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# Year 13 Maths Help Thread

1. When I asked somebody on TSR whether I should learn FP2-FP3 and M3-M4 over the summer, he said that there isn't much point. Only in the past week did I understand what he meant. I will now concentrate on improving depth (on C1-C4) rather than breadth.
2. If you're asked to find the stationary point (sp) of f(x) then f(x-2) is there an easier way to find the sp for f(x-2)? (instead of subbing in x-2 then differentiating etc.)
3. (Original post by kiiten)
If you're asked to find the stationary point (sp) of f(x) then f(x-2) is there an easier way to find the sp for f(x-2)? (instead of subbing in x-2 then differentiating etc.)
Of course. f(x-2) is a translation by vector [2,0] from f(x).
4. (Original post by Palette)
When I asked somebody on TSR whether I should learn FP2-FP3 and M3-M4 over the summer, he said that there isn't much point. Only in the past week did I understand what he meant. I will now concentrate on improving depth (on C1-C4) rather than breadth.
That to me still doesn't sound like a great idea. You need to ask yourself what particular topics you want/need to challenge yourself on in C1-C4 if you even need to, or look at whatever it is you're trying to work towards (eg STEP or a university course that requires some areas in particular from FP2 and FP3 eg matrix algebra, taylor series) and pick out those ones rather than blindly going off in depth into C1-C4. That is how I would approach it anyway (understanding what exactly it is that needs work on).

(Original post by kiiten)
If you're asked to find the stationary point (sp) of f(x) then f(x-2) is there an easier way to find the sp for f(x-2)? (instead of subbing in x-2 then differentiating etc.)
Think about it with a graph to reach your answer.
5. Am i missing something? I keep getting the wrong answer :3

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6. (Original post by kiiten)
Am i missing something? I keep getting the wrong answer :3

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What's the actual right answer? x=1?
7. (Original post by kiiten)
Am i missing something? I keep getting the wrong answer :3

Posted from TSR Mobile
You've inadvertently uploaded your image in the wrong orientation. It's annoying how computers do that but mystifying how they would actually be able to fix it. But reading stuff sideways is not fun. Please try rotating the images on your computer or if it's on your tablet/phone, figure out which way you hold the camera to get the right orientation.
8. (Original post by SeanFM)
You've inadvertently uploaded your image in the wrong orientation. It's annoying how computers do that but mystifying how they would actually be able to do it. But reading stuff sideways is not fun. Please try rotating the images on your computer or if it's on your tablet/phone, figure out which way you hold the camera to get the right orientation.
Agreed. My neck feels abused.
9. (Original post by RDKGames)
What's the actual right answer? x=1?
correct answer is 3+ sqrt 13
10. Rotated image

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11. (Original post by kiiten)
correct answer is 3+ sqrt 13
In that case I'm correct, I was a bit hesitant to go forth with such an unrealistic answer applied to a real-life scenario.

Anyway,

You should not take the length of the path to be 2m, it simply does not make sense, it doesn't tell you this anywhere so I'm not sure where you pulled it from. The correct length would be 2x+2.

Here is the diagram showing so:
12. (Original post by RDKGames)
In that case I'm correct, I was a bit hesitant to go forth with such an unrealistic answer applied to a real-life scenario.

Anyway,

You should not take the length of the path to be 2m, it simply does not make sense, it doesn't tell you this anywhere so I'm not sure where you pulled it from. The correct length would be 2x+2.

Here is the diagram showing so:
How do you know its 2x +2? i thought it would be 2 because the width is 1 (the length of the middle part is twice the width).
13. (Original post by kiiten)
How do you know its 2x +2? i thought it would be 2 because the width is 1 (the length of the middle part is twice the width).
Whoops forgot to attach the diagram; it should explain it. Yes the WIDTH is 1, doesn't mean that it is doubled for the length.

"(the length of the middle part is twice the width)" that's only for the lawn.... which is separate...

Edit: Forgive my mouse writing skills.
14. (Original post by kiiten)
How do you know its 2x +2? i thought it would be 2 because the width is 1 (the length of the middle part is twice the width).
Also if you think about, if the length was 2m, what the hell would happen to the path if x keeps increasing? It would be completely destroyed, covered by the lawn and your local city council would make your pay for it. Be careful with maths.
15. (Original post by RDKGames)
Whoops forgot to attach the diagram; it should explain it. Yes the WIDTH is 1, doesn't mean that it is doubled for the length.

"(the length of the middle part is twice the width)" that's only for the lawn.... which is separate...

Edit: Forgive my mouse writing skills.
The width of the path is 1 but how do you know the length after the lawn is also 1? - if that makes any sense
16. (Original post by kiiten)
The width of the path is 1 but how do you know the length after the lawn is also 1? - if that makes any sense
Because that's still the width of the path...
17. (Original post by RDKGames)
Because that's still the width of the path...
Ohhh i misread the question: i thought the width of the larger rectangle was 1 (thats why i got it wrong)
18. (Original post by kiiten)
Ohhh i misread the question: i thought the width of the larger rectangle was 1 (thats why i got it wrong)
No problem, rookie mistake.
19. (Original post by RDKGames)
No problem, rookie mistake.
Haha thanks for your help
20. (Original post by RDKGames)
No problem, rookie mistake.
Now i got 3 + sqrt 17 instead of 3 + sqrt 13???

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