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    Would I get a mark for calculating the midpoint for the last one, and putting the y bit equal to 0 and getting p?
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    I didnt see the simplification for finding the x value in 9)b) and just made my equation equal to the value given. I then used the x value given to find the y value. Would this still give me a mark?
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    (Original post by Arsey)
    Here are my solutions to the FP1 paper.

    Reasonable paper I thought, a few tricky bits
    how do I know your solutions are correct?
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    (Original post by mathsisjust)
    how do I know your solutions are correct?
    It is fairly easy for someone with experience to be sure of 100% or near 100% accuracy on papers of this level...also if something were incorrect someone would have noticed by now
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    (Original post by 13 1 20 8 42)
    It is fairly easy for someone with experience to be sure of 100% or near 100% accuracy on papers of this level...also if something were incorrect someone would have noticed by now
    I didn't know he was experienced
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    (Original post by Arsey)
    Here are my solutions to the FP1 paper.

    Reasonable paper I thought, a few tricky bits
    IAL FP1 solutions here


    http://www.thestudentroom.co.uk/show...3#post65033993
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    (Original post by Arsey)
    Here are my solutions to the FP1 paper.

    Reasonable paper I thought, a few tricky bits
    would you be able to predict grade boundaries for this paper?
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    (Original post by mathsisjust)
    Is Arsey a math's teacher??
    Arsy Is a very smart mathematician and therefore has a very high probability of getting all the answer correct. I tested this with a 1% Hypothesis testing.
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    (Original post by mathsnerd27)
    would you be able to predict grade boundaries for this paper?
    My Predictions:

    74- 100 UMS
    68 - 90 UMS (A* equiv)
    60 - 80 Ums (A)
    54 - 70 UMS (B)
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    (Original post by NoahMal)
    My Predictions:

    74- 100 UMS
    68 - 90 UMS (A* equiv)
    60 - 80 Ums (A)
    54 - 70 UMS (B)
    nah

    100 UMS - 75
    90 UMS - 70
    80 UMS - 62
    70 UMS - 56
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    (Original post by marinara pizza)
    nah

    100 UMS - 75
    90 UMS - 70
    80 UMS - 62
    70 UMS - 56
    The 90 UMS boundary must be equidistant from the 80 and 100 UMS boundaries
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    (Original post by NoahMal)
    Arsy Is a very smart mathematician and therefore has a very high probability of getting all the answer correct. I tested this with a 1% Hypothesis testing.
    lool
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    (Original post by olmomiau)
    The 90 UMS boundary must be equidistant from the 80 and 100 UMS boundaries
    if you insist:

    100 UMS = 75
    90 UMS = 70
    80 UMS = 65
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    (Original post by NoahMal)
    My Predictions:

    74- 100 UMS
    68 - 90 UMS (A* equiv)
    60 - 80 Ums (A)
    54 - 70 UMS (B)
    I second this
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    do u need to put sqrt 5 in 3 sf to get the one mark?????
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    I have posted solutions to the F1 paper, I thought it was a fair bit easier than UK FP1
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    (Original post by mathsisjust)
    how do I know your solutions are correct?
    I am Arsey
    • Thread Starter
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    (Original post by mathsnerd27)
    would you be able to predict grade boundaries for this paper?
    75 = 100ums
    69 = 91ums
    68 = 89ums
    62 for 80ums
    54 for 70ums

    would be my guess
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    (Original post by Arsey)
    75 = 100ums
    69 = 91ums
    68 = 89ums
    62 for 80ums
    54 for 70ums

    would be my guess
    For the first Proof question. I did the n=1 step and I worked out what need to be added (2k+3/(k+1)^2(k+2)^2 but I couldnt simplify it to the actual answer. How many marks would that be?
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    (Original post by 4nonymous)
    For the first Proof question. I did the n=1 step and I worked out what need to be added (2k+3/(k+1)^2(k+2)^2 but I couldnt simplify it to the actual answer. How many marks would that be?
    Usually 1 mark for proving true for n=1, 1 mark for assuming n=k. Sometimes they give a mark for an attempt to prove, sometimes they only give 3rd mark for successful n=k+1 proof. Other 2 marks are available for successful proof for n=k+1 AND conclusion, you will (most definitely) not get conclusion marks without proving for n=k+1.

    I'd say you probably have 2 or 3 marks out of 5.
 
 
 
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