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    (Original post by Son234)
    Someone write the last two 4 marker question? Then I can answer it hopefully

    1) X-N(25.25, variance/10) find p(X<25) Right? can't remember the standard deviation

    2) X-N (25.25, variance) find P(X>25) for each or ahh I can't remember?




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    For the first one you had to find the standard error of the mean I think, then the second part was just done normally? Or have I gone crazy x
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    (Original post by AMMK)
    For the first one you had to find the standard error of the mean I think, then the second part was just done normally? Or have I gone crazy x
    That's exactly right

    first one was simple

    but for the second part I found the probability as normal but did it to power of 10

    And I can't remember the wording of it


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    [QUOTE=archy_van;42665198]
    (Original post by Son234)
    40x0.85 = p(met reserve price)

    34x0.5= p(met lowest estimate price)

    17x(1-0.175)= p(did not meet the highest estimate price)

    So it was 14 that's my logic


    got the same!
    I still think I'm right :L compared to everyone

    I understand 0.85-0.175

    And multiply it by 40

    But when do ever minus probabilities unless your trying to find the union

    My way seems so logical oh well it's only two marks

    I hope the examiner see's it and be like this guys got mad statistic skills and gives me a Mark


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    (Original post by Son234)
    The value for a was actually 0.467 or something close

    I don't know where the 0.6 is coming from

    And the b value was 1.00

    So y=0.467ish+1.00x




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    I got the 0.6 bit from doing b=syy/sxy or what ever was in the booklet!


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    Looks like I will be the first one to take a pop at the grade boundaries:

    A :: 54raw
    B :: 48raw
    C :: 42raw
    D :: 36raw
    E :: 31raw

    They are rather optimistic but I would say that was the hardest Stats 1b yet.
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    (Original post by AMELIA-x)
    I got the 0.6 bit from doing b=syy/sxy or what ever was in the booklet!


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    a=y (mean) - b*x (mean)

    Did you calculate a like that?


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    [QUOTE=Son234;42665391][QUOTE=archy_van;42665198]

    I still think I'm right :L compared to everyone

    I understand 0.85-0.175

    And multiply it by 40

    But when do ever minus probabilities unless your trying to find the union

    My way seems so logical oh well it's only two marks

    I hope the examiner see's it and be like this guys got mad statistic skills and gives me a Mark


    Dont work out the union is succes is 0.175 not success is (1-0.175)
    Because u want success follow but not succes you do 0.85x(1-0.175)x40=28.05

    And because apple was trying to get free ad of me posting this apple products are **** they keep on crashing
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    (Original post by Ingamo)
    Noo AQA :P
    pheeew... thanks!
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    [QUOTE=agharaza94;42665479][QUOTE=Son234;42665391]
    (Original post by archy_van)

    I still think I'm right :L compared to everyone

    I understand 0.85-0.175

    And multiply it by 40

    But when do ever minus probabilities unless your trying to find the union

    My way seems so logical oh well it's only two marks

    I hope the examiner see's it and be like this guys got mad statistic skills and gives me a Mark


    Dont work out the union is succes is 0.175 not success is (1-0.175)
    Because u want success follow but not succes you do 0.85x(1-0.175)x40=28.05

    And because apple was trying to get free ad of me posting this apple products are **** they keep on crashing
    dude, by any chance, do you go to New College?

    If not, I'm mistaking you for another guy with the same name that did Stats today in my college :P
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    For the regression line, would I get a mark for the correct a value even if I got the value of b wrong?
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    (Original post by laurag4131)
    For the regression line, would I get a mark for the correct a value even if I got the value of b wrong?
    I can't remember whether it was 3 or 2 marks, however you'd certainly receive a mark for getting the correct a value.
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    [QUOTE=MrJiggly;42665648][QUOTE=agharaza94;42665479]
    (Original post by Son234)

    dude, by any chance, do you go to New College?

    If not, I'm mistaking you for another guy with the same name that did Stats today in my college :P
    Me or agharaza?


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    [QUOTE=MrJiggly;42665648][QUOTE=agharaza94;42665479]
    (Original post by Son234)

    dude, by any chance, do you go to New College?

    If not, I'm mistaking you for another guy with the same name that did Stats today in my college :P
    Yes i do go to new college swindon, would i know?
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    Does anyone have an idea how many UMS 67/75 would convert to? Thanks for any responses!
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    [QUOTE=Son234;42665705][QUOTE=MrJiggly;42665648]
    (Original post by agharaza94)

    Me or agharaza?


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    agharaza...copying that HTML screwed it up
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    (Original post by Son234)
    a=y (mean) - b*x (mean)

    Did you calculate a like that?


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    No I mean this one the first one

    Name:  ImageUploadedByStudent Room1368803439.705967.jpg
Views: 227
Size:  146.5 KB


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    (Original post by 002)
    Does anyone have an idea how many UMS 67/75 would convert to? Thanks for any responses!
    I think it depends on the grade boundaries
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    (Original post by AMELIA-x)
    No I mean this one the first one

    Name:  ImageUploadedByStudent Room1368803439.705967.jpg
Views: 227
Size:  146.5 KB


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    I don't get what your asking me lol


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    (Original post by Son234)
    I don't get what your asking me lol


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    Oops maybe I did it wrong :/ I used the a=y(mean)-b(xmean) was that right?


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    (Original post by Leery24)
    I think I got 0.4 ;(


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    I got 0.486 or something similar. Lots of people got 0.6, which is right, but if you used your b value as 1.001x (or to a greater degree of accuracy) you got 0.486-ish as your value, but it will still be marked correct.

    So 116 - 1(115.4) = 0.6
    116 - 1.001(115.4) = 0.486

    Both get the marks - the second one used a greater degree of accuracy, that's all.
 
 
 
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