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    (Original post by Z.M.1)
    For q4 I simplified it to 3 1/4 instead of 13/4 would I lose any marks? And for q5 if I read the question wrong, and moved the graph 4 in negative x and got 2/(x+4)^2 how many marks would I lose?

    Also is the correct sketch for the _)|(_ something like that? Again q5
    As the grade boundaries haven't changed since june12 61/72 for a and 54/72 for , what would you expect?


    Thank you!
    Q4) that's fine

    Q5) lose 1 mark

    I've provided a link to the correct graph on wolfram alpha a few pages ago.

    No idea about grade boundaries.
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    I'm busy again for another hour or so folks. Back later.
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    Hi Mr m for question 7ii.
    i left it has x<(equal to)5
    also for Q8) I divided by 2
    how many marks would i drop?
    Thanks
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    (Original post by Mr M)
    Mr M's OCR (not OCR MEI) Core 1 Answers May 2013


    1. (i) 12 \sqrt 5 (2 marks)

    (ii) 4 \sqrt 5 (1 mark)

    (iii) 5 \sqrt 5 (1 mark)


    2. x=\frac{1}{2} or x=-1 (5 marks)


    3. (i) f'(x)=2-\frac{12}{x^3} (3 marks)

    (ii) f''(x)=\frac{36}{x^4} (2 marks)


    4. (i) 3(x+\frac{3}{2})^2+\frac{13}{4} (3 marks)

    (ii) (-\frac{3}{2}, \frac{13}{4}) (3 marks)

    (iii) -39 (2 marks)


    5. (i) Correct sketch (2 marks)

    (ii) y=\frac{2}{(x+5)^2} (2 marks)

    (iii) Stretch scale factor \frac{1}{2} parallel to y axis (2 marks)


    6. (i) Centre (0, -4) and radius 2 \sqrt{10} (3 marks)

    (ii) (-2, -10) (2 marks)


    7. (i) x&lt;-\frac{1}{8} (2 marks)

    (ii) 0 \leq x \leq 5 (5 marks)


    8. 6x+2y-1=0 (7 marks)


    9. (i) Correct sketch with intersections at (-1.5, 0) and (2, 0) and (0, -6) (5 marks)

    (ii) x \leq \frac{1}{4} OR x &lt; \frac{1}{4} (either will be marked correct) (3 marks)

    (iii) 4.5 (4 marks)


    10. (i) k=-5 (7 marks)

    (ii) Minimum (2 marks)

    (iii) (-2, -27) (5 marks)


    I'll be around to answer questions shortly.
    sorry to keep pestering you as you have been an amazing help, but how did you work out number 8 as again got something slightly different. thanks again
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    (Original post by aran0909)
    Hi Mr m for question 7ii.
    i left it has x<(equal to)5
    how many marks would i drop?
    Thanks
    I would imagine only one mark.
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    (Original post by Majeue)
    I would imagine only one mark.
    Thanks what about if i divided by 2 on Q8?
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    Mr M, for question 9 part ii) , I stated that the range of values was
    -3/2 < x < 1/4 , I also go two solutions for the final question but had a line saying A = (-2,-27) as my final line of working (underlined). How many marks do you reckon I will lose?
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    Does anyone have all of the questions?
    People keep on asking for individual ones so it might make sense to put them all up at once! :-)
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    How many marks would I get if I did the right curve but only in the first quadrant (i.e. I didn't put a second curve symmetrical to it on the opposite side of the y-axis)?
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    (Original post by aran0909)
    Thanks what about if i divided by 2 on Q8?
    If you just left it in the form 3x+y-1/2 = 0, that should only lose the final mark. You'll have to tell me what answer you got.
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    (Original post by Rrobba)
    How many marks would I get if I did the right curve but only in the first quadrant (i.e. I didn't put a second curve symmetrical to it on the opposite side of the y-axis)?
    You would get 1/2 marks.
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    (Original post by fluker6696)
    Mr M, for question 9 part ii) , I stated that the range of values was
    -3/2 < x < 1/4 , I also go two solutions for the final question but had a line saying A = (-2,-27) as my final line of working (underlined). How many marks do you reckon I will lose?
    For 9ii, you might get 1, or 2 if you're lucky.
    For the final, you should only lose 1 mark, or may get full marks.
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    (Original post by Mr M)
    Mr M's OCR (not OCR MEI) Core 1 Answers May 2013


