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    (Original post by scnotcrazy)
    bear we cannot chat no space again
    alles in ordnung now :yep:
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    (Original post by FamilyFirst)
    Question 2:

    If you were me and still had to teach S1, S2 and D1

    With the modules exams on the following dates:

    S1 - 15 June
    S2 - 27 June
    D1 - 17 June

    Would you give up? If not, how would you go about teaching them to yourself? Would every single textbook question waste too much time?
    there is still time... have you looked at www.mathsnetalevel.com ? it now offers all the uk and many foreign syllabi for: Full syllabus (i.e. option 1) single user £20 + vat. (Just 3 modules £10 + vat.)
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    (Original post by Fullofsurprises)
    UC, with its emphasis on superior bourgeois colleges and the undue credit placed on such middle class values as poetry, physics and knowing things, will be summarily terminated by a Corbyn government, as it will by the Tories under John Whittingdale, who mainly prefers programmes about prostitutes on pay-TV.
    Your starter for £10...
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    (Original post by the bear)
    there is still time... have you looked at www.mathsnetalevel.com ? it now offers all the uk and many foreign syllabi for: Full syllabus (i.e. option 1) single user £20 + vat. (Just 3 modules £10 + vat.)
    Nope, I may check it out and purchase it doe.

    Here is my failed proof.

    Prove by induction that:  2^n + 6^n is divisible by 8

    Fast forward...

     f_(_k_+_1_) - f_(_k_) = 2^k^+^1 + 6^k^+^1 - [2^k + 6^k]
     = 2(2^k) + 6(6^k) - 2^k - 6^k
     = 2^k + 5(6^k)
     = 8(2^k) - 7(2^k) + 8(6^k) - 3(6^k)
     = 8(2^k + 6^k) -7(2^k) - 3(6^k)
     = 8f(k) -7(2^k) - 3(6^k)

    Now I'm totally lost...
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    (Original post by FamilyFirst)
    Nope, I may check it out and purchase it doe.

    Here is my failed proof.

    Prove by induction that:  2^n + 6^n is divisible by 8

    Fast forward...

     f_(_k_+_1_) - f_(_k_) = 2^k^+^1 + 6^k^+^1 - [2^k + 6^k]
     = 2(2^k) + 6(6^k) - 2^k - 6^k
     = 2^k + 5(6^k)
     = 8(2^k) - 7(2^k) + 8(6^k) - 3(6^k)
     = 8(2^k + 6^k) -7(2^k) - 3(6^k)
     = 8f(k) -7(2^k) - 3(6^k)

    Now I'm totally lost...
    if you replace 6 with ( 8 - 2 ) at a certain stage it comes out neatly
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    (Original post by the bear)
    bring bear™ your problems

    :console:
    I'm struggling with exam revision and my first exam is in 3 weeks. HELP ME PLEASE
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    (Original post by Nuba123)
    I'm struggling with exam revision and my first exam is in 3 weeks. HELP ME PLEASE
    have you made yourself a revision timetable ? :holmes:
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    (Original post by the bear)
    have you made yourself a revision timetable ? :holmes:
    Yes but i can't focus and so i haven't been following it - i can never stick to it
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    (Original post by Nuba123)
    Yes but i can't focus and so i haven't been following it - i can never stick to it
    give yourself rewards/treats for sticking to the plan.
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    (Original post by the bear)
    if you replace 6 with ( 8 - 2 ) at a certain stage it comes out neatly
    Nope, not coming out... Well in my mind it isn't.

     2(2^k) + (8-2)(6^k) - 2^k - 6^k

    From here I'm lost tried many different things but she's not working out for me
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    (Original post by FamilyFirst)
    Nope, not coming out... Well in my mind it isn't.

     2(2^k) + (8-2)(6^k) - 2^k - 6^k

    From here I'm lost tried many different things but she's not working out for me
    nearly there !!! replace each 6^k with 8W - 2^k

    because the assumption is that 2^k + 6^k = a multiple of 8
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    (Original post by the bear)
    if you replace 6 with ( 8 - 2 ) at a certain stage it comes out neatly
    I think she's shy
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    (Original post by FamilyFirst)
    I think she's shy

    the thumbnail is fine

    bear™ has to go and do stuff in the so-called "real world" now ? :sad:

    laters dudes & dudettes

    :wavey:
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    Hey the bear, I need some advice about a couple of things and they are

    1 how to work clothes, shoes and Jewellery into a story,

    2 Remember a dream and replay it back so that I can write it down in a bit more detail and read it back whenever I want.

    3 to continue something from where I last left off
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    Yo bear can i help you instead?
 
 
 
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