So circle with center (-1,0) ONTO circle with center (5,-7)

    So translation 6 units in the positive x directions and 7 units in the negative y direction.

    SURELY
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    (Original post by stuart_aitken)
    I agree with this. Unless the question asked for a translation from the original circle to the new one. Anybody remember?

    I also agree with the way you wrote that post.
    Thank you! I got worried that I'd made a stupid mistake when I saw the "official unofficial" mark scheme.

    And lololol I have no idea how that happened, hardly ever comment on threads on here!
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    anyone know how many marks Q1 on Core 1 was? as it is not in the link at the beginning.
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    Its about 8 i believe


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    thanks for sharing
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    (Original post by Sophia Yeh)
    read the question, it says 'the new circle equation' ONTO 'the old circle equation'.....
    ?

    Sorry, can't read the question as I didn't take the exam booklet home when I finished...........

    Posted from TSR Mobile
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    (Original post by hit94)
    What was the proof for trig question at the end? I couldnt for the life of me do the last 2 parts on Q9
    Cant remember the exact question wording but... You had to use sinx/cosx=tanx then rearrange to get sinx=tanxcosx
    Then just sub in.
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    For 5a part 2 - write down the minimum value for the expression 2x^2+6x+5 i wrote both the x and y co ords of the minimum - (-3/2 , 1/2) will i get the mark ?
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    (Original post by Alifff)
    for x i got 3/2
    it was 2xsqrt3=3sqrt3--------so 2x=3sqrt3/sqrt3 wich cancels down to 2x=3 and so I got x=3/2 same as you! YAY!!!!!
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    (Original post by Namch)
    For 5a part 2 - write down the minimum value for the expression 2x^2+6x+5 i wrote both the x and y co ords of the minimum - (-3/2 , 1/2) will i get the mark ?
    That's exactly what I did. And because of that, perhaps, I couldn't make any sense of the follow on question. I must start reading properly.
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    Hi Guys, Im an Edexcel GCSE Examiner and many of my A-Level students have done the AQA C2 exam the other day and have asked me to explain Q3(binomials) and Q8(logs)
    I am just in the process of creating a youtube video and will upload it later this afternoon.
    I will post a message here when its ready.
    I hope you guys will find it helpful, and let me know if you'd like me to do it for any other questions.
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    I found this exam so hard.
 
 
 
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