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    OK so I think I ****ed up slightly. I forgot to square root for the modulus in i think Q2 and then I forgot to square the modulus in the transformation question. I think everything else is fine. Can I still get 90+ ums?
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    (Original post by kingaaran)
    That's good then - at least I'm not the only one.
    It's the way you're taught in C4. Using Sin and Cos addition furmulae to evaluate integrals with trigs multiplied together
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    (Original post by kingaaran)
    Yep, I have it on me. I can scan it when I get home, but at the moment I can only post the questions?
    Scanned version would be ideal. Thanks a lot really.
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    (Original post by TeeEm)
    I am not planning to do solutions now.
    I have a list of currently 95 papers to do solutions for and this will slot somewhere mid-July in my do lists.

    However it will be nice to see the paper.
    (Original post by kingaaran)
    Yep, I have it on me. I can scan it when I get home, but at the moment I can only post the questions?
    (Original post by aidinpoori)
    Honestly? Have you scanned it? I'd love to see it please. I teach FP2 and am very concerened for my students. I know exactly what they can do and what they can't do. Jst wanted to check it please. Much appreciated.
    See the other thread
    http://www.thestudentroom.co.uk/show...156193&page=63
    post 1246
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    Yeah i did that!
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    Q1)

    (a) Use algebra to find the set of values of x for which  x+2 > \frac{12}{x+3}

    (b) Hence, or otherwise, find the set of values for x for which  x+2 > \frac{12}{|x+3|}

    Q2)

    z = -2 + 2(root3)i

    (a) Find the modulus and argument of z

    Using de Moivre's theorem,

    (b) find z^6, simplifying your answer

    (c) find the values of w such that w^4 = z^3, giving your answers in the form a+ib, where a, b are real numbers.

    3)

    Find, in the form y=f(x), the general solution of the differential equation

    tanx\frac{dy}{dx} + y = 3cos2x tan x

    4)

    (a) Show that

    r^2(r+1)^2 - (r-1)^2r^2 = 4r^3

    (b)

    use the identity given in (a) and the method of differences to show that

    (1^3+2^2+3^3...+n^3) = (1+2+3...+n)^2

    Q5)

    A transformation T from the z-plane to the w-plane is given by

     w=\frac{z}{z+3i}

    The circle with equation |z| = 2 is mapped by T onto the curve C.

    (a) Show that C is a circle and find the centre and radius of C

    The region |z| <= 2 in the z-plane is mapped by T onto the region R in the w-plane.

    (b) SHade the region R on an argand diagram

    Q6)

    The curve C, shown in Figure 1, has polar equation  r = 3a(1+cos\theta)

    The tangent to C at the point A is parallel to the initial line.

    (a) Find the polar coordinates of A.

    The finite region R shown shaded in Figure 1 is bounded by the curve C, the initial line and the line OA.

    (b) Use calculus to find the area of R.

    Q7)

    y=tan^2x

    (a) Show that \frac{d^2y}{dx^2} = 6sec^4x - 4sec^2x

    (b) Hence show that \frac{d^3y}{dx^3} = 8sec^2x tan x (Asec^2x +B), where A and B are constants to be found.

    (c) Find the taylor series expansion of y=tan^2x, in ascending powers of x - (pi/3), up to and including the term in [x - (pi/3)]^3

    Q8)

    (a) Show that the transformation  x=e^u transforms the differential equation


     x^2\frac{d^2y}{dx^2} -7x\frac{dy}{dx} + 16y = 2lnx (i)

    into the differential equation

     \frac{d^2y}{du^2} -8\frac{dy}{du} + 16y = 2u (ii)

    (b) Find the general solution of the differential equation (ii), expressing y as a function of u.

    (c) Hence obtain the general solution of the differential equation (i).
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    120+ students have voted... Have you?
    http://www.thestudentroom.co.uk/show....php?t=3376607
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    (Original post by Anshul6974)
    That's what I got!
    mine is pretty much the same as yours!! but for q3 i had sth like cosecxln()... maybe its just coz i didn't simplify it ??
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    why is this thread so quiet ...?
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    Anyone know if Arsey has posted for this yet??
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    does anyone know the marks for each question?
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    (Original post by TeeEm)
    why is this thread so quiet ...?
    Most people are on the other one.
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    All I know is that Edexcel is BAE after that exam! ☺️ Oxford here I come!


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    (Original post by kingaaran)
    Integral of 3cos2xsinx

    Is it okay to integrate 3/2(sin3x -sinx) instead?
    I also integrated it this way! ended up with something like y = -cos3x/2sinx + 3cotx/2... etc or something like that, hard to remember! hopefully won't need to simplify that anymore!
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    (Original post by StarvingAutist)
    I got inside.
    Is anything there wrong?
    I got it inside too.I thought of z=0 (which satisfies IzI=<2) then w=0 which is inside the circle .
    Did you mentioned that the circle itself satisfies this. I forgot...
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    (Original post by V0ldemort17)
    All I know is that Edexcel is BAE after that exam! ☺️ Oxford here I come!


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    Oxford Brookes?
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    (Original post by Idomaths)
    u chat so much sh it
    Don't know if I do bro.
    Don't be jealous bro.


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    (Original post by MrBowcat)
    Oxford Brookes?
    University of Oxford, you might not have heard of it but it's a pretty big deal


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    (Original post by V0ldemort17)
    University of Oxford, you might not have heard of it but it's a pretty big deal


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    Oh cool. You heard of Harvard?
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    (Original post by kingaaran)
    cos2xsinx = sin3x - sin x

    And then I integrated that. Is that fine?
    Yeah this will be fine I wrote sin3/2x-sinx/2 because im stoopid and now ill only get about 85 ums
 
 
 
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