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    veldt127 Is there any chance you can explain / show us working for question 7b)? I thought I got the answer at the time but I seem to remember my answer being different to yours - the question was to solve
    3g(x+1) + 1 = 0
    with g(x) = arcsinx
    if I remember correctly? Thank you - and thanks so much for your answers, they're great!
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    Someone needs to get the actual paper up ASAP so everyone can establish the ranges in the trig questions. I will give an infinite number of rep using an infinite number of accounts to anyone who could possibly upload pictures of the paper. I'll even pay $. If you want $ PM me.
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    (Original post by Linguist131)
    veldt127 Is there any chance you can explain / show us working for question 7b)? I thought I got the answer at the time but I seem to remember my answer being different to yours - the question was to solve
    3g(x+1) + 1 = 0
    with g(x) = arcsinx
    if I remember correctly? Thank you - and thanks so much for your answers, they're great!
    Here you go! It was 3g(x+1) + pi = 0
    Name:  image.jpg
Views: 207
Size:  487.1 KB
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    does anyone know how many marks each questions is worth?
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    Guys does anyone remember question 5a please please i dont remember the question and dont remeber the answer and please help me
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    what was question 6 about again?
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    (Original post by veldt127)
    Here you go! It was 3g(x+1) + pi = 0
    Name:  image.jpg
Views: 207
Size:  487.1 KB
    Yep, that was it, thanks! I'm so annoyed - I think I wrote x = sin (pi / 3) when I converted it from arcsin and just missed out the 1 which is so irritating! Oh well, fingers crossed I only lost 1 or 2 marks for something that stupid - thanks
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    (Original post by eyeman567)
    what was question 6 about again?
    Long division, then finding a normal to the a point on the equation you found at the start.
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    Can someone explain how to do question 5a?
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    (Original post by Narxs)
    I did 4e^2x =25
    e^2x=25/4
    2x=ln(25/4)
    x=0.5ln(25/4)

    But didn't simplify ant further would this be alright??
    Just 1 mark you lose
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    (Original post by Ayagh)
    Guys does anyone remember question 5a please please i dont remember the question and dont remeber the answer and please help me
    Hi I think that is the one where you had 0=e^2x(3sintheta - 4costheta)

    Something like that.
    Then you end with tantheta = 3/4 or something.
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    (Original post by veldt127)
    Here you go! It was 3g(x+1) + pi = 0
    Name:  image.jpg
Views: 207
Size:  487.1 KB
    Correct
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    (Original post by veldt127)
    Here you go! It was 3g(x+1) + pi = 0
    Name:  image.jpg
Views: 207
Size:  487.1 KB
    I left it at sin(-pi) + 1 = x would i lose a mark for that?
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    (Original post by Kay Fearn)
    I left it at sin(-pi) + 1 = x would i lose a mark for that?
    It had to be sin(-pi/3)
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    (Original post by unimaginable118)
    Does anyone remember how many marks the last question was? I was SO STUPID. I left it out (( looks like someones not going to uni...
    Dont worry, it was like 8 max
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    (Original post by veldt127)
    It had to be sin(-pi/3)
    yes that's what i mean, would i lose a mark for leaving it like that?
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    (Original post by Kay Fearn)
    yes that's what i mean, would i lose a mark for leaving it like that?
    Possibly 1 or 2 for not finishing the answer; you'll definitely get method marks
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    If you put 2cosec4y but did all working out correct how marks would you lose and what do people think an A will be?
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    (Original post by veldt127)
    Possibly 1 or 2 for not finishing the answer; you'll definitely get method marks
    Yeah but i just left it as it's exact value, i thought that's what you had to do when it came to stuff with pi :-(
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    (Original post by strud1e)
    LHS:
    2/tan2A +tanA
    2(1-tan^A)/2tanA +tanA
    (1-tan^2A+tan^2A)/tanA
    1/tanA
    AH I was going to try it that way, but I did it the other way by making the cot into cos/sin and doing it all from there.. sigh
 
 
 
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