Edexcel GCSE Mathematics May/June 2016 Official Thread

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    I think overall the exam was quite good. I simplified my answers for the last question. So is that still correct?
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    (Original post by junayd1998)
    What did people get for the Standard form q?
    It was 7x10^8
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    (Original post by tkrv)
    I think overall the exam was quite good. I simplified my answers for the last question. So is that still correct?
    It depends what you got o.O
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    (Original post by GoodGirlFaith)
    Ah, I wrote about the range but not the median. Oops.
    I got 11 females (I love those kind of questions) and 36% for the rent question. The circle theorem one was probably wrong, I put 48 (I think) but I got 69 by doing some calculation 😒 I was a bit 'what?' about the crisps question, I thought it was really weird!
    I got 11
    But i didn't get 36%
    And tht circle theorem is 69 degrees.
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    (Original post by 34908seikj)
    It was 7x10^8
    Thank gosh how about the Circle in the square i wrote 75 pi cuz is said the total shaded area so I did 10x10=100 then take that away from 25Pi
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    (Original post by junayd1998)
    Thank gosh how about the Circle in the square i wrote 75 pi cuz is said the total shaded area so I did 10x10=100 then take that away from 25Pi
    I got 69 degrees, don't remember my working though.

    And Pi is a number 3.14...

    Is it's 25pi = 25*3.14, so you can't just take it away from 100, without first dealing with Pi. BIDMAS or whatever it's called.
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    (Original post by 34908seikj)
    I got 69 degrees, don't remember my working though.

    And Pi is a number 3.14...

    Is it's 25pi = 25*3.14, so you can't just take it away from 100, without first dealing with Pi. BIDMAS or whatever it's called.

    yes but the question said in whats the answer in terms of Pi which means you leave Pi as it is.
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    (Original post by junayd1998)
    yes but the question said in whats the answer in terms of Pi which means you leave Pi as it is.
    Exactly therefore you just leave it as pi, 25pi you can't do anything else to it.
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    Can you simplify 100 - 25Pi down to 4 - Pi? Or not?
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    (Original post by 34908seikj)
    Exactly therefore you just leave it as pi, 25pi you can't do anything else to it.
    No CF no Histograms jack **** they put some long ass paragragh for comparing the two box plots f me edexcel
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    (Original post by zara_ruby)
    69
    So did I!


    Posted from TSR Mobile
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    (Original post by Ellen03)
    Can you simplify 100 - 25Pi down to 4 - Pi? Or not?
    Yes 25(4-pi)
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    (Original post by 34908seikj)
    I got 69 degrees, don't remember my working though.

    And Pi is a number 3.14...

    Is it's 25pi = 25*3.14, so you can't just take it away from 100, without first dealing with Pi. BIDMAS or whatever it's called.
    It says give your answer in pi so the answer in fact needed the symbol
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    (Original post by Kajsajbas)
    It says give your answer in pi so the answer in fact needed the symbol
    Yes Im aware, but I was explaining why you can't do 100-25pi = 75pi
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    (Original post by Kajsajbas)
    It says give your answer in pi so the answer in fact needed the symbol
    What did you get for that q?
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    What about the very last question, i think it was, on vectors where it was something like 'from your previous answer, what do we learn about the vector OS?' . I put something like OS is a multiple of OT therefore it is part of the vector OT.
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    (Original post by Ellen03)
    Can you simplify 100 - 25Pi down to 4 - Pi? Or not?
    Yh u can, but you need to write: 25(4-pi) as it is an area, not just a formula
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    oh and its the higher paper by the way
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    (Original post by AmateurBrainBox)
    What about the very last question, i think it was, on vectors where it was something like 'from your previous answer, what do we learn about the vector OS?' . I put something like OS is a multiple of OT therefore it is part of the vector OT.
    That they're parallel.
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    (Original post by 34908seikj)
    That they're parallel.
    lol no

    that point S also satisfies the vector OT (?) so it is the intersection of the two lines.
 
 
 
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