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# UNOFFICIAL MARKSCHEME Edexcel Maths Calculator paper 09/06/2016 Watch

1. (Original post by Certified)
no it wasn't because 56 was corresponding, then its angles on a straight line..
I got 55
2. 24) A) -1/3x+4

B0 2x/(x+1)(x-1)

5) 0.09, 0.36

13) -1,1,-1

11) 42.28
12) 144
3. (Original post by rayestar)
u mean pentagon righttt? :d
yessss is it 144 omggg yas
4. (Original post by Jf1234)
What if we put 9/20 instead of 0.45 for 1b?
I did this it will still give u a mark
5. What did everyone get for the pentagon question?
6. Fast baller..star sigining for the paki internetional team also porn all the way and btw 1+1=69
7. What is the predicted grade boundaries for an A* for this year? And have grade boundaries ever been more than 170/200 for an A*?
8. (Original post by LilyKitty)
I don't think so because the angle has to be between the two sides (7 &8) for the formula of triangle area to work and x was another angle so you had to do cosine to find another side and then sine rule too before you could get x. Not sure though. xx
What? I got 80.4 but used cousins twice. Is that all right?
9. (Original post by Rajive)
I got 40.0?
Yeah that's what I got too , seems to be a few different answers people got though so not sure if it's right
10. (Original post by 34908seikj)
Wasn't the last question like 1/2 * 7 * 8 Sin(X) = 18

56Sin(x) = 36

Sin^-1(36/56) = X

x = 40

???

I think I did it wrong then.
I got the same and I thought it's right but apparently not since everyone else got 80.4 or 80.1

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11. GUYS WHAT DO YOU THINK THE GRADE BOUNDARIES WILL BE I REALLY WANT AN A BUT I THINK I GOT AROUND 120-130 OUT OF 200?!?!?! IS it possible?
12. (Original post by ellamoon_22)
This is correct. I forgot to do the inverse but i shall at least get 3/4marks i think
This is correct for the angle at B, but the question asked for the angle at A.
13. 80.1 is also ok for the last question right?
14. 3.8 is right
15. did u guys get 84638 bars ?
16. last question-
find angle bac

first find angle abc
18=0.5x7x8xsinabc
18=28sinabc
18/28= sinabc =0.642...
sin-1(0.642...)=abc=40.0052...

then find length AC
ac^2=7^2+8^2-3x7x8cos40.00
ac^2=27.209...
ac=5.216...

then find angle bac
18=0.5 x5.216...x7xsinbac
18/18.25...=sinbac=0.985...
sin-1(0.98...)=bac=80.3755...
=80.4
17. (Original post by 34908seikj)
Wasn't the last question like 1/2 * 7 * 8 Sin(X) = 18

56Sin(x) = 36

Sin^-1(36/56) = X

x = 40

???

I think I did it wrong then.

you had to find the area, then use the cosine rule then the sine rule to get 80.4
18. (Original post by samiuls)
yep its correct
W h a t!! !! I got 4! ! Time to cry salty tears.
19. I got 40.0 too...
Working back from 1/2absinC
20. (Original post by hannah2360)
What did everyone get for the pentagon question?
144 degrees

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