    1. (i) 12 \sqrt 5 (2 marks)

    (ii) 4 \sqrt 5 (1 mark)

    (iii) 5 \sqrt 5 (1 mark)


    2. x=\frac{1}{2} or x=-1 (5 marks)


    3. (i) f'(x)=2-\frac{12}{x^3} (3 marks)

    (ii) f''(x)=\frac{36}{x^4} (2 marks)


    4. (i) 3(x+\frac{3}{2})^2+\frac{13}{4} (3 marks)

    (ii) (-\frac{3}{2}, \frac{13}{4}) (3 marks)

    (iii) -39 (2 marks)


    5. (i) Correct sketch (2 marks)

    (ii) y=\frac{2}{(x+5)^2} (2 marks)

    (iii) Stretch scale factor \frac{1}{2} parallel to y axis (2 marks)


    6. (i) Centre (0, -4) and radius 2 \sqrt{10} (3 marks)

    (ii) (-2, -10) (2 marks)


    7. (i) x&lt;-\frac{1}{8} (2 marks)

    (ii) 0 \leq x \leq 5 (5 marks)


    8. 6x+2y-1=0 (7 marks)


    9. (i) Correct sketch with intersections at (-1.5, 0) and (2, 0) and (0, -6) (5 marks)

    (ii) x \leq \frac{1}{4} OR x &lt; \frac{1}{4} (either will be marked correct) (3 marks)

    (iii) 4.5 (4 marks)


    10. (i) k=-5 (7 marks)

    (ii) Minimum (2 marks)

    (iii) (-2, -27) (5 marks)


    I'll be around to answer questions shortly.
    For K=-5 I worked it out to be -49 I did all the correct working but I put in a negative sign instead of a positive infront of K at one point. I multiplied out the brackets and found dy/dy made it equal to 0 and substituted -3 for x.

    Then because this answer was wrong I couldn't do (-2,-27) I did the correct working but stopped when I couldn't find the multiples (because it didn't work) although I did do simultaneous equations and then showed an alternative method of dy/dx up until that point..

    Is it possible to get any method marks and if so could you hazard a guess at how many marks I'll lose/get.. Thanks!! I got nearly full marks in the rest of the paper I'm just worried the wrong sign will cost me an A (((((
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    Will I lose marks for not not writing the differentiation answers in a more suitable format? For example I wrote 36x^-4 instead of 36 over x^4 and the same with the other differentiation question.
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    (Original post by aran0909)
    Hi Mr m for question 7ii.
    i left it has x<(equal to)5
    also for Q8) I divided by 2
    how many marks would i drop?
    Thanks
    drop 2 marks and 1 mark respectively
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    (Original post by hayhayhay1)
    sorry to keep pestering you as you have been an amazing help, but how did you work out number 8 as again got something slightly different. thanks again
    I have provided the question earlier in the thread. Try working it out again?
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    (Original post by fluker6696)
    Mr M, for question 9 part ii) , I stated that the range of values was
    -3/2 < x < 1/4 , I also go two solutions for the final question but had a line saying A = (-2,-27) as my final line of working (underlined). How many marks do you reckon I will lose?
    9ii) you might get 1 mark if you are lucky

    full marks on the last part
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    (Original post by Rrobba)
    How many marks would I get if I did the right curve but only in the first quadrant (i.e. I didn't put a second curve symmetrical to it on the opposite side of the y-axis)?
    drop 1 mark
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    (Original post by Whyllee)
    For K=-5 I worked it out to be -49 I did all the correct working but I put in a negative sign instead of a positive infront of K at one point. I multiplied out the brackets and found dy/dy made it equal to 0 and substituted -3 for x.

    Then because this answer was wrong I couldn't do (-2,-27) I did the correct working but stopped when I couldn't find the multiples (because it didn't work) although I did do simultaneous equations and then showed an alternative method of dy/dx up until that point..

    Is it possible to get any method marks and if so could you hazard a guess at how many marks I'll lose/get.. Thanks!! I got nearly full marks in the rest of the paper I'm just worried the wrong sign will cost me an A (((((
    drop 1 mark in the first part and 2 marks at the end
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    (Original post by Maths927384)
    Will I lose marks for not not writing the differentiation answers in a more suitable format? For example I wrote 36x^-4 instead of 36 over x^4 and the same with the other differentiation question.
    That's fine.
 
 
 
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